Master Advanced Odd Days - Intermediate-Advanced Level Problems Advanced Odd Days INTERMEDIATE ADVANCED

Excel in competitive exams with this self assessment worksheet on Advanced Odd Days. Worksheet 7 of 10 contains 20 intermediate-advanced-level problems. Target your accuracy improvement skills while practicing advanced odd days shortcut methods, advanced odd days bank exam questions, and advanced odd days ssc cgl.

📝 Worksheet 7 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate Advanced level

What you'll learn in this worksheet:
Your progress through Advanced Odd Days
Worksheet 7 of 10 (66% complete)

Question 1

How many odd days are there in 76 years starting from 1972? (Note: Odd days = remainder when total days are divided by 7)
Total days = 57×365 + 19×366 = 27759 days. Odd days = 27759 mod 7 = 4.

Question 2

How many odd days are there in 100 years starting from 1989? (Note: Odd days = remainder when total days are divided by 7)
Total days = 75×365 + 25×366 = 36525 days. Odd days = 36525 mod 7 = 6.

Question 3

How many odd days are there in 28 years starting from 1947? (Note: Odd days = remainder when total days are divided by 7)
Total days = 21×365 + 7×366 = 10227 days. Odd days = 10227 mod 7 = 0.

Question 4

How many odd days are there in 100 years starting from 1872? (Note: Odd days = remainder when total days are divided by 7)
Total days = 76×365 + 24×366 = 36524 days. Odd days = 36524 mod 7 = 5.

Question 5

How many odd days are there in 400 years starting from 1845? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.

Question 6

How many odd days are there in 100 years starting from 1921? (Note: Odd days = remainder when total days are divided by 7)
Total days = 75×365 + 25×366 = 36525 days. Odd days = 36525 mod 7 = 6.

Question 7

How many odd days are there in 400 years starting from 1822? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.

Question 8

How many odd days are there in 52 years starting from 1852? (Note: Odd days = remainder when total days are divided by 7)
Total days = 40×365 + 12×366 = 18992 days. Odd days = 18992 mod 7 = 1.

Question 9

How many odd days are there in 28 years starting from 1825? (Note: Odd days = remainder when total days are divided by 7)
Total days = 21×365 + 7×366 = 10227 days. Odd days = 10227 mod 7 = 0.

Question 10

How many odd days are there in 28 years starting from 1844? (Note: Odd days = remainder when total days are divided by 7)
Total days = 21×365 + 7×366 = 10227 days. Odd days = 10227 mod 7 = 0.

Question 11

How many odd days are there in 400 years starting from 1977? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.

Question 12

How many odd days are there in 400 years starting from 1908? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.

Question 13

How many odd days are there in 100 years starting from 1836? (Note: Odd days = remainder when total days are divided by 7)
Total days = 76×365 + 24×366 = 36524 days. Odd days = 36524 mod 7 = 5.

Question 14

How many odd days are there in 100 years starting from 1905? (Note: Odd days = remainder when total days are divided by 7)
Total days = 75×365 + 25×366 = 36525 days. Odd days = 36525 mod 7 = 6.

Question 15

How many odd days are there in 400 years starting from 1892? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.

Question 16

How many odd days are there in 400 years starting from 1855? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.

Question 17

How many odd days are there in 76 years starting from 1921? (Note: Odd days = remainder when total days are divided by 7)
Total days = 57×365 + 19×366 = 27759 days. Odd days = 27759 mod 7 = 4.

Question 18

How many odd days are there in 52 years starting from 1853? (Note: Odd days = remainder when total days are divided by 7)
Total days = 40×365 + 12×366 = 18992 days. Odd days = 18992 mod 7 = 1.

Question 19

How many odd days are there in 76 years starting from 1829? (Note: Odd days = remainder when total days are divided by 7)
Total days = 58×365 + 18×366 = 27758 days. Odd days = 27758 mod 7 = 3.

Question 20

How many odd days are there in 52 years starting from 1992? (Note: Odd days = remainder when total days are divided by 7)
Total days = 39×365 + 13×366 = 18993 days. Odd days = 18993 mod 7 = 2.
Previous Worksheet Next Worksheet