Question 1
If vowels = @, even position consonants = #, odd position consonants = *, then 'NETWORK' = ?
Position-wise coding: N(pos 1, even)→#, E(vowel)→@, T(pos 3, even)→#, W(pos 4, odd)→*, O(vowel)→@, R(pos 6, odd)→*, K(pos 7, even)→# = #@#*@*#