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Position Arithmetic - Intermediate Level: tricky scenarios handling Position Arithmetic INTERMEDIATE

This expert challenge 📈 worksheet focuses on Position Arithmetic - a key topic in Coding Decoding. You'll solve 20 intermediate-level problems (Worksheet 5 of 10). The primary focus is on tricky scenarios handling. Master how to solve position arithmetic, position arithmetic tricks, and position arithmetic shortcut methods through systematic practice.

📝 Worksheet 5 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate level

What you'll learn in this worksheet:
Your progress through Position Arithmetic
Worksheet 5 of 10 (44% complete)

Question 1

If 'DECODE' is coded as 'GHFRGH' using the rule 'add 3 to each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'LEG' coded?
Each letter position +3: DECODE → GHFRGH

Question 2

If 'DIGITAL' is coded as 'EJHJUBM' using the rule 'add 1 to each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'ENCRYPT' coded?
Each letter position +1: DIGITAL → EJHJUBM

Question 3

If 'NOTE' is coded as 'JKPA' using the rule 'subtract 4 from each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'THETA' coded?
Each letter position -4: NOTE → JKPA

Question 4

If 'STREAM' is coded as 'WXVIEQ' using the rule 'add 4 to each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'DATA' coded?
Each letter position +4: STREAM → WXVIEQ

Question 5

If 'VALUE' is coded as 'YDOXH' using the rule 'add 3 to each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'TREE' coded?
Each letter position +3: VALUE → YDOXH

Question 6

If 'FINAL' is coded as 'LRBBX' using the rule 'multiply each letter's position by 2' (A=1, B=2, ..., Z=26, wrap around), then how is 'PROCESSOR' coded?
Each letter position ×2: FINAL → LRBBX

Question 7

If 'DISK' is coded as 'LAEG' using the rule 'multiply each letter's position by 3' (A=1, B=2, ..., Z=26, wrap around), then how is 'MYSTERY' coded?
Each letter position ×3: DISK → LAEG

Question 8

If 'DOG' is coded as 'HDN' using the rule 'multiply each letter's position by 2' (A=1, B=2, ..., Z=26, wrap around), then how is 'LID' coded?
Each letter position ×2: DOG → HDN

Question 9

If 'RUBY' is coded as 'JPDX' using the rule 'multiply each letter's position by 2' (A=1, B=2, ..., Z=26, wrap around), then how is 'CUBE' coded?
Each letter position ×2: RUBY → JPDX

Question 10

If 'FINAL' is coded as 'CFKXI' using the rule 'subtract 3 from each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'BINARY' coded?
Each letter position -3: FINAL → CFKXI

Question 11

If 'WEB' is coded as 'SAX' using the rule 'subtract 4 from each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'PATTERN' coded?
Each letter position -4: WEB → SAX

Question 12

If 'BINARY' is coded as '69' using the rule 'sum of the positions of all letters', then how is 'ROOT' coded?
Sum of positions: BINARY → 69

Question 13

If 'BINARY' is coded as '69' using the rule 'sum of the positions of all letters', then how is 'PROTOCOL' coded?
Sum of positions: BINARY → 69

Question 14

If 'EAR' is coded as 'JFW' using the rule 'add 5 to each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'MEMORY' coded?
Each letter position +5: EAR → JFW

Question 15

If 'FINAL' is coded as 'DGLYJ' using the rule 'subtract 2 from each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'BAG' coded?
Each letter position -2: FINAL → DGLYJ

Question 16

If 'HELLO' is coded as 'CZGGJ' using the rule 'subtract 5 from each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'BEE' coded?
Each letter position -5: HELLO → CZGGJ

Question 17

If 'PAGE' is coded as 'FBNJ' using the rule 'multiply each letter's position by 2' (A=1, B=2, ..., Z=26, wrap around), then how is 'GRASS' coded?
Each letter position ×2: PAGE → FBNJ

Question 18

If 'NETWORK' is coded as 'SJYBTWP' using the rule 'add 5 to each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'DATABASE' coded?
Each letter position +5: NETWORK → SJYBTWP

Question 19

If 'RUBY' is coded as 'PSZW' using the rule 'subtract 2 from each letter's position' (A=1, B=2, ..., Z=26, wrap around), then how is 'ALPHA' coded?
Each letter position -2: RUBY → PSZW

Question 20

If 'LIGHT' is coded as 'JAUXH' using the rule 'multiply each letter's position by 3' (A=1, B=2, ..., Z=26, wrap around), then how is 'PIG' coded?
Each letter position ×3: LIGHT → JAUXH
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