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Sum of n terms in AP - Intermediate Level: tricky scenarios handling Sum of n terms in AP INTERMEDIATE

This expert challenge 📈 worksheet focuses on Sum of n terms in AP - a key topic in Arithmetic Problems. You'll solve 20 intermediate-level problems (Worksheet 5 of 10). The primary focus is on tricky scenarios handling. Master how to solve sum of n terms in ap, sum of n terms in ap tricks, and sum of n terms in ap shortcut methods through systematic practice.

📝 Worksheet 5 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate level

What you'll learn in this worksheet:
Your progress through Sum of n terms in AP
Worksheet 5 of 10 (44% complete)

Question 1

Find the sum of first 7 terms of the AP: First term=12, common difference=4.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*12+(6)*4] = 168.0

Question 2

Find the sum of first 11 terms of the AP: First term=7, common difference=3.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*7+(10)*3] = 242.0

Question 3

Find the sum of first 15 terms of the AP: First term=5, common difference=8.
S_n = n/2 [2a + (n-1)d] = 15/2*[2*5+(14)*8] = 915.0

Question 4

Find the sum of first 11 terms of the AP: First term=2, common difference=6.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*2+(10)*6] = 352.0

Question 5

Find the sum of first 17 terms of the AP: First term=11, common difference=7.
S_n = n/2 [2a + (n-1)d] = 17/2*[2*11+(16)*7] = 1139.0

Question 6

Find the sum of first 10 terms of the AP: First term=3, common difference=7.
S_n = n/2 [2a + (n-1)d] = 10/2*[2*3+(9)*7] = 345.0

Question 7

Find the sum of first 14 terms of the AP: First term=4, common difference=3.
S_n = n/2 [2a + (n-1)d] = 14/2*[2*4+(13)*3] = 329.0

Question 8

Find the sum of first 20 terms of the AP: First term=11, common difference=6.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*11+(19)*6] = 1360.0

Question 9

Find the sum of first 12 terms of the AP: First term=12, common difference=3.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*12+(11)*3] = 342.0

Question 10

Find the sum of first 12 terms of the AP: First term=5, common difference=2.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*5+(11)*2] = 192.0

Question 11

Find the sum of first 7 terms of the AP: First term=5, common difference=2.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*5+(6)*2] = 77.0

Question 12

Find the sum of first 19 terms of the AP: First term=11, common difference=8.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*11+(18)*8] = 1577.0

Question 13

Find the sum of first 10 terms of the AP: First term=6, common difference=4.
S_n = n/2 [2a + (n-1)d] = 10/2*[2*6+(9)*4] = 240.0

Question 14

Find the sum of first 9 terms of the AP: First term=4, common difference=4.
S_n = n/2 [2a + (n-1)d] = 9/2*[2*4+(8)*4] = 180.0

Question 15

Find the sum of first 7 terms of the AP: First term=4, common difference=3.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*4+(6)*3] = 91.0

Question 16

Find the sum of first 10 terms of the AP: First term=11, common difference=5.
S_n = n/2 [2a + (n-1)d] = 10/2*[2*11+(9)*5] = 335.0

Question 17

Find the sum of first 15 terms of the AP: First term=8, common difference=2.
S_n = n/2 [2a + (n-1)d] = 15/2*[2*8+(14)*2] = 330.0

Question 18

Find the sum of first 13 terms of the AP: First term=2, common difference=6.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*2+(12)*6] = 494.0

Question 19

Find the sum of first 16 terms of the AP: First term=11, common difference=4.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*11+(15)*4] = 656.0

Question 20

Find the sum of first 11 terms of the AP: First term=8, common difference=6.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*8+(10)*6] = 418.0
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