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Min/Max Age Constraints - Intermediate Level: tricky scenarios handling Min/Max Age Constraints INTERMEDIATE

This expert challenge 📈 worksheet focuses on Min/Max Age Constraints - a key topic in Age Problems. You'll solve 20 intermediate-level problems (Worksheet 5 of 10). The primary focus is on tricky scenarios handling. Master how to solve min/max age constraints, min/max age constraints tricks, and min/max age constraints shortcut methods through systematic practice.

📝 Worksheet 5 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate level

What you'll learn in this worksheet:
Your progress through Min/Max Age Constraints
Worksheet 5 of 10 (44% complete)

Question 1

A is older than B. C is younger than B. A + B + C = 66. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 66, max C = 19

Question 2

A is older than B. C is younger than B. A + B + C = 70. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 70, max C = 19

Question 3

A is older than B. C is younger than B. A + B + C = 72. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 72, max C = 19

Question 4

A and B's ages sum to 58. A is between 5 and 2 times as old as B. What is the minimum possible age of A?
A + B = 58, A/B between 5 and 2. For min A, take A/B = 5 → B = 9.7, A = 48.3 → min A = 49

Question 5

Sum of A and B's ages is 52. After 6 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 52, (A+6) = 3*(B+6) → A = 42.0 → max A = 42

Question 6

A is older than B. C is younger than B. A + B + C = 78. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 78, max C = 23

Question 7

A is older than B. C is younger than B. A + B + C = 78. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 78, max C = 19

Question 8

Sum of A and B's ages is 61. After 6 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 61, (A+6) = 3*(B+6) → A = 48.8 → max A = 48

Question 9

Sum of A and B's ages is 55. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 55, (A+10) = 3*(B+10) → A = 46.2 → max A = 46

Question 10

Sum of A and B's ages is 58. After 8 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 58, (A+8) = 3*(B+8) → A = 47.5 → max A = 47

Question 11

A and B's ages sum to 56. A is between 4 and 5 times as old as B. What is the minimum possible age of A?
A + B = 56, A/B between 4 and 5. For min A, take A/B = 4 → B = 11.2, A = 44.8 → min A = 45

Question 12

Sum of A and B's ages is 69. After 6 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 69, (A+6) = 2*(B+6) → A = 48.0 → max A = 48

Question 13

A is older than B. C is younger than B. A + B + C = 62. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 62, max C = 18

Question 14

Sum of A and B's ages is 61. After 9 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 61, (A+9) = 2*(B+9) → A = 43.7 → max A = 43

Question 15

A and B's ages sum to 50. A is between 3 and 5 times as old as B. What is the minimum possible age of A?
A + B = 50, A/B between 3 and 5. For min A, take A/B = 3 → B = 12.5, A = 37.5 → min A = 38

Question 16

A is older than B. C is younger than B. A + B + C = 66. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 66, max C = 19

Question 17

Sum of A and B's ages is 66. After 9 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 66, (A+9) = 2*(B+9) → A = 47.0 → max A = 47

Question 18

A is older than B. C is younger than B. A + B + C = 70. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 70, max C = 21

Question 19

A and B's ages sum to 45. A is between 2 and 4 times as old as B. What is the minimum possible age of A?
A + B = 45, A/B between 2 and 4. For min A, take A/B = 2 → B = 15.0, A = 30.0 → min A = 30

Question 20

A is older than B. C is younger than B. A + B + C = 71. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 71, max C = 21
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