Position Arithmetic

Position Arithmetic problems involve performing arithmetic operations (addition, subtraction, multiplication, division) on the position numbers of letters. The result may be a new number or a transformed letter. These problems test arithmetic skills applied to alphabet positions.

10Worksheets
200+Practice Questions
IntermediateDifficulty
2-3 hoursHours to Master

Introduction to Position Arithmetic

Position Arithmetic problems involve performing arithmetic operations (addition, subtraction, multiplication, division) on the position numbers of letters. The result may be a new number or a transformed letter. These problems test arithmetic skills applied to alphabet positions.

Prerequisites

Alphabet positions (A=1 to Z=26) Basic arithmetic operations (+, -, ×, ÷) Modulo 26 for wrap-around Order of operations
Why This Matters: Position Arithmetic problems appear in 1-2 questions in SSC CGL and Banking PO exams. They test arithmetic operations and pattern recognition.

How to Solve Position Arithmetic Problems

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Step 1: Convert each letter to its position number (A=1 to Z=26)

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Step 2: Apply the specified arithmetic operation to each position

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Step 3: For operations that produce numbers >26 or <1, apply modulo 26 (wrap-around)

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Step 4: Convert resulting numbers back to letters

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Step 5: For sum/product of positions in a word, calculate the total

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Step 6: Verify the operation is consistent for all letters

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Step 7: Present the coded word or number

Pro Strategy: Always handle wrap-around carefully. When a result is 0, it maps to Z (position 26). When result is negative, add 26 repeatedly until in 1-26 range. When result >26, subtract 26 until in 1-26 range.

Example Problem

Example 1: If each letter is coded as (position × 2), code 'BED'. Solution: Step 1: B=2, E=5, D=4 Step 2: B:2×2=4→D, E:5×2=10→J, D:4×2=8→H Step 3: Coded word = DJH Answer: DJH Example 2: If each letter is coded as (position - 3), code 'CAT'. Solution: C=3→0? 0 mod 26? Usually 0 maps to Z? Actually 3-3=0 → 26→Z, A=1-3=-2+26=24→X, T=20-3=17→Q → ZXQ Answer: ZXQ

Pro Tips & Tricks

  • Multiplication by 2: A(1)→B(2), B(2)→D(4), C(3)→F(6), M(13)→Z(26), N(14)→B(2) after wrap
  • Addition of constant: A(1)+3=D(4), B(2)+3=E(5)
  • Subtraction of constant: A(1)-1=Z(26), B(2)-1=A(1)
  • For position × 2, the result is always even (except wrap to odd)
  • For position × 3, wrap occurs at 9 (I), 17 (Q), 26 (Z)
  • The operations can be chained: ((pos + a) × b) mod 26

Shortcut Methods to Solve Faster

If result = 0 → Z (26)
If result = 27 → A (1) (since 27-26=1)
Modulo formula: final position = ((position - 1 + shift) mod 26) + 1 for addition
For multiplication: final position = ((position - 1) × multiplier) mod 26 + 1

Common Mistakes to Avoid

Forgetting wrap-around when result exceeds 26 or goes below 1
Mapping 0 to A instead of Z (common mistake)
Applying operations in wrong order for chained operations
Using division incorrectly (fractional results)

Exam Importance

Position Arithmetic is an important topic for various competitive exams. Here's how frequently it appears:

SSC CGL
1-2 questions
BANKING PO
1-2 questions
RAILWAYS RRB
1-2 questions
CAT
1-2 questions
INSURANCE
1-2 questions

Ready to Master Position Arithmetic?

Start with Worksheet 1 and work your way up to expert level! Each worksheet includes:

20 practice questions
Detailed solutions
Step-by-step explanations
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