Permutation with Restriction

Permutation with Restriction problems involve arranging objects with specific constraints such as: certain objects must be together, must be apart, must be at fixed positions, or must be at ends. These problems require treating restricted groups as units or using complementary counting.

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Introduction to Permutation with Restriction

Permutation with Restriction problems involve arranging objects with specific constraints such as: certain objects must be together, must be apart, must be at fixed positions, or must be at ends. These problems require treating restricted groups as units or using complementary counting.

Prerequisites

Basic permutation Fundamental Counting Principle Treating groups as units Complementary counting
Why This Matters: Restricted permutation problems appear in 2-3 questions in SSC CGL and Banking exams. They test application of permutation concepts to real-world constraints.

How to Solve Permutation with Restriction Problems

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Step 1: Identify the type of restriction (together, apart, fixed position, ends)

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Step 2: For 'together' problems: treat the group as a single unit

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Step 3: Arrange the units (including the group unit) using permutation formula

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Step 4: Multiply by internal arrangements within the group

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Step 5: For 'apart' problems: use complementary counting or gap method

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Step 6: For fixed position: fix that position first, then arrange remaining

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Step 7: For 'ends' problems: handle end positions first, then arrange middle

Pro Strategy: For 'together' constraints: tie the required objects into a bundle. For 'apart' constraints: use the gap method or subtract 'together' cases from total. For fixed positions: fill constrained positions first.

Example Problem

Example: In how many ways can 5 people be seated in a row such that two specific people always sit together? Solution: Step 1: Treat the two specific people as a single unit Step 2: Now we have 4 units to arrange (the pair + 3 other individuals) Step 3: 4 units can be arranged in 4! = 24 ways Step 4: The two people within the pair can be arranged in 2! = 2 ways Step 5: Total = 24 × 2 = 48 ways Answer: 48 ways

Pro Tips & Tricks

  • Together = treat as one unit, then multiply by internal arrangements
  • Apart = total - together (complementary counting)
  • Gap method for 'no two together': arrange unrestricted items first, then place restricted in gaps
  • For 'ends' constraints: fill end positions first
  • For specific positions: fix those positions, then arrange the rest
  • When multiple groups must be together, treat each group as a separate unit

Shortcut Methods to Solve Faster

Two specific persons together in a row: 2 × (n-1)!
Two specific persons apart: n! - 2 × (n-1)!
Vowels together in a word: treat vowels as one unit, then multiply by vowels' internal arrangements
First and last positions fixed: arrange remaining (n-2) items

Common Mistakes to Avoid

Forgetting to multiply by internal arrangements of the grouped items
Applying 'together' logic to 'apart' problems
Not considering that grouped items can be arranged internally
For 'ends' problems, forgetting that both ends need to be filled

Exam Importance

Permutation with Restriction is an important topic for various competitive exams. Here's how frequently it appears:

SSC CGL
2-3 questions
BANKING PO
2-3 questions
RAILWAYS RRB
2-3 questions
CAT
1-2 questions
INSURANCE
2-3 questions

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Start with Worksheet 1 and work your way up to expert level! Each worksheet includes:

20 practice questions
Detailed solutions
Step-by-step explanations
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