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Min/Max Age Constraints: Worksheet 6 - Intermediate-Advanced Practice Min/Max Age Constraints INTERMEDIATE ADVANCED

Ready to master Min/Max Age Constraints? This timed practice ⚡ worksheet (6/10) presents 20 intermediate-advanced-level challenges. Focus area: speed building. Learn to solve min/max age constraints tricks, handle min/max age constraints shortcut methods, and perfect min/max age constraints bank exam questions with our step-by-step solutions.

📝 Worksheet 6 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate Advanced level

What you'll learn in this worksheet:
Your progress through Min/Max Age Constraints
Worksheet 6 of 10 (55% complete)

Question 1

A is older than B. C is younger than B. A + B + C = 75. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 75, max C = 20

Question 2

Sum of A and B's ages is 53. After 6 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 53, (A+6) = 3*(B+6) → A = 42.8 → max A = 42

Question 3

A and B's ages sum to 43. A is between 4 and 2 times as old as B. What is the minimum possible age of A?
A + B = 43, A/B between 4 and 2. For min A, take A/B = 4 → B = 8.6, A = 34.4 → min A = 35

Question 4

A is older than B. C is younger than B. A + B + C = 66. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 66, max C = 17

Question 5

A and B's ages sum to 43. A is between 3 and 5 times as old as B. What is the minimum possible age of A?
A + B = 43, A/B between 3 and 5. For min A, take A/B = 3 → B = 10.8, A = 32.2 → min A = 33

Question 6

A is older than B. C is younger than B. A + B + C = 83. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 83, max C = 20

Question 7

Sum of A and B's ages is 55. After 7 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 55, (A+7) = 2*(B+7) → A = 39.0 → max A = 39

Question 8

A is older than B. C is younger than B. A + B + C = 79. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 79, max C = 20

Question 9

Sum of A and B's ages is 61. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 61, (A+10) = 3*(B+10) → A = 50.8 → max A = 50

Question 10

Sum of A and B's ages is 60. After 10 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 60, (A+10) = 2*(B+10) → A = 43.3 → max A = 43

Question 11

A is older than B. C is younger than B. A + B + C = 80. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 80, max C = 21

Question 12

A is older than B. C is younger than B. A + B + C = 56. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 56, max C = 14

Question 13

A and B's ages sum to 48. A is between 4 and 2 times as old as B. What is the minimum possible age of A?
A + B = 48, A/B between 4 and 2. For min A, take A/B = 4 → B = 9.6, A = 38.4 → min A = 39

Question 14

Sum of A and B's ages is 63. After 8 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 63, (A+8) = 2*(B+8) → A = 44.7 → max A = 44

Question 15

A is older than B. C is younger than B. A + B + C = 63. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 63, max C = 16

Question 16

Sum of A and B's ages is 51. After 9 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 51, (A+9) = 3*(B+9) → A = 42.8 → max A = 42

Question 17

A is older than B. C is younger than B. A + B + C = 64. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 64, max C = 15

Question 18

Sum of A and B's ages is 53. After 6 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 53, (A+6) = 2*(B+6) → A = 37.3 → max A = 37

Question 19

Sum of A and B's ages is 69. After 10 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 69, (A+10) = 2*(B+10) → A = 49.3 → max A = 49

Question 20

A and B's ages sum to 55. A is between 4 and 2 times as old as B. What is the minimum possible age of A?
A + B = 55, A/B between 4 and 2. For min A, take A/B = 4 → B = 11.0, A = 44.0 → min A = 44
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