Circular Arrangement Ranking

Circular Arrangement Ranking problems involve persons seated in a circle. Unlike a linear row, there are two paths between any two persons (clockwise and anticlockwise). You must find the minimum number of persons between them, considering both directions. These problems test your spatial reasoning in circular arrangements.

10Worksheets
200+Practice Questions
HardDifficulty
2-3 hoursHours to Master

Introduction to Circular Arrangement Ranking

Circular Arrangement Ranking problems involve persons seated in a circle. Unlike a linear row, there are two paths between any two persons (clockwise and anticlockwise). You must find the minimum number of persons between them, considering both directions. These problems test your spatial reasoning in circular arrangements.

Prerequisites

Understanding of circular arrangements Clockwise and anticlockwise directions Distance calculation in circle Minimum path selection
Why This Matters: Circular Arrangement Ranking problems appear in 1-2 questions in Banking PO and SSC CGL exams. They test circular reasoning skills.

How to Solve Circular Arrangement Ranking Problems

1

Step 1: Identify total number of persons and positions of the two persons

2

Step 2: Calculate clockwise distance = (pos2 - pos1) mod total

3

Step 3: Calculate anticlockwise distance = total - clockwise distance

4

Step 4: Persons between clockwise = clockwise distance - 1

5

Step 5: Persons between anticlockwise = anticlockwise distance - 1

6

Step 6: Minimum persons between = min(clockwise - 1, anticlockwise - 1)

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Step 7: Ensure the result is non-negative

Pro Strategy: In a circle, always consider both directions. The number of persons between them is the smaller of the two distances minus 1. Positions can be numbered clockwise from 1 to N.

Example Problem

Example: 12 persons sit around a circle numbered 1-12 clockwise. A is at position 3, B is at position 8. Minimum persons between them? Solution: Step 1: Total = 12, posA = 3, posB = 8 Step 2: Clockwise from A to B: 8 - 3 = 5 steps Step 3: Anticlockwise: 12 - 5 = 7 steps Step 4: Persons between clockwise = 5 - 1 = 4 Step 5: Persons between anticlockwise = 7 - 1 = 6 Step 6: Minimum = min(4, 6) = 4 Answer: 4 persons

Pro Tips & Tricks

  • Clockwise distance = (pos2 - pos1) mod N (using 1-indexed positions)
  • Anticlockwise distance = N - clockwise distance
  • Persons between = distance - 1
  • If distance = 0, persons are at same position
  • If distance = 1, persons are adjacent (0 between)
  • The sum of clockwise and anticlockwise distances = N

Shortcut Methods to Solve Faster

Clockwise = (pos2 - pos1 + N) % N (with 0 meaning N)
Min persons between = min(clockwise, anticlockwise) - 1
Adjacent persons have min distance = 1, so 0 between

Common Mistakes to Avoid

Forgetting that circles have two paths
Not subtracting 1 from distance to get persons between
Using absolute difference without considering circular wrap-around
Assuming clockwise is always the shorter path

Exam Importance

Circular Arrangement Ranking is an important topic for various competitive exams. Here's how frequently it appears:

SSC CGL
1-2 questions
BANKING PO
1-2 questions
RAILWAYS RRB
1-2 questions
CAT
1-2 questions
INSURANCE
1-2 questions

Ready to Master Circular Arrangement Ranking?

Start with Worksheet 1 and work your way up to expert level! Each worksheet includes:

20 practice questions
Detailed solutions
Step-by-step explanations
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