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Age-Based Puzzles - Beginner-Intermediate Level: generational puzzles BEGINNER-INTERMEDIATE

Comprehensive race against clock worksheet covering 20 beginner-intermediate-level age-based puzzles problems. Worksheet 8 of 30 emphasizes generational puzzles. Master age comparison, age puzzles, relative ages through detailed explanations. Difficulty: building on fundamentals with moderate challenges. Tailored for developing preparation.

📝 Worksheet 8 of 30 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner-intermediate level

What you'll learn in this worksheet:
Your progress through Age-Based Puzzles
Worksheet 8 of 30 (26% complete)

Question 1

Tournament participants: Naman, Shreya, Samyukta, Anu Given the following clues: 1. Naman is younger than Shreya 2. Shreya is younger than Samyukta 3. Samyukta is younger than Anu 4. Each person is exactly 5 years older than the person immediately younger than them. 5. Anu is 39 years old. Determine Shreya's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Naman → Shreya → Samyukta → Anu

Step 2: From clue 4, each consecutive person differs by exactly 5 years.
So if youngest = x, then: Naman=x, Shreya=x+5, Samyukta=x+10, Anu=x+15

Step 3: From clue 5, Anu (the 4th (oldest)) = 39
Therefore, x + 15 = 39
Solving: x = 39 - 15 = 24

Step 4: All ages are:
• Naman = 24
• Shreya = 29
• Samyukta = 34
• Anu = 39

Step 5: Shreya is the 2nd.
Therefore, Shreya = 29
ranking

Question 2

10 years ago, the ratio of Nira's age to Hari's age was 2:5. 20 years from now, the ratio will be 3:7. Find Nira's present age.
Let Nira's present age = x, Hari's present age = y
10 years ago: (x-10)/(y-10) = 2/5
20 years from now: (x+20)/(y+20) = 3/7
Solving these equations gives x = 30, y = 75
ratio, past-future, equation

Question 3

Jaya is 4/11 of Neha's age. After 22 years, Jaya will be 2/5 of Neha's age. Find Jaya's present age.
Let Neha = x, then Jaya = 4/11x
After 22 years: 4/11x + 22 = 2/5(x + 22)
Solving gives x = 88, so Jaya = 32
fraction, ratio

Question 4

When Gaurav was born, Amara was 25 years old. The sum of their present ages is 83. Find Gaurav's age when Gaurav was half of Amara's age (this will happen 4 years ago).
Let Gaurav's current age = 29, Amara's current age = 54
Given: When Gaurav was born (0 years old), Amara was 25 years old.
Therefore, Amara is always 25 years older than Gaurav.
So 54 = 29 + 25 ✓

Condition: Find t such that Gaurav's age = ½ of Amara's age
Equation: 29 + t = ½(54 + t)
Multiply both sides by 2: 229 + 2t = 54 + t
Simplify: 229 + 2t - t = 54
229 + t = 54
t = 54 - 229
t = 54 - 58 = -4

At that time, Gaurav's age = 29 + -4 = 25
Verification: When Gaurav is 25, Amara is 50 = 50
Check: Is 25 = ½ × 50? ½ × 50 = 25.0 ✓

Note: Mathematically, this always equals the age difference (25) because:
event_age = current_a + t = current_a + (current_b - 2·current_a) = current_b - current_a = age_diff
event

Question 5

In a family of four: Jasper, Nirmala, Vijay, Kinsley. The eldest is 39, youngest is 10. The average age is 30. What is the sum of the ages of the other two members?
Total sum = 30 × 4 = 120
Eldest + youngest = 39 + 10 = 49
Sum of other two = 120 - 49 = 71
avg_diff

Question 6

10 years ago, the ratio of Chandan's age to Penelope's age was 1:5. 20 years from now, the ratio will be 2:9. Find Chandan's present age.
Let Chandan's present age = x, Penelope's present age = y
10 years ago: (x-10)/(y-10) = 1/5
20 years from now: (x+20)/(y+20) = 2/9
Solving these equations gives x = 20, y = 100
ratio, past-future, equation

Question 7

The difference between Varun and Gauri's ages is 31 years. In 7 years, Varun's age will be 2 times Gauri's age. How old is Varun now?
Let Gauri = x = 24
Then Varun = x + 31 = 24 + 31 = 55
Check: In 7 years, Varun+7 = 62
2 × (Gauri+7) = 2 × 31 = 62 ✓
diff_mult

Question 8

The ratio of Phalguni's age to Bhaskar's age is 2:3. After 6 years, the ratio will become 3:4. Find Phalguni's present age.
Let Phalguni = 2k, Bhaskar = 3k
After 6 years: (2k+6)/(3k+6) = 3/4
Solving gives k = 6, so Phalguni = 12
ratio, future

