Arithmetic Progression Analogy: Worksheet 6 - Intermediate-Advanced Practice Arithmetic Progression Analogy INTERMEDIATE ADVANCED

Ready to master Arithmetic Progression Analogy? This timed practice ⚡ worksheet (6/10) presents 20 intermediate-advanced-level challenges. Focus area: speed building. Learn to solve arithmetic progression analogy tricks, handle arithmetic progression analogy shortcut methods, and perfect arithmetic progression analogy bank exam questions with our step-by-step solutions.

📝 Worksheet 6 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate Advanced level

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Worksheet 6 of 10 (55% complete)

Question 1

Find the missing number: 8, 11 : 3 :: 10, ? : ?
In AP, common difference = 3. Next term after 10 is 13

Question 2

Find the missing number: 4, 7 : 3 :: 10, ? : ?
In AP, common difference = 3. Next term after 10 is 13

Question 3

Find the missing number: 10, 16 : 6 :: 3, ? : ?
In AP, common difference = 6. Next term after 3 is 9

Question 4

Find the missing number: 2 : 6 (n=3) :: 2 : ?
The nth term formula: a + (n-1)d. For 2, term 3 = 6

Question 5

Find the missing number: 4 : sum of 2 terms = 12 :: 2 : sum of 2 terms = ?
Sum of 2 terms of AP: n/2 × (2a + (n-1)d). For 2, sum = 8

Question 6

Find the missing number: 10, 14 : 4 :: 9, ? : ?
In AP, common difference = 4. Next term after 9 is 13

Question 7

Find the missing number: 4 : sum of 2 terms = 10 :: 1 : sum of 2 terms = ?
Sum of 2 terms of AP: n/2 × (2a + (n-1)d). For 1, sum = 4

Question 8

Find the missing number: 3 : 11 (n=3) :: 4 : ?
The nth term formula: a + (n-1)d. For 4, term 3 = 12

Question 9

Find the missing number: 4 : 14 (n=3) :: 2 : ?
The nth term formula: a + (n-1)d. For 2, term 3 = 12

Question 10

Find the missing number: 6 : 12 (n=4) :: 7 : ?
The nth term formula: a + (n-1)d. For 7, term 4 = 13

Question 11

Find the missing number: 3, 7 : 4 :: 10, ? : ?
In AP, common difference = 4. Next term after 10 is 14

Question 12

Find the missing number: 10, 14 : 4 :: 10, ? : ?
In AP, common difference = 4. Next term after 10 is 14

Question 13

Find the missing number: 1 : sum of 2 terms = 5 :: 5 : sum of 2 terms = ?
Sum of 2 terms of AP: n/2 × (2a + (n-1)d). For 5, sum = 13

Question 14

Find the missing number: 5 : sum of 2 terms = 12 :: 3 : sum of 2 terms = ?
Sum of 2 terms of AP: n/2 × (2a + (n-1)d). For 3, sum = 8

Question 15

Find the missing number: 1 : sum of 3 terms = 12 :: 4 : sum of 3 terms = ?
Sum of 3 terms of AP: n/2 × (2a + (n-1)d). For 4, sum = 21

Question 16

Find the missing number: 5 : sum of 2 terms = 13 :: 2 : sum of 2 terms = ?
Sum of 2 terms of AP: n/2 × (2a + (n-1)d). For 2, sum = 7

Question 17

Find the missing number: 5 : sum of 3 terms = 27 :: 4 : sum of 3 terms = ?
Sum of 3 terms of AP: n/2 × (2a + (n-1)d). For 4, sum = 24

Question 18

Find the missing number: 6, 12 : 6 :: 3, ? : ?
In AP, common difference = 6. Next term after 3 is 9

Question 19

Find the missing number: 1 : sum of 2 terms = 5 :: 4 : sum of 2 terms = ?
Sum of 2 terms of AP: n/2 × (2a + (n-1)d). For 4, sum = 11

Question 20

Find the missing number: 3 : sum of 3 terms = 18 :: 1 : sum of 3 terms = ?
Sum of 3 terms of AP: n/2 × (2a + (n-1)d). For 1, sum = 12
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