Question 1
When Sneha was born, Paridhi was 22 years old. The sum of their present ages is 60. Find Sneha's age when Sneha was half of Paridhi's age (this will happen in 3 years).
Let Sneha's current age = 19, Paridhi's current age = 41
Given: When Sneha was born (0 years old), Paridhi was 22 years old.
Therefore, Paridhi is always 22 years older than Sneha.
So 41 = 19 + 22 ✓
Condition: Find t such that Sneha's age = ½ of Paridhi's age
Equation: 19 + t = ½(41 + t)
Multiply both sides by 2: 219 + 2t = 41 + t
Simplify: 219 + 2t - t = 41
219 + t = 41
t = 41 - 219
t = 41 - 38 = 3
At that time, Sneha's age = 19 + 3 = 22
Verification: When Sneha is 22, Paridhi is 44 = 44
Check: Is 22 = ½ × 44? ½ × 44 = 22.0 ✓
Note: Mathematically, this always equals the age difference (22) because:
event_age = current_a + t = current_a + (current_b - 2·current_a) = current_b - current_a = age_diff
Given: When Sneha was born (0 years old), Paridhi was 22 years old.
Therefore, Paridhi is always 22 years older than Sneha.
So 41 = 19 + 22 ✓
Condition: Find t such that Sneha's age = ½ of Paridhi's age
Equation: 19 + t = ½(41 + t)
Multiply both sides by 2: 219 + 2t = 41 + t
Simplify: 219 + 2t - t = 41
219 + t = 41
t = 41 - 219
t = 41 - 38 = 3
At that time, Sneha's age = 19 + 3 = 22
Verification: When Sneha is 22, Paridhi is 44 = 44
Check: Is 22 = ½ × 44? ½ × 44 = 22.0 ✓
Note: Mathematically, this always equals the age difference (22) because:
event_age = current_a + t = current_a + (current_b - 2·current_a) = current_b - current_a = age_diff