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Min/Max Age Constraints Beginner-Intermediate Worksheet: Focus on common variations practice Min/Max Age Constraints BEGINNER INTERMEDIATE

Level up your Min/Max Age Constraints skills! You're at Worksheet 4 of 10 (33% through this series). This step-up challenge worksheet features 20 beginner-intermediate-level problems with a focus on common variations practice. Topics covered: min/max age constraints for competitive exams, how to solve min/max age constraints, min/max age constraints tricks.

📝 Worksheet 4 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner Intermediate level

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Worksheet 4 of 10 (33% complete)

Question 1

A is older than B. C is younger than B. A + B + C = 62. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 62, max C = 17

Question 2

A and B's ages sum to 48. A is between 3 and 4 times as old as B. What is the minimum possible age of A?
A + B = 48, A/B between 3 and 4. For min A, take A/B = 3 → B = 12.0, A = 36.0 → min A = 36

Question 3

Sum of A and B's ages is 52. After 8 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 52, (A+8) = 2*(B+8) → A = 37.3 → max A = 37

Question 4

Sum of A and B's ages is 59. After 9 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 59, (A+9) = 2*(B+9) → A = 42.3 → max A = 42

Question 5

Sum of A and B's ages is 61. After 6 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 61, (A+6) = 3*(B+6) → A = 48.8 → max A = 48

Question 6

Sum of A and B's ages is 50. After 5 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 50, (A+5) = 2*(B+5) → A = 35.0 → max A = 35

Question 7

A is older than B. C is younger than B. A + B + C = 68. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 68, max C = 19

Question 8

A and B's ages sum to 58. A is between 3 and 4 times as old as B. What is the minimum possible age of A?
A + B = 58, A/B between 3 and 4. For min A, take A/B = 3 → B = 14.5, A = 43.5 → min A = 44

Question 9

Sum of A and B's ages is 68. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 68, (A+10) = 3*(B+10) → A = 56.0 → max A = 56

Question 10

Sum of A and B's ages is 67. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 67, (A+10) = 3*(B+10) → A = 55.2 → max A = 55

Question 11

Sum of A and B's ages is 63. After 7 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 63, (A+7) = 2*(B+7) → A = 44.3 → max A = 44

Question 12

Sum of A and B's ages is 56. After 5 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 56, (A+5) = 3*(B+5) → A = 44.5 → max A = 44

Question 13

A and B's ages sum to 52. A is between 3 and 4 times as old as B. What is the minimum possible age of A?
A + B = 52, A/B between 3 and 4. For min A, take A/B = 3 → B = 13.0, A = 39.0 → min A = 39

Question 14

A and B's ages sum to 59. A is between 2 and 5 times as old as B. What is the minimum possible age of A?
A + B = 59, A/B between 2 and 5. For min A, take A/B = 2 → B = 19.7, A = 39.3 → min A = 40

Question 15

Sum of A and B's ages is 59. After 7 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 59, (A+7) = 3*(B+7) → A = 47.8 → max A = 47

Question 16

Sum of A and B's ages is 59. After 8 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 59, (A+8) = 2*(B+8) → A = 42.0 → max A = 42

Question 17

A and B's ages sum to 54. A is between 5 and 4 times as old as B. What is the minimum possible age of A?
A + B = 54, A/B between 5 and 4. For min A, take A/B = 5 → B = 9.0, A = 45.0 → min A = 45

Question 18

A is older than B. C is younger than B. A + B + C = 71. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 71, max C = 16

Question 19

A and B's ages sum to 52. A is between 3 and 2 times as old as B. What is the minimum possible age of A?
A + B = 52, A/B between 3 and 2. For min A, take A/B = 3 → B = 13.0, A = 39.0 → min A = 39

Question 20

A is older than B. C is younger than B. A + B + C = 68. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 68, max C = 19
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