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Min/Max Age Constraints - Expert Level: conceptual clarity Min/Max Age Constraints EXPERT

This skill evaluation ⚡ worksheet focuses on Min/Max Age Constraints - a key topic in Age Problems. You'll solve 20 expert-level problems (Worksheet 9 of 10). The primary focus is on conceptual clarity. Master min/max age constraints ssc cgl, min/max age constraints reasoning tricks, and fast min/max age constraints solving through systematic practice.

📝 Worksheet 9 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Expert level

What you'll learn in this worksheet:
Your progress through Min/Max Age Constraints
Worksheet 9 of 10 (88% complete)

Question 1

A is older than B. C is younger than B. A + B + C = 61. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 61, max C = 15

Question 2

A is older than B. C is younger than B. A + B + C = 81. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 81, max C = 20

Question 3

A and B's ages sum to 45. A is between 4 and 5 times as old as B. What is the minimum possible age of A?
A + B = 45, A/B between 4 and 5. For min A, take A/B = 4 → B = 9.0, A = 36.0 → min A = 36

Question 4

Sum of A and B's ages is 53. After 8 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 53, (A+8) = 3*(B+8) → A = 43.8 → max A = 43

Question 5

A and B's ages sum to 49. A is between 3 and 5 times as old as B. What is the minimum possible age of A?
A + B = 49, A/B between 3 and 5. For min A, take A/B = 3 → B = 12.2, A = 36.8 → min A = 37

Question 6

A is older than B. C is younger than B. A + B + C = 70. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 70, max C = 21

Question 7

Sum of A and B's ages is 52. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 52, (A+10) = 3*(B+10) → A = 44.0 → max A = 44

Question 8

A and B's ages sum to 45. A is between 5 and 2 times as old as B. What is the minimum possible age of A?
A + B = 45, A/B between 5 and 2. For min A, take A/B = 5 → B = 7.5, A = 37.5 → min A = 38

Question 9

A and B's ages sum to 51. A is between 2 and 3 times as old as B. What is the minimum possible age of A?
A + B = 51, A/B between 2 and 3. For min A, take A/B = 2 → B = 17.0, A = 34.0 → min A = 34

Question 10

Sum of A and B's ages is 69. After 5 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 69, (A+5) = 2*(B+5) → A = 47.7 → max A = 47

Question 11

A and B's ages sum to 50. A is between 2 and 4 times as old as B. What is the minimum possible age of A?
A + B = 50, A/B between 2 and 4. For min A, take A/B = 2 → B = 16.7, A = 33.3 → min A = 34

Question 12

Sum of A and B's ages is 54. After 8 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 54, (A+8) = 2*(B+8) → A = 38.7 → max A = 38

Question 13

Sum of A and B's ages is 63. After 8 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 63, (A+8) = 2*(B+8) → A = 44.7 → max A = 44

Question 14

A and B's ages sum to 49. A is between 5 and 3 times as old as B. What is the minimum possible age of A?
A + B = 49, A/B between 5 and 3. For min A, take A/B = 5 → B = 8.2, A = 40.8 → min A = 41

Question 15

A is older than B. C is younger than B. A + B + C = 80. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 80, max C = 19

Question 16

A and B's ages sum to 47. A is between 4 and 5 times as old as B. What is the minimum possible age of A?
A + B = 47, A/B between 4 and 5. For min A, take A/B = 4 → B = 9.4, A = 37.6 → min A = 38

Question 17

A and B's ages sum to 42. A is between 4 and 2 times as old as B. What is the minimum possible age of A?
A + B = 42, A/B between 4 and 2. For min A, take A/B = 4 → B = 8.4, A = 33.6 → min A = 34

Question 18

A and B's ages sum to 45. A is between 4 and 5 times as old as B. What is the minimum possible age of A?
A + B = 45, A/B between 4 and 5. For min A, take A/B = 4 → B = 9.0, A = 36.0 → min A = 36

Question 19

A is older than B. C is younger than B. A + B + C = 70. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 70, max C = 19

Question 20

Sum of A and B's ages is 67. After 10 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 67, (A+10) = 2*(B+10) → A = 48.0 → max A = 48
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