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Product of Ages Advanced Worksheet: Focus on exam-oriented approach Product of Ages ADVANCED

Level up your Product of Ages skills! You're at Worksheet 8 of 10 (77% through this series). This exam hall simulation worksheet features 20 advanced-level problems with a focus on exam-oriented approach. Topics covered: product of ages bank exam questions, product of ages ssc cgl, product of ages reasoning tricks.

📝 Worksheet 8 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Advanced level

What you'll learn in this worksheet:
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Worksheet 8 of 10 (77% complete)

Question 1

The product of the ages of Hannah, Yashaswi, and Akash is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14

Question 2

The product of the ages of Ramesh, Ranveer, and Amit is 2646. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2646 ÷ (x × 2x) = 2646 ÷ (2x²)
Testing x = 9: middle = 2646 ÷ (2 × 9²) = 14
Therefore, eldest = 21

Question 3

The product of the ages of Jordan, Ankur, and Revathi is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 4

The product of the ages of Vijay, Anna, and Sophie is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15

Question 5

The product of the ages of Purvi, Connor, and Ankit is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 6

The product of the ages of Zoe, Dilip, and Raj is 640. The eldest is 4 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 4x
Then middle = 640 ÷ (x × 4x) = 640 ÷ (4x²)
Testing x = 4: middle = 640 ÷ (4 × 4²) = 10
Therefore, eldest = 16

Question 7

The product of the ages of Benjamin, Hitesh, and Leo is 400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 400 ÷ (x × 2x) = 400 ÷ (2x²)
Testing x = 5: middle = 400 ÷ (2 × 5²) = 8
Therefore, eldest = 10

Question 8

The product of the ages of Tyler, Kaveri, and Nikita is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20

Question 9

The product of the ages of Siddharth, Peter, and Victor is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 10

The product of the ages of Shalini, Vrijesh, and Vipul is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 11

The product of the ages of Penelope, Leah, and Ashwin is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 12

The product of the ages of Kayden, Hemant, and Hailey is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 13

The product of the ages of Sarita, Krishna, and Ines is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 14

The product of the ages of Suraj, Violet, and Marcus is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 15

The product of the ages of Gunjan, Nolan, and Rajesh is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 16

The product of the ages of Prashant, Kiran, and Ritu is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 17

The product of the ages of Indira, Rajiv, and Milo is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20

Question 18

The product of the ages of Jatin, Dominic, and Rajiv is 1911. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1911 ÷ (x × 3x) = 1911 ÷ (3x²)
Testing x = 7: middle = 1911 ÷ (3 × 7²) = 13
Therefore, eldest = 21

Question 19

The product of the ages of Finn, Deepa, and Evan is 640. The eldest is 4 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 4x
Then middle = 640 ÷ (x × 4x) = 640 ÷ (4x²)
Testing x = 4: middle = 640 ÷ (4 × 4²) = 10
Therefore, eldest = 16

Question 20

The product of the ages of Ezra, Piya, and Anjali is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16
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