Question 1
How many odd days are there in 52 years starting from 1856? (Note: Odd days = remainder when total days are divided by 7)
Total days = 40×365 + 12×366 = 18992 days. Odd days = 18992 mod 7 = 1.
Advanced Odd Days: Worksheet 6 - Intermediate-Advanced Practice Advanced Odd Days INTERMEDIATE ADVANCED
Ready to master Advanced Odd Days? This timed practice ⚡ worksheet (6/10) presents 20 intermediate-advanced-level challenges. Focus area: speed building. Learn to solve advanced odd days tricks, handle advanced odd days shortcut methods, and perfect advanced odd days bank exam questions with our step-by-step solutions.
What you'll learn in this worksheet:
- Understand the logic behind advanced odd days shortcut methods
- Learn step-by-step approaches to speed building
- Handle multi-step problems systematically
- Master complex problem variations and edge cases
- Master advanced odd days tricks through focused practice
Your progress through Advanced Odd Days
Worksheet 6 of 10 (55% complete)
Question 2
How many odd days are there in 400 years starting from 1912? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.
Question 3
How many odd days are there in 76 years starting from 1937? (Note: Odd days = remainder when total days are divided by 7)
Total days = 57×365 + 19×366 = 27759 days. Odd days = 27759 mod 7 = 4.
Question 4
How many odd days are there in 100 years starting from 1885? (Note: Odd days = remainder when total days are divided by 7)
Total days = 76×365 + 24×366 = 36524 days. Odd days = 36524 mod 7 = 5.
Question 5
How many odd days are there in 100 years starting from 1993? (Note: Odd days = remainder when total days are divided by 7)
Total days = 75×365 + 25×366 = 36525 days. Odd days = 36525 mod 7 = 6.
Question 6
How many odd days are there in 400 years starting from 1842? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.
Question 7
How many odd days are there in 400 years starting from 1803? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.
Question 8
How many odd days are there in 400 years starting from 1960? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.
Question 9
How many odd days are there in 76 years starting from 1983? (Note: Odd days = remainder when total days are divided by 7)
Total days = 57×365 + 19×366 = 27759 days. Odd days = 27759 mod 7 = 4.
Question 10
How many odd days are there in 28 years starting from 1950? (Note: Odd days = remainder when total days are divided by 7)
Total days = 21×365 + 7×366 = 10227 days. Odd days = 10227 mod 7 = 0.
Question 11
How many odd days are there in 400 years starting from 1972? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.
Question 12
How many odd days are there in 400 years starting from 1881? (Note: Odd days = remainder when total days are divided by 7)
Total days = 303×365 + 97×366 = 146097 days. Odd days = 146097 mod 7 = 0.
Question 13
How many odd days are there in 52 years starting from 1816? (Note: Odd days = remainder when total days are divided by 7)
Total days = 39×365 + 13×366 = 18993 days. Odd days = 18993 mod 7 = 2.
Question 14
How many odd days are there in 100 years starting from 1951? (Note: Odd days = remainder when total days are divided by 7)
Total days = 75×365 + 25×366 = 36525 days. Odd days = 36525 mod 7 = 6.
Question 15
How many odd days are there in 52 years starting from 1970? (Note: Odd days = remainder when total days are divided by 7)
Total days = 39×365 + 13×366 = 18993 days. Odd days = 18993 mod 7 = 2.
Question 16
How many odd days are there in 28 years starting from 1890? (Note: Odd days = remainder when total days are divided by 7)
Total days = 22×365 + 6×366 = 10226 days. Odd days = 10226 mod 7 = 6.
Question 17
How many odd days are there in 100 years starting from 1919? (Note: Odd days = remainder when total days are divided by 7)
Total days = 75×365 + 25×366 = 36525 days. Odd days = 36525 mod 7 = 6.
Question 18
How many odd days are there in 28 years starting from 1989? (Note: Odd days = remainder when total days are divided by 7)
Total days = 21×365 + 7×366 = 10227 days. Odd days = 10227 mod 7 = 0.
Question 19
How many odd days are there in 100 years starting from 1811? (Note: Odd days = remainder when total days are divided by 7)
Total days = 76×365 + 24×366 = 36524 days. Odd days = 36524 mod 7 = 5.
Question 20
How many odd days are there in 76 years starting from 1849? (Note: Odd days = remainder when total days are divided by 7)
Total days = 58×365 + 18×366 = 27758 days. Odd days = 27758 mod 7 = 3.
🏆 Halfway champion! 55% through Advanced Odd Days. Keep the momentum!