ReasoningAbility.com

Product of Ages: Worksheet 10 - Expert Practice Product of Ages EXPERT

Ready to master Product of Ages? This accuracy focus 👑 worksheet (10/10) presents 20 expert-level challenges. Focus area: application-based learning. Learn to solve product of ages reasoning tricks, handle fast product of ages solving, and perfect product of ages mastery with our step-by-step solutions.

📝 Worksheet 10 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Expert level

What you'll learn in this worksheet:
Your progress through Product of Ages
Worksheet 10 of 10 (100% complete)

Question 1

The product of the ages of Ritika, Milo, and Malachi is 1188. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 1188 ÷ (x × 3x) = 1188 ÷ (3x²)
Testing x = 6: middle = 1188 ÷ (3 × 6²) = 11
Therefore, eldest = 18

Question 2

The product of the ages of Chaitra, Jatin, and Lucy is 1944. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1944 ÷ (x × 2x) = 1944 ÷ (2x²)
Testing x = 9: middle = 1944 ÷ (2 × 9²) = 12
Therefore, eldest = 18

Question 3

The product of the ages of Harper, Shruti, and Louis is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20

Question 4

The product of the ages of Raghav, Beatrice, and Aaliyah is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 5

The product of the ages of Amrita, Autumn, and Tatiana is 288. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 288 ÷ (x × 3x) = 288 ÷ (3x²)
Testing x = 4: middle = 288 ÷ (3 × 4²) = 6
Therefore, eldest = 12

Question 6

The product of the ages of Dilip, Hailey, and Rupali is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20

Question 7

The product of the ages of Hailey, Freya, and Karan is 3750. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3750 ÷ (x × 2x) = 3750 ÷ (2x²)
Testing x = 10: middle = 3750 ÷ (2 × 10²) = 15
Therefore, eldest = 25

Question 8

The product of the ages of Aditi, Neeraj, and Archana is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 10: middle = 2400 ÷ (2 × 10²) = 12
Therefore, eldest = 20

Question 9

The product of the ages of Mila, Ethan, and Harrison is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 10

The product of the ages of Navya, Prem, and Owen is 3200. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 3200 ÷ (x × 2x) = 3200 ÷ (2x²)
Testing x = 10: middle = 3200 ÷ (2 × 10²) = 16
Therefore, eldest = 20

Question 11

The product of the ages of Vaibhav, Yara, and Pravin is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 12

The product of the ages of Evan, Emma, and Raghav is 400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 400 ÷ (x × 2x) = 400 ÷ (2x²)
Testing x = 5: middle = 400 ÷ (2 × 5²) = 8
Therefore, eldest = 10

Question 13

The product of the ages of John, Malachi, and Sita is 1536. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1536 ÷ (x × 2x) = 1536 ÷ (2x²)
Testing x = 8: middle = 1536 ÷ (2 × 8²) = 12
Therefore, eldest = 16

Question 14

The product of the ages of William, Josephine, and Arthur is 2430. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2430 ÷ (x × 2x) = 2430 ÷ (2x²)
Testing x = 9: middle = 2430 ÷ (2 × 9²) = 15
Therefore, eldest = 18

Question 15

The product of the ages of Satish, Prasanna, and Katia is 288. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 288 ÷ (x × 3x) = 288 ÷ (3x²)
Testing x = 4: middle = 288 ÷ (3 × 4²) = 6
Therefore, eldest = 12

Question 16

The product of the ages of Skylar, Navya, and Mamta is 576. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 576 ÷ (x × 2x) = 576 ÷ (2x²)
Testing x = 6: middle = 576 ÷ (2 × 6²) = 8
Therefore, eldest = 12

Question 17

The product of the ages of Babita, Silas, and Pratibha is 2400. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2400 ÷ (x × 2x) = 2400 ÷ (2x²)
Testing x = 8: middle = 2400 ÷ (2 × 8²) = 15
Therefore, eldest = 20

Question 18

The product of the ages of Prashant, Deepti, and Kailash is 810. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 810 ÷ (x × 2x) = 810 ÷ (2x²)
Testing x = 6: middle = 810 ÷ (2 × 6²) = 9
Therefore, eldest = 15

Question 19

The product of the ages of Sophie, Sanjit, and Muskan is 2240. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 2240 ÷ (x × 2x) = 2240 ÷ (2x²)
Testing x = 8: middle = 2240 ÷ (2 × 8²) = 14
Therefore, eldest = 20

Question 20

The product of the ages of Deepa, Shilpa, and Saachi is 750. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 750 ÷ (x × 3x) = 750 ÷ (3x²)
Testing x = 5: middle = 750 ÷ (3 × 5²) = 10
Therefore, eldest = 15
Previous Worksheet