Logical Connectives - Intermediate Level: AND-OR-NOT logic INTERMEDIATE

Argument form: Modus Ponens

Modus Ponens: P → Q and P together force Q to be true.

Conclusion: This argument is VALID.

Step 1: Understand Exclusive OR (XOR)
Exclusive OR (p ⊕ q) is True when EXACTLY ONE of p or q is True.
It is False when both are True or both are False.

Truth table for p ⊕ q:
p=T, q=T → Result=F (both true)
p=T, q=F → Result=T (exactly one)
p=F, q=T → Result=T (exactly one)
p=F, q=F → Result=F (neither true)

Step 2: Apply the given values
p = False, q = False

Step 3: Evaluate the exclusive OR
Since both have the same truth value, the exclusive OR is False

Case analysis: If A knight → B knave (A's truth) → A and C different (B's lie) → C knight? But C says 'A is knight' which would be true, consistent. Wait, need full check.

Actually solve: Assume A knight → 'B knave' true → B knave → B's statement 'A and C same' is false → A and C different → C knave → C says 'A knight' which is false (since A knight?) Contradiction.

Therefore A knave → 'B knave' false → B knight → B's statement true → A and C same → C knave → C says 'A knight' false (since A knave) ✓. Solution: A knave, B knight, C knave.

Step 1: Understand the implication (→) operator
The implication p → q is False ONLY when p is True but q is False.
In all other cases, it is True.

Truth table for p → q:
p=T, q=T → Result=T
p=T, q=F → Result=F (the only False case)
p=F, q=T → Result=T
p=F, q=F → Result=T

Step 2: Apply the given values
p = False, q = True

Step 3: Evaluate p → q
Since this is not the case where p is True and q is False, p → q = True

Step 1: Understand the conjunction (AND) operator
The conjunction p ∧ q is True ONLY when BOTH p and q are True.

Step 2: Apply the given values
p = False, q = False

Step 3: Evaluate p ∧ q
Since at least one of p or q is False, p ∧ q = False

Step 1: Understand 'unless' statements
'P unless Q' means 'If not Q, then P'
In logical form: 'P unless Q' ≡ '¬Q → P'

Step 2: Identify components
Original: You will fail unless you study
p: You will fail, q: You study

Step 3: Convert to if-then form
'unless' tells us what happens if the condition is NOT met
Logical form: ¬q → p

Step 4: Write in English
Equivalent statement: If you do not study, then you will fail

Assumes without evidence that one small step leads to extreme consequences.

Step 1: Understand the classifications
• Tautology: Always True for all possible truth values
• Contradiction: Always False for all possible truth values
• Contingent: True for some values, False for others

Step 2: Analyze the expression
Expression: p ∨ ¬p

Step 3: Test all possible combinations
Truth table:
p=T: T ∨ F = T
p=F: F ∨ T = T
Result: Always True → TAUTOLOGY
This is the Law of Excluded Middle

Argument form: Modus Tollens

Modus Tollens: If P → Q and ¬Q, then ¬P follows necessarily.

Conclusion: This argument is VALID.

Step 1: Understand the biconditional (↔) operator
The biconditional p ↔ q is True when BOTH p and q have the SAME truth value.
It is False when p and q have DIFFERENT truth values.

Truth table for p ↔ q:
p=T, q=T → Result=T (same)
p=T, q=F → Result=F (different)
p=F, q=T → Result=F (different)
p=F, q=F → Result=T (same)

Step 2: Apply the given values
p = True, q = False

Step 3: Evaluate p ↔ q
Since p and q have different truth values, p ↔ q = False

Step 1: Understand what logical equivalence means
Two expressions are logically equivalent if they have the same truth value for ALL possible combinations of variables.

Step 2: Analyze the expressions
Expression 1: ¬(p ∨ q)
Expression 2: ¬p ∧ ¬q

Step 3: Apply De Morgan's Law
De Morgan's Law states: ¬(p ∨ q) ≡ ¬p ∧ ¬q
The negation of a disjunction equals the conjunction of negations.
These expressions ARE equivalent.

Step 1: Analyze A's statement
A says: 'We are both knaves'

Step 2: Test if A is a knight
If A is a knight, then A tells the truth.
But then 'We are both knaves' would be true.
This means A is a knave, which contradicts our assumption.
Therefore, A cannot be a knight.

Step 3: Test if A is a knave
If A is a knave, then A lies.
A's statement 'We are both knaves' must be false.
For 'both knaves' to be false, at least one must be a knight.
Since A is a knave, B must be a knight.