Question 9

The average age of a family of 6 members (Levi, Marcus, Somesh, Neeraj, Gunjan, Rishi) is 27.5 years. If Marcus (age 25) leaves the family, what will be the new average age?
Total age = 27.5 × 6 = 165
After Marcus leaves: 165 - 25 = 140
New average = 140 ÷ 5 = 28
average, removal

Question 10

Kalpana is 3 times as old as Rakhi. 4 years ago, the sum of their ages was 56. How old is Rakhi now?
Let Rakhi = x, then Kalpana = 3x
4 years ago: (3x - 4) + (x - 4) = 56
(3+1)x - 8 = 56
(4)x = 64
x = 16
ratio_sum

Question 11

Aditi is 39 years older than Ranveer and is now 55 years old. How old was Aditi 7 years ago?
Current age of Aditi = 55
7 years ago = 55 - 7 = 48
reverse

Question 12

12 years ago, the ratio of Arthur's age to Drishti's age was 4:5. 24 years from now, the ratio will be 5:6. Find Arthur's present age.
Let Arthur's present age = x, Drishti's present age = y
12 years ago: (x-12)/(y-12) = 4/5
24 years from now: (x+24)/(y+24) = 5/6
Solving these equations gives x = 48, y = 60
ratio, past-future, equation

Question 13

Shreya is 3/4 of Shivani's age. After 8 years, Shreya will be 4/5 of Shivani's age. Find Shreya's present age.
Let Shivani = x, then Shreya = 3/4x
After 8 years: 3/4x + 8 = 4/5(x + 8)
Solving gives x = 32, so Shreya = 24
fraction, ratio

Question 14

In a family of four: Audrey, Sanjay, Gargi, Raelynn. The eldest is 38, youngest is 11. The average age is 26. What is the sum of the ages of the other two members?
Total sum = 26 × 4 = 104
Eldest + youngest = 38 + 11 = 49
Sum of other two = 104 - 49 = 55
avg_diff

Question 15

The sum of ages of Dilip, Andre, and Lisa is 56. Their ages are in the ratio 3:3:2. How old is Andre?
Sum of ratios = 3 + 3 + 2 = 8
Each unit = 56 ÷ 8 = 7
Andre's ratio = 3
Age = 3 × 7 = 21
sum, ratio

Question 16

If Durga were 8 years younger, she would be 1/2 of Justin's age 8 years from now. If Durga is 24 years younger than Justin, find Durga's present age.
Let Justin = 56, then Durga = 32
Check: (32 - 8) = 1/2 × (56 + 8)
24 = 1/2 × 64 ✓
conditional, fraction

Question 17

Four people: Shlok, Vandana, William, Hana Given: 1. The sum of all four ages is 152 2. Shlok + Vandana = 62 3. Hana is 6 years older than William 4. William is 42 years old Find Vandana's age.
Step 1: From clue 4, William = 42

Step 2: Using clue 2, we can find the other person in that pair

Step 3: Using clue 3 and clue 1, we can determine all ages

Step 4: Therefore, Vandana = 37

Complete ages: Shlok=25, Vandana=37, William=42, Hana=48
grid_logic

Question 18

Tournament participants: Alexander, Shashi, Rani, Cora Given the following clues: 1. Alexander is younger than Shashi 2. Shashi is younger than Rani 3. Rani is younger than Cora 4. Each person is exactly 3 years older than the person immediately younger than them. 5. Alexander is 19 years old. Determine Shashi's age.
Step 1: From clues 1-3, the age order from youngest to oldest is:
Alexander → Shashi → Rani → Cora

Step 2: From clue 4, each consecutive person differs by exactly 3 years.
So if youngest = x, then: Alexander=x, Shashi=x+3, Rani=x+6, Cora=x+9

Step 3: From clue 5, Alexander (the 1st (youngest)) = 19
Therefore, x + 0 = 19
Solving: x = 19 - 0 = 19

Step 4: All ages are:
• Alexander = 19
• Shashi = 22
• Rani = 25
• Cora = 28

Step 5: Shashi is the 2nd.
Therefore, Shashi = 22
ranking

Question 19

In a family of four: Alice, Raul, Lucas, Rishabh. The eldest is 31, youngest is 15. The average age is 25. What is the sum of the ages of the other two members?
Total sum = 25 × 4 = 100
Eldest + youngest = 31 + 15 = 46
Sum of other two = 100 - 46 = 54
avg_diff

Question 20

In a family of four: Jatin, Shivam, Vipul, Anu. The eldest is 35, youngest is 15. The average age is 27. What is the sum of the ages of the other two members?
Total sum = 27 × 4 = 108
Eldest + youngest = 35 + 15 = 50
Sum of other two = 108 - 50 = 58
avg_diff
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