Age-Based Puzzles - Intermediate Level: ratio ages INTERMEDIATE

Exam-focused quick response training β˜… worksheet: 20 intermediate-level age-based puzzles questions. Worksheet 13 of 30 targets ratio ages. Build proficiency in age-based logic, family ages, generational puzzles with detailed solutions. Ideal for mid-level competitive exam preparation.

πŸ“ Worksheet 13 of 30 β€’ 20 questions β€’ ⏱️ Estimated time: 20 minutes β€’ 🎯 Intermediate level

What you'll learn in this worksheet:
Your progress through Age-Based Puzzles
Worksheet 13 of 30 (43% complete)

Question 1

Bela is 35 years older than Nora and is now 49 years old. How old was Bela 7 years ago?
Current age of Bela = 49
7 years ago = 49 - 7 = 42

Question 2

Emmett is 2 times as old as Nimesh. 5 years ago, the sum of their ages was 35. How old is Nimesh now?
Let Nimesh = x, then Emmett = 2x
5 years ago: (2x - 5) + (x - 5) = 35
(2+1)x - 10 = 35
(3)x = 45
x = 15

Question 3

In a family of four: Ramesh, Kamini, Anthony, Mason. The eldest is 21, youngest is 5. The average age is 13. What is the sum of the ages of the other two members?
Total sum = 13 Γ— 4 = 52
Eldest + youngest = 21 + 5 = 26
Sum of other two = 52 - 26 = 26

Question 4

Ajay is 29 years old and Brooklyn is 16 years old. What will be the sum of their ages after 10 years?
Current sum = 29 + 16 = 45
After 10 years, each ages by 10, so sum increases by 20
Future sum = 45 + 20 = 65

Question 5

If Jivika were 7 years younger, she would be 2/5 of Bhavna's age 5 years from now. If Jivika is 7 years younger than Bhavna, find Jivika's present age.
Let Bhavna = 35, then Jivika = 28
Check: (28 - 7) = 2/5 Γ— (35 + 5)
21 = 2/5 Γ— 40 βœ“

Question 6

The average age of a family of 5 members (Laksh, Bentley, Leon, Pallavi, Eleanor) is 37.6 years. If Pallavi (age 44) leaves the family, what will be the new average age?
Total age = 37.6 Γ— 5 = 188
After Pallavi leaves: 188 - 44 = 144
New average = 144 Γ· 4 = 36

Question 7

3 years ago, the ratio of Deepak's age to Surbhi's age was 3:4. 6 years from now, the ratio will be 4:5. Find Deepak's present age.
Let Deepak's present age = x, Surbhi's present age = y
3 years ago: (x-3)/(y-3) = 3/4
6 years from now: (x+6)/(y+6) = 4/5
Solving these equations gives x = 9, y = 12

Question 8

In a family of four: Ethan, Chetan, Emmett, Anu. The eldest is 34, youngest is 5. The average age is 24. What is the sum of the ages of the other two members?
Total sum = 24 Γ— 4 = 96
Eldest + youngest = 34 + 5 = 39
Sum of other two = 96 - 39 = 57

Question 9

Tournament participants: Hailey, Lars, Dante, Michael Given the following clues: 1. Hailey is younger than Lars 2. Lars is younger than Dante 3. Dante is younger than Michael 4. Each person is exactly 3 years older than the person immediately younger than them. 5. Dante is 30 years old. Determine Michael's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Hailey β†’ Lars β†’ Dante β†’ Michael

Step 2: From clue 4, each consecutive person differs by exactly 3 years.
So if youngest = x, then: Hailey=x, Lars=x+3, Dante=x+6, Michael=x+9

Step 3: From clue 5, Dante (the 3rd) = 30
Therefore, x + 6 = 30
Solving: x = 30 - 6 = 24

Step 4: All ages are:
β€’ Hailey = 24
β€’ Lars = 27
β€’ Dante = 30
β€’ Michael = 33

Step 5: Michael is the 4th (oldest).
Therefore, Michael = 33

Question 10

When Arthur was born, Chaitra was 4 years old. The sum of their present ages is 40. Find Arthur's age when Arthur was half of Chaitra's age (this will happen 14 years ago).
Let Arthur's current age = 18, Chaitra's current age = 22
Given: When Arthur was born (0 years old), Chaitra was 4 years old.
Therefore, Chaitra is always 4 years older than Arthur.
So 22 = 18 + 4 βœ“

Condition: Find t such that Arthur's age = Β½ of Chaitra's age
Equation: 18 + t = Β½(22 + t)
Multiply both sides by 2: 218 + 2t = 22 + t
Simplify: 218 + 2t - t = 22
218 + t = 22
t = 22 - 218
t = 22 - 36 = -14

