Sum of n terms in AP: Worksheet 10 - Expert Practice Sum of n terms in AP EXPERT

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📝 Worksheet 10 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Expert level

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Question 1

Find the sum of first 18 terms of the AP: First term=6, common difference=4.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*6+(17)*4] = 720.0

Question 2

Find the sum of first 15 terms of the AP: First term=10, common difference=7.
S_n = n/2 [2a + (n-1)d] = 15/2*[2*10+(14)*7] = 885.0

Question 3

Find the sum of first 20 terms of the AP: First term=4, common difference=3.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*4+(19)*3] = 650.0

Question 4

Find the sum of first 18 terms of the AP: First term=12, common difference=6.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*12+(17)*6] = 1134.0

Question 5

Find the sum of first 16 terms of the AP: First term=7, common difference=8.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*7+(15)*8] = 1072.0

Question 6

Find the sum of first 20 terms of the AP: First term=12, common difference=2.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*12+(19)*2] = 620.0

Question 7

Find the sum of first 10 terms of the AP: First term=11, common difference=8.
S_n = n/2 [2a + (n-1)d] = 10/2*[2*11+(9)*8] = 470.0

Question 8

Find the sum of first 7 terms of the AP: First term=11, common difference=4.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*11+(6)*4] = 161.0

Question 9

Find the sum of first 18 terms of the AP: First term=3, common difference=4.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*3+(17)*4] = 666.0

Question 10

Find the sum of first 19 terms of the AP: First term=12, common difference=7.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*12+(18)*7] = 1425.0

Question 11

Find the sum of first 12 terms of the AP: First term=7, common difference=3.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*7+(11)*3] = 282.0

Question 12

Find the sum of first 19 terms of the AP: First term=2, common difference=6.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*2+(18)*6] = 1064.0

Question 13

Find the sum of first 8 terms of the AP: First term=10, common difference=5.
S_n = n/2 [2a + (n-1)d] = 8/2*[2*10+(7)*5] = 220.0

Question 14

Find the sum of first 20 terms of the AP: First term=4, common difference=7.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*4+(19)*7] = 1410.0

Question 15

Find the sum of first 12 terms of the AP: First term=6, common difference=2.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*6+(11)*2] = 204.0

Question 16

Find the sum of first 16 terms of the AP: First term=11, common difference=3.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*11+(15)*3] = 536.0

Question 17

Find the sum of first 16 terms of the AP: First term=2, common difference=6.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*2+(15)*6] = 752.0

Question 18

Find the sum of first 17 terms of the AP: First term=12, common difference=6.
S_n = n/2 [2a + (n-1)d] = 17/2*[2*12+(16)*6] = 1020.0

Question 19

Find the sum of first 16 terms of the AP: First term=12, common difference=6.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*12+(15)*6] = 912.0

Question 20

Find the sum of first 20 terms of the AP: First term=4, common difference=3.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*4+(19)*3] = 650.0
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