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Master Product of Ages - Beginner Level Problems Product of Ages BEGINNER

Excel in competitive exams with this skill builder ⚡ worksheet on Product of Ages. Worksheet 3 of 10 contains 20 beginner-level problems. Target your step-by-step problem solving skills while practicing product of ages practice, product of ages for competitive exams, and how to solve product of ages.

📝 Worksheet 3 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner level

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Worksheet 3 of 10 (22% complete)

Question 1

The product of the ages of Lucy, Santosh, and Rylee is 900. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 900 ÷ (x × 3x) = 900 ÷ (3x²)
Testing x = 5: middle = 900 ÷ (3 × 5²) = 12
Therefore, eldest = 15

Question 2

The product of the ages of Oscar, Sarah, and Mamta is 1188. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1188 ÷ (x × 3x) = 1188 ÷ (3x²)
Testing x = 6: middle = 1188 ÷ (3 × 6²) = 11
Therefore, eldest = 18

Question 3

The product of the ages of Kritika, Avinash, and Lily is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 4

The product of the ages of Jitendra, Prem, and Penelope is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 5

The product of the ages of Hina, Shree, and Somesh is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 6

The product of the ages of Sita, Pratibha, and Yashaswi is 2646. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2646 ÷ (x × 2x) = 2646 ÷ (2x²)
Testing x = 9: middle = 2646 ÷ (2 × 9²) = 14
Therefore, eldest = 21

Question 7

The product of the ages of Ayush, Maverick, and Piya is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 8

The product of the ages of Beatrice, Janvi, and Shakti is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15

Question 9

The product of the ages of Tarun, Henry, and Skylar is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15

Question 10

The product of the ages of Anup, Sangeeta, and Eleanor is 1080. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1080 ÷ (x × 3x) = 1080 ÷ (3x²)
Testing x = 6: middle = 1080 ÷ (3 × 6²) = 10
Therefore, eldest = 18

Question 11

The product of the ages of Balram, Piya, and Sasha is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 12

The product of the ages of Lily, Surya, and Balram is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20

Question 13

The product of the ages of Gopal, Sanyam, and Everly is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15

Question 14

The product of the ages of Daksh, Finn, and Anmol is 2646. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2646 ÷ (x × 2x) = 2646 ÷ (2x²)
Testing x = 9: middle = 2646 ÷ (2 × 9²) = 14
Therefore, eldest = 21

Question 15

The product of the ages of David, Indira, and Sarika is 1080. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1080 ÷ (x × 3x) = 1080 ÷ (3x²)
Testing x = 6: middle = 1080 ÷ (3 × 6²) = 10
Therefore, eldest = 18

Question 16

The product of the ages of Cole, Rylee, and Lillian is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 17

The product of the ages of Abhay, Nevaeh, and Piya is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 18

The product of the ages of Abhay, Austin, and Wyatt is 400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 400 ÷ (x × 2x) = 400 ÷ (2x²)
Testing x = 5: middle = 400 ÷ (2 × 5²) = 8
Therefore, eldest = 10

Question 19

The product of the ages of Patrick, Jaideep, and Cole is 162. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 162 ÷ (x × 3x) = 162 ÷ (3x²)
Testing x = 3: middle = 162 ÷ (3 × 3²) = 6
Therefore, eldest = 9

Question 20

The product of the ages of Sophie, Sushma, and Quinn is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20
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