Two Clue Chain

Two Clue Chain problems present exactly two relationship statements about ages, such as 'A is twice as old as B' and 'Five years ago, A was three times as old as B'. These two clues are sufficient to determine the present ages.

10Worksheets
200+Practice Questions
BeginnerDifficulty
2-3 hoursHours to Master

Introduction to Two Clue Chain

Two Clue Chain problems present exactly two relationship statements about ages, such as 'A is twice as old as B' and 'Five years ago, A was three times as old as B'. These two clues are sufficient to determine the present ages.

Prerequisites

Basic linear equations Understanding of 'years ago' and 'years later' Ratio and proportion basics
Why This Matters: Two Clue Chain forms the foundation of age problems. You can expect 2-3 questions in SSC CGL, 2-3 in Banking PO, and 2-3 in Railways RRB exams.

How to Solve Two Clue Chain Problems

1

Step 1: Let the present age of the first person be x and the second person be y (or use one variable for both if relationship is direct)

2

Step 2: Translate the first clue into a mathematical equation

3

Step 3: Translate the second clue by adjusting ages (subtract for past, add for future)

4

Step 4: Write both equations and solve using substitution or elimination

5

Step 5: Verify your solution by checking both original clues

6

Step 6: Answer the specific question asked (present age, future age, or past age)

Pro Strategy: Always define the present ages first, then express past and future ages as variations of present ages. Use one variable when a direct relationship exists between the two persons.

Example Problem

Example: A is twice as old as B. Five years ago, A was three times as old as B. Find their present ages. Solution: Step 1: Let B's age = x, then A's age = 2x Step 2: Five years ago: (2x - 5) = 3(x - 5) Step 3: 2x - 5 = 3x - 15 → 2x - 3x = -15 + 5 → -x = -10 → x = 10 Step 4: B = 10 years, A = 20 years Step 5: Check: Five years ago, A=15, B=5 → 15 is 3 times 5 ✓ Answer: A is 20 years old, B is 10 years old

Pro Tips & Tricks

  • Use a single variable when one age is expressed in terms of the other
  • For 'n years ago', subtract n from both ages in the equation
  • For 'n years later', add n to both ages in the equation
  • Write equations exactly as the statement reads before simplifying
  • Always check if ages are positive integers (reasonable age values)
  • Cross-verify by plugging answers back into both clues

Shortcut Methods to Solve Faster

Two clues with linear relationship always yield unique answers
If difference of ages is constant, use difference method: (ratio1 - ratio2) × years = key equation
For 'n years ago' problems, the equation structure is: (present age of first - n) = ratio × (present age of second - n)

Common Mistakes to Avoid

Forgetting to apply the time change to both persons
Using the wrong operation (addition instead of subtraction for past ages)
Not simplifying equations fully before solving
Assuming ages must be integers when not specified

Exam Importance

Two Clue Chain is an important topic for various competitive exams. Here's how frequently it appears:

SSC CGL
2-3 questions
BANKING PO
2-3 questions
RAILWAYS RRB
2-3 questions
CAT
1-2 questions
INSURANCE
2-3 questions

Ready to Master Two Clue Chain?

Start with Worksheet 1 and work your way up to expert level! Each worksheet includes:

20 practice questions
Detailed solutions
Step-by-step explanations
Start Practicing Now