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Product of Ages - Expert Level: conceptual clarity Product of Ages EXPERT

This skill evaluation ⚡ worksheet focuses on Product of Ages - a key topic in Age Based Puzzles. You'll solve 20 expert-level problems (Worksheet 9 of 10). The primary focus is on conceptual clarity. Master product of ages ssc cgl, product of ages reasoning tricks, and fast product of ages solving through systematic practice.

📝 Worksheet 9 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Expert level

What you'll learn in this worksheet:
Your progress through Product of Ages
Worksheet 9 of 10 (88% complete)

Question 1

The product of the ages of Grace, Amrita, and Sadie is 900. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 900 ÷ (x × 3x) = 900 ÷ (3x²)
Testing x = 5: middle = 900 ÷ (3 × 5²) = 12
Therefore, eldest = 15

Question 2

The product of the ages of Rishi, Evelyn, and Om is 1911. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1911 ÷ (x × 3x) = 1911 ÷ (3x²)
Testing x = 7: middle = 1911 ÷ (3 × 7²) = 13
Therefore, eldest = 21

Question 3

The product of the ages of Ezra, Saachi, and Kritika is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 8: middle = 2400 ÷ (2 × 8²) = 15
Therefore, eldest = 20

Question 4

The product of the ages of Arthur, Rajiv, and Elliott is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 5

The product of the ages of Hina, Sarah, and Archana is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 6

The product of the ages of Rishi, Isabella, and Bina is 288. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 288 ÷ (x × 3x) = 288 ÷ (3x²)
Testing x = 4: middle = 288 ÷ (3 × 4²) = 6
Therefore, eldest = 12

Question 7

The product of the ages of Kamal, Bryson, and Sameer is 288. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 288 ÷ (x × 3x) = 288 ÷ (3x²)
Testing x = 4: middle = 288 ÷ (3 × 4²) = 6
Therefore, eldest = 12

Question 8

The product of the ages of Prasanna, Nira, and Navin is 900. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 900 ÷ (x × 3x) = 900 ÷ (3x²)
Testing x = 5: middle = 900 ÷ (3 × 5²) = 12
Therefore, eldest = 15

Question 9

The product of the ages of Kaushal, Marco, and Prithvi is 900. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 900 ÷ (x × 3x) = 900 ÷ (3x²)
Testing x = 5: middle = 900 ÷ (3 × 5²) = 12
Therefore, eldest = 15

Question 10

The product of the ages of Vedika, Rylee, and Josephine is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 11

The product of the ages of Sandeep, Urvashi, and Jyoti is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 12

The product of the ages of Everly, Alexa, and Xena is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 13

The product of the ages of Levi, Saurabh, and Wyatt is 1764. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1764 ÷ (x × 3x) = 1764 ÷ (3x²)
Testing x = 7: middle = 1764 ÷ (3 × 7²) = 12
Therefore, eldest = 21

Question 14

The product of the ages of Rylee, Sarah, and Narendra is 1911. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1911 ÷ (x × 3x) = 1911 ÷ (3x²)
Testing x = 7: middle = 1911 ÷ (3 × 7²) = 13
Therefore, eldest = 21

Question 15

The product of the ages of Lakhvinder, Mia, and Uday is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 16

The product of the ages of Vivek, Charu, and Chandan is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 17

The product of the ages of Geeta, Revathi, and Kiran is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 18

The product of the ages of Jai, Ian, and Vivek is 490. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 490 ÷ (x × 2x) = 490 ÷ (2x²)
Testing x = 5: middle = 490 ÷ (2 × 5²) = 7
Therefore, eldest = 14

Question 19

The product of the ages of Niyati, Valentina, and Noah is 1188. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1188 ÷ (x × 3x) = 1188 ÷ (3x²)
Testing x = 6: middle = 1188 ÷ (3 × 6²) = 11
Therefore, eldest = 18

Question 20

The product of the ages of Tanu, Bennett, and Colton is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20
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