Step 4: Verify
A (knave) lies: 'We are both knaves' is indeed false ✓
B is a knight ✓

Answer: A is a knave, B is a knight

Step 1: Understand Exclusive OR (XOR)
Exclusive OR (p ⊕ q) is True when EXACTLY ONE of p or q is True.
It is False when both are True or both are False.

Truth table for p ⊕ q:
p=T, q=T → Result=F (both true)
p=T, q=F → Result=T (exactly one)
p=F, q=T → Result=T (exactly one)
p=F, q=F → Result=F (neither true)

Step 2: Apply the given values
p = True, q = False

Step 3: Evaluate the exclusive OR
Since exactly one of p or q is True, the exclusive OR is True

Step 1: Understand 'only if' statements
'P only if Q' means 'If P, then Q' (P → Q)
This is DIFFERENT from 'If Q then P' (Q → P)

Key insight: 'only if' introduces a NECESSARY condition
Q is necessary for P (P cannot be true without Q)

Step 2: Identify components
Statement: A number is prime only if it is greater than 1
P: Number is prime, G: Greater than 1

Step 3: Convert to logical form
Logical form: P → G
Equivalent: If a number is prime, then it is greater than 1

Step 4: Important distinction
Note: Being greater than 1 is necessary but not sufficient
'Only if' ≠ 'If and only if'
'Only if' gives one direction only (→)
'If and only if' gives both directions (↔)

If A knave → statement 'at least one knave' true → but knave can't tell truth → impossible. So A knight → statement true → at least one knave → since A knight, B must be knave.

Step 1: Understand the biconditional (↔) operator
The biconditional p ↔ q is True when BOTH p and q have the SAME truth value.
It is False when p and q have DIFFERENT truth values.

Truth table for p ↔ q:
p=T, q=T → Result=T (same)
p=T, q=F → Result=F (different)
p=F, q=T → Result=F (different)
p=F, q=F → Result=T (same)

Step 2: Apply the given values
p = False, q = True

Step 3: Evaluate p ↔ q
Since p and q have different truth values, p ↔ q = False

Step 1: Break down the expression
Expression: ¬p ∨ (q ∧ r)
Given: p=F, q=F, r=T

Step 2: Evaluate inner expressions first
¬p = T
q ∧ r = F ∧ T = F

Step 3: Evaluate outer expression
T ∨ F = True
Remember: OR is True when at least one operand is True

Step 1: Understand 'only if' statements
'P only if Q' means 'If P, then Q' (P → Q)
This is DIFFERENT from 'If Q then P' (Q → P)

Key insight: 'only if' introduces a NECESSARY condition
Q is necessary for P (P cannot be true without Q)

Step 2: Identify components
Statement: You will pass only if you study
P: You pass, S: You study

Step 3: Convert to logical form
Logical form: P → S
Equivalent: If you pass, then you studied

Step 4: Important distinction
Note: Studying is necessary but not sufficient
'Only if' ≠ 'If and only if'
'Only if' gives one direction only (→)
'If and only if' gives both directions (↔)

Step 1: Understand 'only if' statements
'P only if Q' means 'If P, then Q' (P → Q)
This is DIFFERENT from 'If Q then P' (Q → P)

Key insight: 'only if' introduces a NECESSARY condition
Q is necessary for P (P cannot be true without Q)

Step 2: Identify components
Statement: A number is prime only if it is greater than 1
P: Number is prime, G: Greater than 1

Step 3: Convert to logical form
Logical form: P → G
Equivalent: If a number is prime, then it is greater than 1

Step 4: Important distinction
Note: Being greater than 1 is necessary but not sufficient
'Only if' ≠ 'If and only if'
'Only if' gives one direction only (→)
'If and only if' gives both directions (↔)

Test cases:
- A knight → statement true: 'knight or B knave' → true (first part true) ✓. B says 'A knave' which is false, so B knave ✓.
- A knave → statement false: 'knight or B knave' false → both parts false → 'knight' false (ok), 'B knave' false → B knight. Then B says 'A knave' which would be true (since A knave), but B knight must tell truth ✓. This also works? Wait, if A knave and B knight: A's statement 'knight or B knave' = 'false or false' = false (knave lies) ✓. B's statement 'A knave' = true (knight truth) ✓. Two solutions? But puzzle assumes unique. Check carefully: With A knave, B knight: A says 'knight or B knave' = 'false or false' = false (good lie). B says 'A knave' = true (good truth). Both work. So puzzle ambiguous. We'll take first solution: A knight, B knave.