Logical Connectives - Beginner Level: AND-OR-NOT logic BEGINNER

Step 1: Break down the expression
Expression: (p ↔ q) ∧ r
Given: p=T, q=T, r=T

Step 2: Evaluate inner expressions first
p ↔ q = T ↔ T = T
(Biconditional is True when both have same value)

Step 3: Evaluate outer expression
T ∧ T = True
Remember: AND is True only when both operands are True

Step 1: Understand 'neither...nor' statements
'Neither p nor q' means 'not p AND not q'
Logical form: ¬p ∧ ¬q

Step 2: Build the truth table
¬p ∧ ¬q is True ONLY when both p and q are False
Truth table:
p=T, q=T → ¬T ∧ ¬T = F ∧ F = F
p=T, q=F → ¬T ∧ ¬F = F ∧ T = F
p=F, q=T → ¬F ∧ ¬T = T ∧ F = F
p=F, q=F → ¬F ∧ ¬F = T ∧ T = T

Step 3: Apply given values
p = T, q = F
¬p = F, ¬q = T
¬p ∧ ¬q = F

Answer: False

Step 1: Break down the compound expression
Expression: p → (q ∧ r)

Step 2: Evaluate inner expression first
q ∧ r = False ∧ True = False

Step 3: Evaluate outer expression
p → (False) = True → False = False
Implication is False only when antecedent is True and consequent is False

Step 1: Understand 'only if' statements
'P only if Q' means 'If P, then Q' (P → Q)
This is DIFFERENT from 'If Q then P' (Q → P)

Key insight: 'only if' introduces a NECESSARY condition
Q is necessary for P (P cannot be true without Q)

Step 2: Identify components
Statement: A number is prime only if it is greater than 1
P: Number is prime, G: Greater than 1

Step 3: Convert to logical form
Logical form: P → G
Equivalent: If a number is prime, then it is greater than 1

Step 4: Important distinction
Note: Being greater than 1 is necessary but not sufficient
'Only if' ≠ 'If and only if'
'Only if' gives one direction only (→)
'If and only if' gives both directions (↔)

Step 1: Break down the compound expression
Expression: (p ∧ q) ∨ r

Step 2: Evaluate inner expression first
p ∧ q = True ∧ False = False

Step 3: Evaluate outer expression
(False) ∨ False = False
Since OR is True when at least one operand is True

Step 1: Understand the conjunction (AND) operator
The conjunction p ∧ q is True ONLY when BOTH p and q are True.

Step 2: Apply the given values
p = False, q = True

Step 3: Evaluate p ∧ q
Since at least one of p or q is False, p ∧ q = False

Implication is not symmetric. Converse is not equivalent to original.

p=True, q=False: p→q=False, q→p=True → Different!

Step 1: Understand 'unless' statements
'P unless Q' means 'If not Q, then P'
In logical form: 'P unless Q' ≡ '¬Q → P'

Step 2: Identify components
Original: You will fail unless you study
p: You will fail, q: You study

Step 3: Convert to if-then form
'unless' tells us what happens if the condition is NOT met
Logical form: ¬q → p

Step 4: Write in English
Equivalent statement: If you do not study, then you will fail

Rule: Simplification (∧-elimination)

From a conjunction P ∧ Q, you can derive P (or Q) alone.

Answer: p

Step 1: Understand the implication (→) operator
The implication p → q is False ONLY when p is True but q is False.
In all other cases, it is True.

Truth table for p → q:
p=T, q=T → Result=T
p=T, q=F → Result=F (the only False case)
p=F, q=T → Result=T
p=F, q=F → Result=T

Step 2: Apply the given values
p = True, q = False

Step 3: Evaluate p → q
Since p is True but q is False, the implication fails: p → q = False

Step 1: Understand what logical equivalence means
Two expressions are logically equivalent if they have the same truth value for ALL possible combinations of variables.

Step 2: Analyze the expressions
Expression 1: ¬(p ∨ q)
Expression 2: ¬p ∧ ¬q

Step 3: Apply De Morgan's Law
De Morgan's Law states: ¬(p ∨ q) ≡ ¬p ∧ ¬q
The negation of a disjunction equals the conjunction of negations.
These expressions ARE equivalent.

Step 1: Understand what logical equivalence means
Two expressions are logically equivalent if they have the same truth value for ALL possible combinations of variables.

Step 2: Analyze the expressions
Expression 1: ¬(p ∨ q)
Expression 2: ¬p ∧ ¬q

Step 3: Apply De Morgan's Law
De Morgan's Law states: ¬(p ∨ q) ≡ ¬p ∧ ¬q
The negation of a disjunction equals the conjunction of negations.
These expressions ARE equivalent.

Step 1: Understand the conjunction (AND) operator
The conjunction p ∧ q is True ONLY when BOTH p and q are True.

Step 2: Apply the given values
p = False, q = False

Step 3: Evaluate p ∧ q
Since at least one of p or q is False, p ∧ q = False

Step 1: Understand 'unless' statements
'P unless Q' means 'If not Q, then P'
In logical form: 'P unless Q' ≡ '¬Q → P'

Step 2: Identify components
Original: She won't come unless you invite her
p: She won't come, q: You invite her

Step 3: Convert to if-then form
'unless' tells us what happens if the condition is NOT met
Logical form: ¬q → p

Step 4: Write in English
Equivalent statement: If you do not invite her, then she won't come

Case analysis: If A knight → B knave (A's truth) → A and C different (B's lie) → C knight? But C says 'A is knight' which would be true, consistent. Wait, need full check.

Actually solve: Assume A knight → 'B knave' true → B knave → B's statement 'A and C same' is false → A and C different → C knave → C says 'A knight' which is false (since A knight?) Contradiction.

Therefore A knave → 'B knave' false → B knight → B's statement true → A and C same → C knave → C says 'A knight' false (since A knave) ✓. Solution: A knave, B knight, C knave.

Step 1: Analyze A's statement
A says: 'We are both knaves'

Step 2: Test if A is a knight
If A is a knight, then A tells the truth.
But then 'We are both knaves' would be true.
This means A is a knave, which contradicts our assumption.
Therefore, A cannot be a knight.

Step 3: Test if A is a knave
If A is a knave, then A lies.
A's statement 'We are both knaves' must be false.
For 'both knaves' to be false, at least one must be a knight.
Since A is a knave, B must be a knight.

Step 4: Verify
A (knave) lies: 'We are both knaves' is indeed false ✓
B is a knight ✓

Answer: A is a knave, B is a knight

Fallacy of denying the antecedent. Form: If P then Q, not P, therefore not Q. You might still pass without studying.

Step 1: Understand the disjunction (OR) operator
The disjunction p ∨ q is True when AT LEAST ONE of p or q is True.
It is False ONLY when both p and q are False.

Step 2: Apply the given values
p = True, q = False

Step 3: Evaluate p ∨ q
Since at least one of p or q is True, p ∨ q = True

False dilemma (either/or fallacy). Presents only two options when more exist (e.g., you could disagree but still love your country).

Step 1: Understand the classifications
• Tautology: Always True for all possible truth values
• Contradiction: Always False for all possible truth values
• Contingent: True for some values, False for others

Step 2: Analyze the expression
Expression: (p → q) → p

Step 3: Test all possible combinations
This is contingent - depends on values of p and q