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Min/Max Age Constraints Advanced Worksheet: Focus on exam-oriented approach Min/Max Age Constraints ADVANCED

Level up your Min/Max Age Constraints skills! You're at Worksheet 8 of 10 (77% through this series). This exam hall simulation worksheet features 20 advanced-level problems with a focus on exam-oriented approach. Topics covered: min/max age constraints bank exam questions, min/max age constraints ssc cgl, min/max age constraints reasoning tricks.

📝 Worksheet 8 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Advanced level

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Worksheet 8 of 10 (77% complete)

Question 1

Sum of A and B's ages is 62. After 5 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 62, (A+5) = 2*(B+5) → A = 43.0 → max A = 43

Question 2

A is older than B. C is younger than B. A + B + C = 75. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 75, max C = 20

Question 3

A and B's ages sum to 50. A is between 4 and 3 times as old as B. What is the minimum possible age of A?
A + B = 50, A/B between 4 and 3. For min A, take A/B = 4 → B = 10.0, A = 40.0 → min A = 40

Question 4

A is older than B. C is younger than B. A + B + C = 68. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 68, max C = 19

Question 5

A and B's ages sum to 49. A is between 5 and 4 times as old as B. What is the minimum possible age of A?
A + B = 49, A/B between 5 and 4. For min A, take A/B = 5 → B = 8.2, A = 40.8 → min A = 41

Question 6

Sum of A and B's ages is 64. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 64, (A+10) = 3*(B+10) → A = 53.0 → max A = 53

Question 7

A and B's ages sum to 46. A is between 4 and 2 times as old as B. What is the minimum possible age of A?
A + B = 46, A/B between 4 and 2. For min A, take A/B = 4 → B = 9.2, A = 36.8 → min A = 37

Question 8

Sum of A and B's ages is 66. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 66, (A+10) = 3*(B+10) → A = 54.5 → max A = 54

Question 9

A and B's ages sum to 44. A is between 5 and 2 times as old as B. What is the minimum possible age of A?
A + B = 44, A/B between 5 and 2. For min A, take A/B = 5 → B = 7.3, A = 36.7 → min A = 37

Question 10

Sum of A and B's ages is 70. After 9 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 70, (A+9) = 3*(B+9) → A = 57.0 → max A = 57

Question 11

A is older than B. C is younger than B. A + B + C = 61. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 61, max C = 18

Question 12

Sum of A and B's ages is 66. After 10 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 66, (A+10) = 2*(B+10) → A = 47.3 → max A = 47

Question 13

A is older than B. C is younger than B. A + B + C = 73. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 73, max C = 22

Question 14

A and B's ages sum to 60. A is between 4 and 5 times as old as B. What is the minimum possible age of A?
A + B = 60, A/B between 4 and 5. For min A, take A/B = 4 → B = 12.0, A = 48.0 → min A = 48

Question 15

A is older than B. C is younger than B. A + B + C = 66. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 66, max C = 19

Question 16

Sum of A and B's ages is 54. After 10 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 54, (A+10) = 3*(B+10) → A = 45.5 → max A = 45

Question 17

A and B's ages sum to 40. A is between 5 and 2 times as old as B. What is the minimum possible age of A?
A + B = 40, A/B between 5 and 2. For min A, take A/B = 5 → B = 6.7, A = 33.3 → min A = 34

Question 18

A and B's ages sum to 58. A is between 2 and 4 times as old as B. What is the minimum possible age of A?
A + B = 58, A/B between 2 and 4. For min A, take A/B = 2 → B = 19.3, A = 38.7 → min A = 39

Question 19

A and B's ages sum to 55. A is between 3 and 2 times as old as B. What is the minimum possible age of A?
A + B = 55, A/B between 3 and 2. For min A, take A/B = 3 → B = 13.8, A = 41.2 → min A = 42

Question 20

A and B's ages sum to 42. A is between 2 and 5 times as old as B. What is the minimum possible age of A?
A + B = 42, A/B between 2 and 5. For min A, take A/B = 2 → B = 14.0, A = 28.0 → min A = 28
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