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Product of Ages: Worksheet 2 - Beginner Practice Product of Ages BEGINNER

Ready to master Product of Ages? This entry level practice worksheet (2/10) presents 20 beginner-level challenges. Focus area: pattern recognition. Learn to solve product of ages reasoning questions, handle product of ages practice, and perfect product of ages for competitive exams with our step-by-step solutions.

📝 Worksheet 2 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner level

What you'll learn in this worksheet:
Your progress through Product of Ages
Worksheet 2 of 10 (11% complete)

Question 1

The product of the ages of Nitin, Ashwin, and Leon is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 2

The product of the ages of Raul, Nolan, and Parvathy is 490. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 490 ÷ (x × 2x) = 490 ÷ (2x²)
Testing x = 5: middle = 490 ÷ (2 × 5²) = 7
Therefore, eldest = 14

Question 3

The product of the ages of Pratibha, Komal, and Silas is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 4

The product of the ages of Vedika, Ayush, and Chandan is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 5

The product of the ages of Sonam, Caleb, and Rowan is 1764. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1764 ÷ (x × 3x) = 1764 ÷ (3x²)
Testing x = 7: middle = 1764 ÷ (3 × 7²) = 12
Therefore, eldest = 21

Question 6

The product of the ages of Dhara, Kai, and Chandan is 3750. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3750 ÷ (x × 2x) = 3750 ÷ (2x²)
Testing x = 10: middle = 3750 ÷ (2 × 10²) = 15
Therefore, eldest = 25

Question 7

The product of the ages of Hans, Neelam, and Manju is 3750. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3750 ÷ (x × 2x) = 3750 ÷ (2x²)
Testing x = 10: middle = 3750 ÷ (2 × 10²) = 15
Therefore, eldest = 25

Question 8

The product of the ages of Luke, Dhanush, and Wyatt is 2240. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2240 ÷ (x × 2x) = 2240 ÷ (2x²)
Testing x = 8: middle = 2240 ÷ (2 × 8²) = 14
Therefore, eldest = 20

Question 9

The product of the ages of Owen, Ojas, and Bjorn is 2646. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2646 ÷ (x × 2x) = 2646 ÷ (2x²)
Testing x = 9: middle = 2646 ÷ (2 × 9²) = 14
Therefore, eldest = 21

Question 10

The product of the ages of Shree, Mehul, and Mamta is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 11

The product of the ages of Nandini, Camila, and Tapsi is 810. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 810 ÷ (x × 2x) = 810 ÷ (2x²)
Testing x = 6: middle = 810 ÷ (2 × 6²) = 9
Therefore, eldest = 15

Question 12

The product of the ages of Puneet, Giridhar, and Nolan is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 13

The product of the ages of Meena, Harrison, and Luke is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14

Question 14

The product of the ages of Riddhima, Natalie, and Liam is 162. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 162 ÷ (x × 3x) = 162 ÷ (3x²)
Testing x = 3: middle = 162 ÷ (3 × 3²) = 6
Therefore, eldest = 9

Question 15

The product of the ages of Bhaskar, Sujata, and Ishwar is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 16

The product of the ages of Caroline, Sagar, and Raj is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14

Question 17

The product of the ages of Miles, Ganesh, and Audrey is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 18

The product of the ages of Sangeeta, Bjorn, and Sakshi is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 19

The product of the ages of Sourav, Archana, and Bjorn is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 20

The product of the ages of Nandini, Brielle, and Urvi is 2240. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2240 ÷ (x × 2x) = 2240 ÷ (2x²)
Testing x = 8: middle = 2240 ÷ (2 × 8²) = 14
Therefore, eldest = 20
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