Question 1
When Karthik was born, Satish was 16 years old. The sum of their present ages is 26. Find Karthik's age when Karthik was half of Satish's age (this will happen in 11 years).
Let Karthik's current age = 5, Satish's current age = 21
Given: When Karthik was born (0 years old), Satish was 16 years old.
Therefore, Satish is always 16 years older than Karthik.
So 21 = 5 + 16 ✓
Condition: Find t such that Karthik's age = ½ of Satish's age
Equation: 5 + t = ½(21 + t)
Multiply both sides by 2: 25 + 2t = 21 + t
Simplify: 25 + 2t - t = 21
25 + t = 21
t = 21 - 25
t = 21 - 10 = 11
At that time, Karthik's age = 5 + 11 = 16
Verification: When Karthik is 16, Satish is 32 = 32
Check: Is 16 = ½ × 32? ½ × 32 = 16.0 ✓
Note: Mathematically, this always equals the age difference (16) because:
event_age = current_a + t = current_a + (current_b - 2·current_a) = current_b - current_a = age_diff
Given: When Karthik was born (0 years old), Satish was 16 years old.
Therefore, Satish is always 16 years older than Karthik.
So 21 = 5 + 16 ✓
Condition: Find t such that Karthik's age = ½ of Satish's age
Equation: 5 + t = ½(21 + t)
Multiply both sides by 2: 25 + 2t = 21 + t
Simplify: 25 + 2t - t = 21
25 + t = 21
t = 21 - 25
t = 21 - 10 = 11
At that time, Karthik's age = 5 + 11 = 16
Verification: When Karthik is 16, Satish is 32 = 32
Check: Is 16 = ½ × 32? ½ × 32 = 16.0 ✓
Note: Mathematically, this always equals the age difference (16) because:
event_age = current_a + t = current_a + (current_b - 2·current_a) = current_b - current_a = age_diff