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Product of Ages Beginner-Intermediate Worksheet: Focus on common variations practice Product of Ages BEGINNER INTERMEDIATE

Level up your Product of Ages skills! You're at Worksheet 4 of 10 (33% through this series). This step-up challenge worksheet features 20 beginner-intermediate-level problems with a focus on common variations practice. Topics covered: product of ages for competitive exams, how to solve product of ages, product of ages tricks.

📝 Worksheet 4 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner Intermediate level

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Worksheet 4 of 10 (33% complete)

Question 1

The product of the ages of Yuvraj, Jatin, and Victor is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 8: middle = 2400 ÷ (2 × 8²) = 15
Therefore, eldest = 20

Question 2

The product of the ages of Siddharth, Anthony, and Shweta is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 8: middle = 2400 ÷ (2 × 8²) = 15
Therefore, eldest = 20

Question 3

The product of the ages of Harsh, Joseph, and Bryson is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15

Question 4

The product of the ages of Tucker, Alice, and Justin is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 5

The product of the ages of Narendra, Sujata, and Felix is 288. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 288 ÷ (x × 3x) = 288 ÷ (3x²)
Testing x = 4: middle = 288 ÷ (3 × 4²) = 6
Therefore, eldest = 12

Question 6

The product of the ages of Pranay, Laksh, and Leah is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 7

The product of the ages of Shivam, Nimesh, and Vishal is 1188. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1188 ÷ (x × 3x) = 1188 ÷ (3x²)
Testing x = 6: middle = 1188 ÷ (3 × 6²) = 11
Therefore, eldest = 18

Question 8

The product of the ages of Mike, Mahesh, and Xena is 2240. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2240 ÷ (x × 2x) = 2240 ÷ (2x²)
Testing x = 8: middle = 2240 ÷ (2 × 8²) = 14
Therefore, eldest = 20

Question 9

The product of the ages of Kuldeep, Olivia, and Lokesh is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14

Question 10

The product of the ages of Harper, Ira, and Andre is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 11

The product of the ages of Rohan, Sanjit, and Victoria is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 12

The product of the ages of Kai, Simran, and Lata is 1080. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1080 ÷ (x × 3x) = 1080 ÷ (3x²)
Testing x = 6: middle = 1080 ÷ (3 × 6²) = 10
Therefore, eldest = 18

Question 13

The product of the ages of Zoya, Om, and Seema is 3750. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3750 ÷ (x × 2x) = 3750 ÷ (2x²)
Testing x = 10: middle = 3750 ÷ (2 × 10²) = 15
Therefore, eldest = 25

Question 14

The product of the ages of Siddharth, Yashaswi, and Jaideep is 1911. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1911 ÷ (x × 3x) = 1911 ÷ (3x²)
Testing x = 7: middle = 1911 ÷ (3 × 7²) = 13
Therefore, eldest = 21

Question 15

The product of the ages of Vivian, Eliana, and Akash is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 16

The product of the ages of Julian, Sourav, and Deepa is 810. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 810 ÷ (x × 2x) = 810 ÷ (2x²)
Testing x = 6: middle = 810 ÷ (2 × 6²) = 9
Therefore, eldest = 15

Question 17

The product of the ages of Anup, Shobhit, and Hazel is 2646. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2646 ÷ (x × 2x) = 2646 ÷ (2x²)
Testing x = 9: middle = 2646 ÷ (2 × 9²) = 14
Therefore, eldest = 21

Question 18

The product of the ages of Miles, Tyler, and Kiran is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 19

The product of the ages of Giridhar, Violet, and Sourav is 2646. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2646 ÷ (x × 2x) = 2646 ÷ (2x²)
Testing x = 9: middle = 2646 ÷ (2 × 9²) = 14
Therefore, eldest = 21

Question 20

The product of the ages of Preeti, Akshay, and Savannah is 288. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 288 ÷ (x × 3x) = 288 ÷ (3x²)
Testing x = 4: middle = 288 ÷ (3 × 4²) = 6
Therefore, eldest = 12
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