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Sum of n terms in AP Beginner-Intermediate Worksheet: Focus on common variations practice Sum of n terms in AP BEGINNER INTERMEDIATE

Level up your Sum of n terms in AP skills! You're at Worksheet 4 of 10 (33% through this series). This step-up challenge worksheet features 20 beginner-intermediate-level problems with a focus on common variations practice. Topics covered: sum of n terms in ap for competitive exams, how to solve sum of n terms in ap, sum of n terms in ap tricks.

📝 Worksheet 4 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner Intermediate level

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Worksheet 4 of 10 (33% complete)

Question 1

Find the sum of first 9 terms of the AP: First term=3, common difference=4.
S_n = n/2 [2a + (n-1)d] = 9/2*[2*3+(8)*4] = 171.0

Question 2

Find the sum of first 20 terms of the AP: First term=7, common difference=2.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*7+(19)*2] = 520.0

Question 3

Find the sum of first 9 terms of the AP: First term=12, common difference=4.
S_n = n/2 [2a + (n-1)d] = 9/2*[2*12+(8)*4] = 252.0

Question 4

Find the sum of first 17 terms of the AP: First term=8, common difference=4.
S_n = n/2 [2a + (n-1)d] = 17/2*[2*8+(16)*4] = 680.0

Question 5

Find the sum of first 12 terms of the AP: First term=5, common difference=5.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*5+(11)*5] = 390.0

Question 6

Find the sum of first 20 terms of the AP: First term=5, common difference=6.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*5+(19)*6] = 1240.0

Question 7

Find the sum of first 17 terms of the AP: First term=3, common difference=3.
S_n = n/2 [2a + (n-1)d] = 17/2*[2*3+(16)*3] = 459.0

Question 8

Find the sum of first 19 terms of the AP: First term=12, common difference=5.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*12+(18)*5] = 1083.0

Question 9

Find the sum of first 7 terms of the AP: First term=6, common difference=8.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*6+(6)*8] = 210.0

Question 10

Find the sum of first 15 terms of the AP: First term=9, common difference=7.
S_n = n/2 [2a + (n-1)d] = 15/2*[2*9+(14)*7] = 870.0

Question 11

Find the sum of first 11 terms of the AP: First term=10, common difference=4.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*10+(10)*4] = 330.0

Question 12

Find the sum of first 9 terms of the AP: First term=9, common difference=6.
S_n = n/2 [2a + (n-1)d] = 9/2*[2*9+(8)*6] = 297.0

Question 13

Find the sum of first 8 terms of the AP: First term=9, common difference=4.
S_n = n/2 [2a + (n-1)d] = 8/2*[2*9+(7)*4] = 184.0

Question 14

Find the sum of first 7 terms of the AP: First term=9, common difference=4.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*9+(6)*4] = 147.0

Question 15

Find the sum of first 19 terms of the AP: First term=5, common difference=8.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*5+(18)*8] = 1463.0

Question 16

Find the sum of first 11 terms of the AP: First term=7, common difference=6.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*7+(10)*6] = 407.0

Question 17

Find the sum of first 12 terms of the AP: First term=7, common difference=7.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*7+(11)*7] = 546.0

Question 18

Find the sum of first 19 terms of the AP: First term=11, common difference=7.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*11+(18)*7] = 1406.0

Question 19

Find the sum of first 16 terms of the AP: First term=4, common difference=4.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*4+(15)*4] = 544.0

Question 20

Find the sum of first 16 terms of the AP: First term=11, common difference=3.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*11+(15)*3] = 536.0
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