Master Min/Max Age Constraints - Beginner Level Problems Min/Max Age Constraints BEGINNER

Excel in competitive exams with this skill builder ⚡ worksheet on Min/Max Age Constraints. Worksheet 3 of 10 contains 20 beginner-level problems. Target your step-by-step problem solving skills while practicing min/max age constraints practice, min/max age constraints for competitive exams, and how to solve min/max age constraints.

📝 Worksheet 3 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner level

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Worksheet 3 of 10 (22% complete)

Question 1

A is older than B. C is younger than B. A + B + C = 59. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 59, max C = 15

Question 2

A is older than B. C is younger than B. A + B + C = 71. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 71, max C = 16

Question 3

Sum of A and B's ages is 53. After 8 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 53, (A+8) = 2*(B+8) → A = 38.0 → max A = 38

Question 4

A and B's ages sum to 57. A is between 4 and 5 times as old as B. What is the minimum possible age of A?
A + B = 57, A/B between 4 and 5. For min A, take A/B = 4 → B = 11.4, A = 45.6 → min A = 46

Question 5

A is older than B. C is younger than B. A + B + C = 80. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 80, max C = 21

Question 6

A and B's ages sum to 54. A is between 4 and 2 times as old as B. What is the minimum possible age of A?
A + B = 54, A/B between 4 and 2. For min A, take A/B = 4 → B = 10.8, A = 43.2 → min A = 44

Question 7

A and B's ages sum to 40. A is between 2 and 3 times as old as B. What is the minimum possible age of A?
A + B = 40, A/B between 2 and 3. For min A, take A/B = 2 → B = 13.3, A = 26.7 → min A = 27

Question 8

Sum of A and B's ages is 70. After 7 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 70, (A+7) = 3*(B+7) → A = 56.0 → max A = 56

Question 9

A is older than B. C is younger than B. A + B + C = 60. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 60, max C = 15

Question 10

A is older than B. C is younger than B. A + B + C = 63. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 63, max C = 16

Question 11

A and B's ages sum to 57. A is between 2 and 4 times as old as B. What is the minimum possible age of A?
A + B = 57, A/B between 2 and 4. For min A, take A/B = 2 → B = 19.0, A = 38.0 → min A = 38

Question 12

A and B's ages sum to 55. A is between 5 and 2 times as old as B. What is the minimum possible age of A?
A + B = 55, A/B between 5 and 2. For min A, take A/B = 5 → B = 9.2, A = 45.8 → min A = 46

Question 13

A is older than B. C is younger than B. A + B + C = 72. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 72, max C = 17

Question 14

A is older than B. C is younger than B. A + B + C = 77. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 77, max C = 20

Question 15

Sum of A and B's ages is 66. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 66, (A+10) = 3*(B+10) → A = 54.5 → max A = 54

Question 16

A is older than B. C is younger than B. A + B + C = 64. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 64, max C = 19

Question 17

A is older than B. C is younger than B. A + B + C = 74. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 74, max C = 19

Question 18

A is older than B. C is younger than B. A + B + C = 70. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 70, max C = 19

Question 19

A and B's ages sum to 57. A is between 3 and 5 times as old as B. What is the minimum possible age of A?
A + B = 57, A/B between 3 and 5. For min A, take A/B = 3 → B = 14.2, A = 42.8 → min A = 43

Question 20

A is older than B. C is younger than B. A + B + C = 78. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 78, max C = 17
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