Product of Ages: Worksheet 6 - Intermediate-Advanced Practice Product of Ages INTERMEDIATE ADVANCED

Ready to master Product of Ages? This timed practice ⚡ worksheet (6/10) presents 20 intermediate-advanced-level challenges. Focus area: speed building. Learn to solve product of ages tricks, handle product of ages shortcut methods, and perfect product of ages bank exam questions with our step-by-step solutions.

📝 Worksheet 6 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate Advanced level

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Worksheet 6 of 10 (55% complete)

Question 1

The product of the ages of Puneet, Vasant, and Sophie is 640. The eldest is 4 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 4x
Then middle = 640 ÷ (x × 4x) = 640 ÷ (4x²)
Testing x = 4: middle = 640 ÷ (4 × 4²) = 10
Therefore, eldest = 16

Question 2

The product of the ages of Layla, Omar, and Mansi is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 3

The product of the ages of Vidya, Yash, and Yashaswi is 1911. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1911 ÷ (x × 3x) = 1911 ÷ (3x²)
Testing x = 7: middle = 1911 ÷ (3 × 7²) = 13
Therefore, eldest = 21

Question 4

The product of the ages of Shashi, Addison, and Aria is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 5

The product of the ages of William, Alice, and Kumud is 1764. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1764 ÷ (x × 3x) = 1764 ÷ (3x²)
Testing x = 7: middle = 1764 ÷ (3 × 7²) = 12
Therefore, eldest = 21

Question 6

The product of the ages of Janvi, Shashi, and Freya is 162. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 162 ÷ (x × 3x) = 162 ÷ (3x²)
Testing x = 3: middle = 162 ÷ (3 × 3²) = 6
Therefore, eldest = 9

Question 7

The product of the ages of Matteo, Sarika, and Harsh is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 8

The product of the ages of Ajay, Subhash, and Theo is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 9

The product of the ages of David, Lata, and Elizabeth is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 10

The product of the ages of Isla, Saloni, and Ankur is 490. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 490 ÷ (x × 2x) = 490 ÷ (2x²)
Testing x = 5: middle = 490 ÷ (2 × 5²) = 7
Therefore, eldest = 14

Question 11

The product of the ages of Sohan, Colton, and Parul is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 12

The product of the ages of Veena, Lucas, and Colton is 810. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 810 ÷ (x × 2x) = 810 ÷ (2x²)
Testing x = 6: middle = 810 ÷ (2 × 6²) = 9
Therefore, eldest = 15

Question 13

The product of the ages of Naman, Sarvesh, and Kush is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15

Question 14

The product of the ages of Vidya, Sophie, and Lillian is 900. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 900 ÷ (x × 3x) = 900 ÷ (3x²)
Testing x = 5: middle = 900 ÷ (3 × 5²) = 12
Therefore, eldest = 15

Question 15

The product of the ages of Pooja, Audrey, and Shree is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14

Question 16

The product of the ages of Tristan, Rakhi, and Max is 490. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 490 ÷ (x × 2x) = 490 ÷ (2x²)
Testing x = 5: middle = 490 ÷ (2 × 5²) = 7
Therefore, eldest = 14

Question 17

The product of the ages of Rakshit, Patrick, and Ratna is 2646. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2646 ÷ (x × 2x) = 2646 ÷ (2x²)
Testing x = 9: middle = 2646 ÷ (2 × 9²) = 14
Therefore, eldest = 21

Question 18

The product of the ages of Sushma, Mohan, and Abigail is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 19

The product of the ages of Shakti, Aparna, and Cora is 1080. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1080 ÷ (x × 3x) = 1080 ÷ (3x²)
Testing x = 6: middle = 1080 ÷ (3 × 6²) = 10
Therefore, eldest = 18

Question 20

The product of the ages of Saloni, Sujata, and Zoe is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15
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