Question 1
Tournament participants: Saurabh, Calvin, Samyukta, Bjorn
Given the following clues:
1. Saurabh is younger than Calvin
2. Calvin is younger than Samyukta
3. Samyukta is younger than Bjorn
4. Each person is exactly 3 years older than the person immediately younger than them.
5. Saurabh is 19 years old.
Determine Calvin's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Saurabh → Calvin → Samyukta → Bjorn
Step 2: From clue 4, each consecutive person differs by exactly 3 years.
So if youngest = x, then: Saurabh=x, Calvin=x+3, Samyukta=x+6, Bjorn=x+9
Step 3: From clue 5, Saurabh (the 1st (youngest)) = 19
Therefore, x + 0 = 19
Solving: x = 19 - 0 = 19
Step 4: All ages are:
• Saurabh = 19
• Calvin = 22
• Samyukta = 25
• Bjorn = 28
Step 5: Calvin is the 2nd.
Therefore, Calvin = 22
Saurabh → Calvin → Samyukta → Bjorn
Step 2: From clue 4, each consecutive person differs by exactly 3 years.
So if youngest = x, then: Saurabh=x, Calvin=x+3, Samyukta=x+6, Bjorn=x+9
Step 3: From clue 5, Saurabh (the 1st (youngest)) = 19
Therefore, x + 0 = 19
Solving: x = 19 - 0 = 19
Step 4: All ages are:
• Saurabh = 19
• Calvin = 22
• Samyukta = 25
• Bjorn = 28
Step 5: Calvin is the 2nd.
Therefore, Calvin = 22