Age-Based Puzzles - Intermediate Level: sum ages INTERMEDIATE

Level up your age-based puzzles skills with this comprehensive review. 20 intermediate-level problems await in Worksheet 14 of 30. Focus area: sum ages. Learn family ages, generational puzzles, age sequencing through systematic practice. Designed for mid-level learners seeking moderate complexity with mixed patterns.

📝 Worksheet 14 of 30 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate level

What you'll learn in this worksheet:
Your progress through Age-Based Puzzles
Worksheet 14 of 30 (46% complete)

Question 1

Jai is 25 years older than Beau and is now 34 years old. How old was Jai 12 years ago?
Current age of Jai = 34
12 years ago = 34 - 12 = 22

Question 2

Manas is 3 times as old as Jitendra. 7 years ago, the sum of their ages was 66. How old is Jitendra now?
Let Jitendra = x, then Manas = 3x
7 years ago: (3x - 7) + (x - 7) = 66
(3+1)x - 14 = 66
(4)x = 80
x = 20

Question 3

The product of the ages of Divya and Mia is 252, and the sum of their ages is 32. Find Divya's age.
Let ages be x and y.
xy = 252
x + y = 32
Solving gives x = 14, y = 18
Therefore, Divya's age = 14

Question 4

If Ariana were 8 years younger, she would be 3/5 of Hannah's age 10 years from now. If Ariana is 24 years younger than Hannah, find Ariana's present age.
Let Hannah = 72, then Ariana = 48
Check: (48 - 8) = 3/5 × (72 + 10)
40 = 3/5 × 82 ✓

Question 5

In a family, Dhara : Parvathy = 5:3 and Parvathy : Kaylee = 4:1. The sum of their ages is 70. Find Parvathy's age.
Let common ratio for Parvathy be 12
Then Dhara:Parvathy:Kaylee = 20:12:3
Sum of ratios = 35
Each unit = 70 ÷ 35 = 2
Parvathy's age = 12 × 2 = 24

Question 6

10 years ago, the ratio of Vasudha's age to Dilip's age was 9:4. Currently, the ratio is 8:1. Find Vasudha's present age.
Let present ages be 8k and 1k
10 years ago: (8k-10)/(1k-10) = 9/4
Solving gives k = 10, so Vasudha = 80

Question 7

The product of the ages of Hazel, Vaishali, and Veena is 1600. The eldest is 2 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 2x
Then middle = 1600 ÷ (x × 2x) = 1600 ÷ (2x²)
Testing x = 8: middle = 1600 ÷ (2 × 8²) = 10
Therefore, eldest = 20

Question 8

In a family of four: Kennedy, Priya, Tanmay, Priyanka. The eldest is 27, youngest is 8. The average age is 18. What is the sum of the ages of the other two members?
Total sum = 18 × 4 = 72
Eldest + youngest = 27 + 8 = 35
Sum of other two = 72 - 35 = 37

Question 9

The product of the ages of Xena, Utkarsh, and Liam is 384. The eldest is 3 times the youngest, and the middle child's age is between them. Find the age of the eldest.
Let youngest = x, then eldest = 3x
Then middle = 384 ÷ (x × 3x) = 384 ÷ (3x²)
Testing x = 4: middle = 384 ÷ (3 × 4²) = 8
Therefore, eldest = 12

Question 10

The difference between Ajay and Kinsley's ages is 33 years. In 8 years, Ajay's age will be 2 times Kinsley's age. How old is Ajay now?
Let Kinsley = x = 25
Then Ajay = x + 33 = 25 + 33 = 58
Check: In 8 years, Ajay+8 = 66
2 × (Kinsley+8) = 2 × 33 = 66 ✓

Question 11

The average age of 5 people is 30. If Quinn (age 49) leaves and a new person joins, the average becomes 32. Find the age of the new person.
Initial total = 30 × 5 = 150
After Quinn leaves: 150 - 49 = 101
New total = 32 × 5 = 160
New person's age = 160 - (101) = 59

Question 12

The ratio of Eleanor's age to Sanjit's age is 4:13. After 32 years, the ratio will become 5:16. Find Eleanor's present age.
Let Eleanor = 4k, Sanjit = 13k
After 32 years: (4k+32)/(13k+32) = 5/16
Solving gives k = 12, so Eleanor = 48

Question 13

Thomas is 2 times as old as his son Sophie. After 5 years, the sum of their ages will be 52. How old is Sophie now?
Let son's age = x, then father's age = 2x
After 5 years: (2x+5) + (x+5) = 52
(2+1)x + 10 = 52
(3)x = 42
x = 14

Question 14

Freya is 3 times as old as Sarita. 6 years ago, the sum of their ages was 48. How old is Sarita now?
Let Sarita = x, then Freya = 3x
6 years ago: (3x - 6) + (x - 6) = 48
(3+1)x - 12 = 48
(4)x = 60
x = 15

Question 15

In a family, Caleb : Mridul = 7:4 and Mridul : Willow = 3:1. The sum of their ages is 111. Find Mridul's age.
Let common ratio for Mridul be 12
Then Caleb:Mridul:Willow = 21:12:4
Sum of ratios = 37
Each unit = 111 ÷ 37 = 3
Mridul's age = 12 × 3 = 36

Question 16

Owen and Vivian are twins. If Owen is 15 years old now, how old was Vivian 6 years ago?
Twins have the same age. 6 years ago, both were 15 - 6 = 9

Question 17

Sunil is twice as old as Dante was 8 years ago. The difference between their ages is 15 years. How old is Sunil?
Let Dante's current age = x
Then 8 years ago, Dante was (x - 8)
Sunil = 2(x - 8) = 2x - 16
Difference: Sunil - x = (2x - 16) - x = x - 16
Given difference = 15
So x - 16 = 15 → x = 31 = 31
Then Sunil = 2(31 - 8) = 46

Question 18

The average age of 6 people is 36. If Jitendra (age 27) leaves and a new person joins, the average becomes 40. Find the age of the new person.
Initial total = 36 × 6 = 216
After Jitendra leaves: 216 - 27 = 189
New total = 40 × 6 = 240
New person's age = 240 - (189) = 51

Question 19

Katia is 24 years old and Adam is 32 years old. What will be their combined age after 7 years?
Katia will be 24 + 7 = 31
Adam will be 32 + 7 = 39
Combined = 31 + 39 = 70

Question 20

Tyler is 45 years older than Ishwar and is now 54 years old. How old was Tyler 11 years ago?
Current age of Tyler = 54
11 years ago = 54 - 11 = 43
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