Age-Based Puzzles - Beginner-Intermediate Level: age sequencing BEGINNER-INTERMEDIATE

Strategic fast track practice for age-based puzzles: 20 beginner-intermediate-level problems. Worksheet 9 of 30 - Focus: age sequencing. Develop expertise in age puzzles, relative ages, age constraints with step-by-step solutions. Ideal for developing learners targeting building on fundamentals with moderate challenges.

📝 Worksheet 9 of 30 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner-intermediate level

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Your progress through Age-Based Puzzles
Worksheet 9 of 30 (30% complete)

Question 1

In a family, Hudson : Ajay = 5:4 and Ajay : Chandan = 3:1. The sum of their ages is 124. Find Ajay's age.
Let common ratio for Ajay be 12
Then Hudson:Ajay:Chandan = 15:12:4
Sum of ratios = 31
Each unit = 124 ÷ 31 = 4
Ajay's age = 12 × 4 = 48

Question 2

If Soren were 6 years younger, she would be 2/7 of Ishaan's age 7 years from now. If Soren is 32 years younger than Ishaan, find Soren's present age.
Let Ishaan = 56, then Soren = 24
Check: (24 - 6) = 2/7 × (56 + 7)
18 = 2/7 × 63 ✓

Question 3

11 years ago, the ratio of Ritu's age to Brielle's age was 3:8. 22 years from now, the ratio will be 4:11. Find Ritu's present age.
Let Ritu's present age = x, Brielle's present age = y
11 years ago: (x-11)/(y-11) = 3/8
22 years from now: (x+22)/(y+22) = 4/11
Solving these equations gives x = 33, y = 88

Question 4

In a family, Rakshit : Valentina = 7:3 and Valentina : Piper = 4:1. The sum of their ages is 172. Find Valentina's age.
Let common ratio for Valentina be 12
Then Rakshit:Valentina:Piper = 28:12:3
Sum of ratios = 43
Each unit = 172 ÷ 43 = 4
Valentina's age = 12 × 4 = 48

Question 5

In a family of four: Prateek, Meena, Sohan, Siddharth. The youngest is 10 and the eldest is 20. The other two members are 14 and 16. What is the average age of the family?
Sum of all ages = 10 + 14 + 16 + 20 = 60
Average = 60 ÷ 4 = 15

Question 6

If Sadie were 6 years younger, she would be 3/8 of Priya's age 4 years from now. If Sadie is 6 years younger than Priya, find Sadie's present age.
Let Priya = 30, then Sadie = 24
Check: (24 - 6) = 3/8 × (30 + 4)
18 = 3/8 × 34 ✓

Question 7

Austin is half as old as Natalie was when Austin was 11 years old. If Natalie is now 39 years old, find Austin's current age.
When Austin was 11 years old, that was 13 years ago
At that time, Natalie was 39 - 13 = 26 years old
Now Austin is half of 26
Therefore, Austin's current age = 26 ÷ 2 = 13

Question 8

12 years ago, the ratio of Cole's age to Kunal's age was 4:9. 24 years from now, the ratio will be 5:12. Find Cole's present age.
Let Cole's present age = x, Kunal's present age = y
12 years ago: (x-12)/(y-12) = 4/9
24 years from now: (x+24)/(y+24) = 5/12
Solving these equations gives x = 36, y = 108

Question 9

The average age of a family of 4 members (Vijay, Zoya, Rahul, Prasanna) is 38.2 years. If Prasanna (age 57) leaves the family, what will be the new average age?
Total age = 38.2 × 4 = 153
After Prasanna leaves: 153 - 57 = 96
New average = 96 ÷ 3 = 32

Question 10

In a family of four: Gajendra, Sudhir, Kamini, Rajiv. The eldest is 43, youngest is 14. The average age is 33. What is the sum of the ages of the other two members?
Total sum = 33 × 4 = 132
Eldest + youngest = 43 + 14 = 57
Sum of other two = 132 - 57 = 75

Question 11

Matteo is 15 years old and Shlok is 15 years old. What will be the sum of their ages after 5 years?
Current sum = 15 + 15 = 30
After 5 years, each ages by 5, so sum increases by 10
Future sum = 30 + 10 = 40

