Sum of n terms in AP: Worksheet 6 - Intermediate-Advanced Practice Sum of n terms in AP INTERMEDIATE ADVANCED

Ready to master Sum of n terms in AP? This timed practice ⚡ worksheet (6/10) presents 20 intermediate-advanced-level challenges. Focus area: speed building. Learn to solve sum of n terms in ap tricks, handle sum of n terms in ap shortcut methods, and perfect sum of n terms in ap bank exam questions with our step-by-step solutions.

📝 Worksheet 6 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate Advanced level

What you'll learn in this worksheet:
Your progress through Sum of n terms in AP
Worksheet 6 of 10 (55% complete)

Question 1

Find the sum of first 17 terms of the AP: First term=7, common difference=7.
S_n = n/2 [2a + (n-1)d] = 17/2*[2*7+(16)*7] = 1071.0

Question 2

Find the sum of first 17 terms of the AP: First term=12, common difference=3.
S_n = n/2 [2a + (n-1)d] = 17/2*[2*12+(16)*3] = 612.0

Question 3

Find the sum of first 14 terms of the AP: First term=9, common difference=7.
S_n = n/2 [2a + (n-1)d] = 14/2*[2*9+(13)*7] = 763.0

Question 4

Find the sum of first 15 terms of the AP: First term=5, common difference=7.
S_n = n/2 [2a + (n-1)d] = 15/2*[2*5+(14)*7] = 810.0

Question 5

Find the sum of first 7 terms of the AP: First term=5, common difference=4.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*5+(6)*4] = 119.0

Question 6

Find the sum of first 14 terms of the AP: First term=5, common difference=5.
S_n = n/2 [2a + (n-1)d] = 14/2*[2*5+(13)*5] = 525.0

Question 7

Find the sum of first 19 terms of the AP: First term=10, common difference=3.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*10+(18)*3] = 703.0

Question 8

Find the sum of first 12 terms of the AP: First term=4, common difference=8.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*4+(11)*8] = 576.0

Question 9

Find the sum of first 14 terms of the AP: First term=10, common difference=7.
S_n = n/2 [2a + (n-1)d] = 14/2*[2*10+(13)*7] = 777.0

Question 10

Find the sum of first 13 terms of the AP: First term=10, common difference=8.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*10+(12)*8] = 754.0

Question 11

Find the sum of first 11 terms of the AP: First term=5, common difference=6.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*5+(10)*6] = 385.0

Question 12

Find the sum of first 7 terms of the AP: First term=12, common difference=5.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*12+(6)*5] = 189.0

Question 13

Find the sum of first 14 terms of the AP: First term=8, common difference=2.
S_n = n/2 [2a + (n-1)d] = 14/2*[2*8+(13)*2] = 294.0

Question 14

Find the sum of first 13 terms of the AP: First term=10, common difference=4.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*10+(12)*4] = 442.0

Question 15

Find the sum of first 8 terms of the AP: First term=9, common difference=3.
S_n = n/2 [2a + (n-1)d] = 8/2*[2*9+(7)*3] = 156.0

Question 16

Find the sum of first 18 terms of the AP: First term=7, common difference=7.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*7+(17)*7] = 1197.0

Question 17

Find the sum of first 13 terms of the AP: First term=12, common difference=4.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*12+(12)*4] = 468.0

Question 18

Find the sum of first 8 terms of the AP: First term=7, common difference=5.
S_n = n/2 [2a + (n-1)d] = 8/2*[2*7+(7)*5] = 196.0

Question 19

Find the sum of first 18 terms of the AP: First term=6, common difference=8.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*6+(17)*8] = 1332.0

Question 20

Find the sum of first 11 terms of the AP: First term=10, common difference=2.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*10+(10)*2] = 220.0
Previous Worksheet Next Worksheet