Sum of n terms in AP - Expert Level: conceptual clarity Sum of n terms in AP EXPERT

This skill evaluation ⚡ worksheet focuses on Sum of n terms in AP - a key topic in Arithmetic Problems. You'll solve 20 expert-level problems (Worksheet 9 of 10). The primary focus is on conceptual clarity. Master sum of n terms in ap ssc cgl, sum of n terms in ap reasoning tricks, and fast sum of n terms in ap solving through systematic practice.

📝 Worksheet 9 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Expert level

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Worksheet 9 of 10 (88% complete)

Question 1

Find the sum of first 11 terms of the AP: First term=8, common difference=7.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*8+(10)*7] = 473.0

Question 2

Find the sum of first 18 terms of the AP: First term=5, common difference=6.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*5+(17)*6] = 1008.0

Question 3

Find the sum of first 20 terms of the AP: First term=7, common difference=5.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*7+(19)*5] = 1090.0

Question 4

Find the sum of first 14 terms of the AP: First term=10, common difference=6.
S_n = n/2 [2a + (n-1)d] = 14/2*[2*10+(13)*6] = 686.0

Question 5

Find the sum of first 9 terms of the AP: First term=10, common difference=8.
S_n = n/2 [2a + (n-1)d] = 9/2*[2*10+(8)*8] = 378.0

Question 6

Find the sum of first 14 terms of the AP: First term=8, common difference=7.
S_n = n/2 [2a + (n-1)d] = 14/2*[2*8+(13)*7] = 749.0

Question 7

Find the sum of first 15 terms of the AP: First term=12, common difference=2.
S_n = n/2 [2a + (n-1)d] = 15/2*[2*12+(14)*2] = 390.0

Question 8

Find the sum of first 20 terms of the AP: First term=6, common difference=6.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*6+(19)*6] = 1260.0

Question 9

Find the sum of first 13 terms of the AP: First term=9, common difference=7.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*9+(12)*7] = 663.0

Question 10

Find the sum of first 16 terms of the AP: First term=3, common difference=6.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*3+(15)*6] = 768.0

Question 11

Find the sum of first 8 terms of the AP: First term=11, common difference=2.
S_n = n/2 [2a + (n-1)d] = 8/2*[2*11+(7)*2] = 144.0

Question 12

Find the sum of first 9 terms of the AP: First term=8, common difference=6.
S_n = n/2 [2a + (n-1)d] = 9/2*[2*8+(8)*6] = 288.0

Question 13

Find the sum of first 14 terms of the AP: First term=2, common difference=7.
S_n = n/2 [2a + (n-1)d] = 14/2*[2*2+(13)*7] = 665.0

Question 14

Find the sum of first 15 terms of the AP: First term=9, common difference=4.
S_n = n/2 [2a + (n-1)d] = 15/2*[2*9+(14)*4] = 555.0

Question 15

Find the sum of first 18 terms of the AP: First term=11, common difference=4.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*11+(17)*4] = 810.0

Question 16

Find the sum of first 13 terms of the AP: First term=9, common difference=8.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*9+(12)*8] = 741.0

Question 17

Find the sum of first 20 terms of the AP: First term=3, common difference=5.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*3+(19)*5] = 1010.0

Question 18

Find the sum of first 12 terms of the AP: First term=7, common difference=8.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*7+(11)*8] = 612.0

Question 19

Find the sum of first 13 terms of the AP: First term=12, common difference=7.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*12+(12)*7] = 702.0

Question 20

Find the sum of first 19 terms of the AP: First term=4, common difference=4.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*4+(18)*4] = 760.0
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