Question 1
Tournament participants: Kritika, Eleanor, Dante, Hannah
Given the following clues:
1. Kritika is younger than Eleanor
2. Eleanor is younger than Dante
3. Dante is younger than Hannah
4. Each person is exactly 5 years older than the person immediately younger than them.
5. Dante is 28 years old.
Determine Kritika's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Kritika → Eleanor → Dante → Hannah
Step 2: From clue 4, each consecutive person differs by exactly 5 years.
So if youngest = x, then: Kritika=x, Eleanor=x+5, Dante=x+10, Hannah=x+15
Step 3: From clue 5, Dante (the 3rd) = 28
Therefore, x + 10 = 28
Solving: x = 28 - 10 = 18
Step 4: All ages are:
• Kritika = 18
• Eleanor = 23
• Dante = 28
• Hannah = 33
Step 5: Kritika is the 1st (youngest).
Therefore, Kritika = 18
Kritika → Eleanor → Dante → Hannah
Step 2: From clue 4, each consecutive person differs by exactly 5 years.
So if youngest = x, then: Kritika=x, Eleanor=x+5, Dante=x+10, Hannah=x+15
Step 3: From clue 5, Dante (the 3rd) = 28
Therefore, x + 10 = 28
Solving: x = 28 - 10 = 18
Step 4: All ages are:
• Kritika = 18
• Eleanor = 23
• Dante = 28
• Hannah = 33
Step 5: Kritika is the 1st (youngest).
Therefore, Kritika = 18