Question 1
If vowels = @, even position consonants = #, odd position consonants = *, then 'KEYBOARD' = ?
Position-wise coding: K(pos 1, even)β#, E(vowel)β@, Y(pos 3, even)β#, B(pos 4, odd)β*, O(vowel)β@, A(vowel)β@, R(pos 7, even)β#, D(pos 8, odd)β* = #@#*@@#*