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Product of Ages - Intermediate Level: tricky scenarios handling Product of Ages INTERMEDIATE

This expert challenge 📈 worksheet focuses on Product of Ages - a key topic in Age Based Puzzles. You'll solve 20 intermediate-level problems (Worksheet 5 of 10). The primary focus is on tricky scenarios handling. Master how to solve product of ages, product of ages tricks, and product of ages shortcut methods through systematic practice.

📝 Worksheet 5 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate level

What you'll learn in this worksheet:
Your progress through Product of Ages
Worksheet 5 of 10 (44% complete)

Question 1

The product of the ages of Hemant, Leon, and Elena is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 2

The product of the ages of Shweta, Krishna, and Benjamin is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 3

The product of the ages of Maya, Adeline, and Addison is 400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 400 ÷ (x × 2x) = 400 ÷ (2x²)
Testing x = 5: middle = 400 ÷ (2 × 5²) = 8
Therefore, eldest = 10

Question 4

The product of the ages of Dev, Everett, and Sumit is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 5

The product of the ages of Siddharth, Charles, and Pravin is 1911. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1911 ÷ (x × 3x) = 1911 ÷ (3x²)
Testing x = 7: middle = 1911 ÷ (3 × 7²) = 13
Therefore, eldest = 21

Question 6

The product of the ages of Santosh, Shravan, and Nova is 810. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 810 ÷ (x × 2x) = 810 ÷ (2x²)
Testing x = 6: middle = 810 ÷ (2 × 6²) = 9
Therefore, eldest = 15

Question 7

The product of the ages of Lily, Vidya, and Isabella is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14

Question 8

The product of the ages of Disha, Raul, and Jivika is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 9

The product of the ages of Rajesh, Austin, and Rani is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 10

The product of the ages of Darpan, Chetan, and Eva is 490. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 490 ÷ (x × 2x) = 490 ÷ (2x²)
Testing x = 5: middle = 490 ÷ (2 × 5²) = 7
Therefore, eldest = 14

Question 11

The product of the ages of Waylon, Tushar, and Tristan is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 12

The product of the ages of Abhay, Satish, and Mamta is 640. The eldest is 4 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 4x
Then middle = 640 ÷ (x × 4x) = 640 ÷ (4x²)
Testing x = 4: middle = 640 ÷ (4 × 4²) = 10
Therefore, eldest = 16

Question 13

The product of the ages of Joseph, Nimesh, and Nevaeh is 640. The eldest is 4 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 4x
Then middle = 640 ÷ (x × 4x) = 640 ÷ (4x²)
Testing x = 4: middle = 640 ÷ (4 × 4²) = 10
Therefore, eldest = 16

Question 14

The product of the ages of Max, Shakti, and Brooklyn is 810. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 810 ÷ (x × 2x) = 810 ÷ (2x²)
Testing x = 6: middle = 810 ÷ (2 × 6²) = 9
Therefore, eldest = 15

Question 15

The product of the ages of Gael, Bhuvnesh, and Jackson is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 16

The product of the ages of Utkarsh, Shankar, and Tarun is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14

Question 17

The product of the ages of Dominic, Prateek, and Ishan is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 18

The product of the ages of Sakshi, Anmol, and Christian is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20

Question 19

The product of the ages of Srishti, Harrison, and Eva is 2240. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2240 ÷ (x × 2x) = 2240 ÷ (2x²)
Testing x = 8: middle = 2240 ÷ (2 × 8²) = 14
Therefore, eldest = 20

Question 20

The product of the ages of Milo, Amit, and Andre is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18
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