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Master Product of Ages - Intermediate-Advanced Level Problems Product of Ages INTERMEDIATE ADVANCED

Excel in competitive exams with this self assessment worksheet on Product of Ages. Worksheet 7 of 10 contains 20 intermediate-advanced-level problems. Target your accuracy improvement skills while practicing product of ages shortcut methods, product of ages bank exam questions, and product of ages ssc cgl.

📝 Worksheet 7 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate Advanced level

What you'll learn in this worksheet:
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Worksheet 7 of 10 (66% complete)

Question 1

The product of the ages of Manpreet, Isabella, and Arianna is 1188. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1188 ÷ (x × 3x) = 1188 ÷ (3x²)
Testing x = 6: middle = 1188 ÷ (3 × 6²) = 11
Therefore, eldest = 18

Question 2

The product of the ages of Liam, Savita, and Suresh is 1911. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1911 ÷ (x × 3x) = 1911 ÷ (3x²)
Testing x = 7: middle = 1911 ÷ (3 × 7²) = 13
Therefore, eldest = 21

Question 3

The product of the ages of Sushant, Arun, and Sarabjit is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 4

The product of the ages of Alexa, Vikram, and Ashish is 1188. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1188 ÷ (x × 3x) = 1188 ÷ (3x²)
Testing x = 6: middle = 1188 ÷ (3 × 6²) = 11
Therefore, eldest = 18

Question 5

The product of the ages of Manjari, Beatrice, and Megha is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 6

The product of the ages of Xena, Scarlett, and Louis is 162. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 162 ÷ (x × 3x) = 162 ÷ (3x²)
Testing x = 3: middle = 162 ÷ (3 × 3²) = 6
Therefore, eldest = 9

Question 7

The product of the ages of Ivan, Pooja, and Archana is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 8

The product of the ages of Elias, Amrita, and Emmett is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20

Question 9

The product of the ages of Mahak, Kaylee, and Sloane is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 8: middle = 2400 ÷ (2 × 8²) = 15
Therefore, eldest = 20

Question 10

The product of the ages of Surya, Hugo, and Om is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 11

The product of the ages of Mahak, Nira, and Seema is 490. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 490 ÷ (x × 2x) = 490 ÷ (2x²)
Testing x = 5: middle = 490 ÷ (2 × 5²) = 7
Therefore, eldest = 14

Question 12

The product of the ages of Nova, Pooja, and Sunil is 1764. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1764 ÷ (x × 3x) = 1764 ÷ (3x²)
Testing x = 7: middle = 1764 ÷ (3 × 7²) = 12
Therefore, eldest = 21

Question 13

The product of the ages of Radhika, Luke, and Ariana is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 14

The product of the ages of Kunal, Jivika, and Subhash is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 15

The product of the ages of Allison, Silas, and Henry is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 16

The product of the ages of Ishan, Sourav, and Jasper is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15

Question 17

The product of the ages of Utkarsh, Adeline, and Maya is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14

Question 18

The product of the ages of Sandeep, Evelyn, and Sanjana is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 19

The product of the ages of Prasanna, Radha, and Christopher is 400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 400 ÷ (x × 2x) = 400 ÷ (2x²)
Testing x = 5: middle = 400 ÷ (2 × 5²) = 8
Therefore, eldest = 10

Question 20

The product of the ages of Chandan, Hudson, and Deepa is 400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 400 ÷ (x × 2x) = 400 ÷ (2x²)
Testing x = 5: middle = 400 ÷ (2 × 5²) = 8
Therefore, eldest = 10
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