Question 12

Tournament participants: Vandana, Nirmala, Varun, Arjun Given the following clues: 1. Vandana is younger than Nirmala 2. Nirmala is younger than Varun 3. Varun is younger than Arjun 4. Each person is exactly 5 years older than the person immediately younger than them. 5. Vandana is 20 years old. Determine Nirmala's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Vandana → Nirmala → Varun → Arjun

Step 2: From clue 4, each consecutive person differs by exactly 5 years.
So if youngest = x, then: Vandana=x, Nirmala=x+5, Varun=x+10, Arjun=x+15

Step 3: From clue 5, Vandana (the 1st (youngest)) = 20
Therefore, x + 0 = 20
Solving: x = 20 - 0 = 20

Step 4: All ages are:
• Vandana = 20
• Nirmala = 25
• Varun = 30
• Arjun = 35

Step 5: Nirmala is the 2nd.
Therefore, Nirmala = 25

Question 13

Kashish is twice as old as Chandan was when Rachit was as old as Kashish is now. If Rachit is currently 62 years old, find Kashish's age.
When Rachit was 70 years old, that was 8 years ago
At that time, Chandan was 35
Now Kashish = 2 × 35 = 70 ✓

Question 14

In a family of four: Madhav, Ishwar, Shakti, Raul. The youngest is 9 and the eldest is 27. The other two members are 16 and 20. What is the average age of the family?
Sum of all ages = 9 + 16 + 20 + 27 = 72
Average = 72 ÷ 4 = 18

Question 15

The average age of 4 people is 28. If Mitali (age 34) leaves and a new person joins, the average becomes 32. Find the age of the new person.
Initial total = 28 × 4 = 112
After Mitali leaves: 112 - 34 = 78
New total = 32 × 4 = 128
New person's age = 128 - (78) = 50

Question 16

Dinesh is 14 years old and Kapil is 28 years old. What will be their combined age after 11 years?
Dinesh will be 14 + 11 = 25
Kapil will be 28 + 11 = 39
Combined = 25 + 39 = 64

Question 17

The ratio of Udit's age to Bela's age is 4:11. After 28 years, the ratio will become 5:14. Find Udit's present age.
Let Udit = 4k, Bela = 11k
After 28 years: (4k+28)/(11k+28) = 5/14
Solving gives k = 10, so Udit = 40

Question 18

6 years ago, the ratio of Oscar's age to Sakshi's age was 1:3. 12 years from now, the ratio will be 2:5. Find Oscar's present age.
Let Oscar's present age = x, Sakshi's present age = y
6 years ago: (x-6)/(y-6) = 1/3
12 years from now: (x+12)/(y+12) = 2/5
Solving these equations gives x = 12, y = 36

Question 19

Tournament participants: Joseph, Sonal, Sushma, Abigail Given the following clues: 1. Joseph is younger than Sonal 2. Sonal is younger than Sushma 3. Sushma is younger than Abigail 4. Each person is exactly 5 years older than the person immediately younger than them. 5. Abigail is 40 years old. Determine Sonal's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Joseph → Sonal → Sushma → Abigail

Step 2: From clue 4, each consecutive person differs by exactly 5 years.
So if youngest = x, then: Joseph=x, Sonal=x+5, Sushma=x+10, Abigail=x+15

Step 3: From clue 5, Abigail (the 4th (oldest)) = 40
Therefore, x + 15 = 40
Solving: x = 40 - 15 = 25

Step 4: All ages are:
• Joseph = 25
• Sonal = 30
• Sushma = 35
• Abigail = 40

Step 5: Sonal is the 2nd.
Therefore, Sonal = 30

Question 20

In a family, Saloni : Lucy = 5:3 and Lucy : Sonal = 4:1. The sum of their ages is 105. Find Lucy's age.
Let common ratio for Lucy be 12
Then Saloni:Lucy:Sonal = 20:12:3
Sum of ratios = 35
Each unit = 105 ÷ 35 = 3
Lucy's age = 12 × 3 = 36
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