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Product of Ages - Absolute-Beginner Level: core concept mastery Product of Ages ABSOLUTE BEGINNER

This skill primer 🌟 worksheet focuses on Product of Ages - a key topic in Age Based Puzzles. You'll solve 20 absolute-beginner-level problems (Worksheet 1 of 10). The primary focus is on core concept mastery. Master product of ages problems, product of ages reasoning questions, and product of ages practice through systematic practice.

📝 Worksheet 1 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Absolute Beginner level

What you'll learn in this worksheet:
Your progress through Product of Ages
Worksheet 1 of 10 (0% complete)

Question 1

The product of the ages of Ganesh, Allison, and Sarabjit is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 2

The product of the ages of Sneha, Sakshi, and Beau is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 3

The product of the ages of Kashish, Sarah, and Ashwin is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 4

The product of the ages of Nolan, Mike, and Chaman is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 5

The product of the ages of Clara, Marcus, and Suresh is 1080. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1080 ÷ (x × 3x) = 1080 ÷ (3x²)
Testing x = 6: middle = 1080 ÷ (3 × 6²) = 10
Therefore, eldest = 18

Question 6

The product of the ages of Charu, Santosh, and Oscar is 1911. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1911 ÷ (x × 3x) = 1911 ÷ (3x²)
Testing x = 7: middle = 1911 ÷ (3 × 7²) = 13
Therefore, eldest = 21

Question 7

The product of the ages of Michael, Matthew, and Everett is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 8

The product of the ages of Kush, Angel, and Nitin is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 9

The product of the ages of Grace, Indira, and Nevaeh is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 10

The product of the ages of Charlotte, Matteo, and Rakshit is 882. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 882 ÷ (x × 2x) = 882 ÷ (2x²)
Testing x = 7: middle = 882 ÷ (2 × 7²) = 9
Therefore, eldest = 14

Question 11

The product of the ages of Kapil, Rachit, and Ishwar is 1764. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1764 ÷ (x × 3x) = 1764 ÷ (3x²)
Testing x = 7: middle = 1764 ÷ (3 × 7²) = 12
Therefore, eldest = 21

Question 12

The product of the ages of Mridul, Amara, and Lucas is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 13

The product of the ages of Ram, Elizabeth, and Nevaeh is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 8: middle = 2400 ÷ (2 × 8²) = 15
Therefore, eldest = 20

Question 14

The product of the ages of Leo, Tucker, and Sunil is 2240. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2240 ÷ (x × 2x) = 2240 ÷ (2x²)
Testing x = 8: middle = 2240 ÷ (2 × 8²) = 14
Therefore, eldest = 20

Question 15

The product of the ages of Jackson, Leah, and Harper is 2240. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2240 ÷ (x × 2x) = 2240 ÷ (2x²)
Testing x = 8: middle = 2240 ÷ (2 × 8²) = 14
Therefore, eldest = 20

Question 16

The product of the ages of Isabella, Hailey, and Lisa is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15

Question 17

The product of the ages of David, Ria, and Mukesh is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 18

The product of the ages of Giselle, Sakshi, and Sarah is 1764. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1764 ÷ (x × 3x) = 1764 ÷ (3x²)
Testing x = 7: middle = 1764 ÷ (3 × 7²) = 12
Therefore, eldest = 21

Question 19

The product of the ages of Shanti, Shruti, and Vedika is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 20

The product of the ages of Jyoti, Renu, and Pranay is 980. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 980 ÷ (x × 2x) = 980 ÷ (2x²)
Testing x = 7: middle = 980 ÷ (2 × 7²) = 10
Therefore, eldest = 14
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