At that time, Arthur's age = 18 + -14 = 4
Verification: When Arthur is 4, Chaitra is 8 = 8
Check: Is 4 = Β½ Γ— 8? Β½ Γ— 8 = 4.0 βœ“

Note: Mathematically, this always equals the age difference (4) because:
event_age = current_a + t = current_a + (current_b - 2Β·current_a) = current_b - current_a = age_diff

Question 11

Tournament participants: Cora, Suman, Gargi, Naman Given the following clues: 1. Cora is younger than Suman 2. Suman is younger than Gargi 3. Gargi is younger than Naman 4. Each person is exactly 5 years older than the person immediately younger than them. 5. Naman is 31 years old. Determine Suman's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Cora β†’ Suman β†’ Gargi β†’ Naman

Step 2: From clue 4, each consecutive person differs by exactly 5 years.
So if youngest = x, then: Cora=x, Suman=x+5, Gargi=x+10, Naman=x+15

Step 3: From clue 5, Naman (the 4th (oldest)) = 31
Therefore, x + 15 = 31
Solving: x = 31 - 15 = 16

Step 4: All ages are:
β€’ Cora = 16
β€’ Suman = 21
β€’ Gargi = 26
β€’ Naman = 31

Step 5: Suman is the 2nd.
Therefore, Suman = 21

Question 12

Tournament participants: Hans, Jaxson, Paisley, Peter Given the following clues: 1. Hans is younger than Jaxson 2. Jaxson is younger than Paisley 3. Paisley is younger than Peter 4. Each person is exactly 3 years older than the person immediately younger than them. 5. Jaxson is 27 years old. Determine Paisley's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Hans β†’ Jaxson β†’ Paisley β†’ Peter

Step 2: From clue 4, each consecutive person differs by exactly 3 years.
So if youngest = x, then: Hans=x, Jaxson=x+3, Paisley=x+6, Peter=x+9

Step 3: From clue 5, Jaxson (the 2nd) = 27
Therefore, x + 3 = 27
Solving: x = 27 - 3 = 24

Step 4: All ages are:
β€’ Hans = 24
β€’ Jaxson = 27
β€’ Paisley = 30
β€’ Peter = 33

Step 5: Paisley is the 3rd.
Therefore, Paisley = 30

Question 13

In a family of four: Mike, Ishan, Rakshit, Nikolai. The eldest is 36, youngest is 7. The average age is 26. What is the sum of the ages of the other two members?
Total sum = 26 Γ— 4 = 104
Eldest + youngest = 36 + 7 = 43
Sum of other two = 104 - 43 = 61

Question 14

12 years ago, the ratio of John's age to Kamini's age was 3:5. 24 years from now, the ratio will be 2:3. Find John's present age.
Let John's present age = x, Kamini's present age = y
12 years ago: (x-12)/(y-12) = 3/5
24 years from now: (x+24)/(y+24) = 2/3
Solving these equations gives x = 36, y = 60

Question 15

Lakshmi and Brandon are twins. If Lakshmi is 13 years old now, how old was Brandon 4 years ago?
Twins have the same age. 4 years ago, both were 13 - 4 = 9

Question 16

Elizabeth is half as old as Noah was when Elizabeth was 10 years old. If Noah is now 44 years old, find Elizabeth's current age.
When Elizabeth was 10 years old, that was 14 years ago
At that time, Noah was 44 - 14 = 30 years old
Now Elizabeth is half of 30
Therefore, Elizabeth's current age = 30 Γ· 2 = 15

Question 17

Gaurav is 29 years old and Ashwin is 12 years old. What will be their combined age after 9 years?
Gaurav will be 29 + 9 = 38
Ashwin will be 12 + 9 = 21
Combined = 38 + 21 = 59

Question 18

Four people: Saurabh, Divya, Bjorn, Max Given: 1. The sum of all four ages is 118 2. Saurabh + Divya = 42 3. Max is 10 years older than Bjorn 4. Saurabh is 17 years old Find Bjorn's age.
Step 1: From clue 4, Saurabh = 17

Step 2: Using clue 2, we can find the other person in that pair

Step 3: Using clue 3 and clue 1, we can determine all ages

Step 4: Therefore, Bjorn = 33

Complete ages: Saurabh=17, Divya=25, Bjorn=33, Max=43

Question 19

Riddhima is 3/11 of Chetan's age. After 22 years, Riddhima will be 2/7 of Chetan's age. Find Riddhima's present age.
Let Chetan = x, then Riddhima = 3/11x
After 22 years: 3/11x + 22 = 2/7(x + 22)
Solving gives x = 110, so Riddhima = 30

Question 20

Chandan is twice as old as Omar was when Saloni was as old as Chandan is now. If Saloni is currently 18 years old, find Chandan's age.
When Saloni was 22 years old, that was 4 years ago
At that time, Omar was 11
Now Chandan = 2 Γ— 11 = 22 βœ“
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