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Number-Letter Codes - Expert Level: product codes EXPERT

Comprehensive self assessment worksheet covering 20 expert-level number-letter codes problems. Worksheet 28 of 30 emphasizes product codes. Master alphabet numbering, code conversion, dual coding through detailed explanations. Difficulty: challenging problems and time-bound practice. Tailored for expert-level preparation.

📝 Worksheet 28 of 30 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Expert level

What you'll learn in this worksheet:
Your progress through Number-Letter Codes
Worksheet 28 of 30 (93% complete)

Question 1

For 'EGG', odd positions use shift coding, even positions use shift coding. What is the result?
Alternating coding: E→G(+2), G→I(+2), G→I(+2) → GII
alternating, mixed, advanced

Question 2

If A=26, B=25, C=24... Z=1 (reverse order), then 'ANT' is coded as?
Reverse coding: A=26 + N=13 + T=7 → concatenated = 26137
reverse, sequence

Question 3

If letters are coded as 5-bit binary (A=1=00001, B=2=00010...), 'ABC' is coded as?
Binary coding: A=1=00001, B=2=00010, C=3=00011 → concatenated = 000010001000011
binary, advanced

Question 4

If letters are coded as 5-bit binary (A=1=00001, B=2=00010...), 'FISH' is coded as?
Binary coding: F=6=00110, I=9=01001, S=19=10011, H=8=01000 → concatenated = 00110010011001101000
binary, advanced

Question 5

If letters are coded as (position mod 7), 'PYTHON' becomes?
Modular coding: P=16%7=2, Y=25%7=4, T=20%7=6, H=8%7=1, O=15%7=1, N=14%7=0 → concatenated = 246110
modular, advanced

Question 6

If A=26, B=25, C=24... Z=1 (reverse order), then 'BOX' is coded as?
Reverse coding: B=25 + O=12 + X=3 → concatenated = 25123
reverse, sequence

Question 7

If A=1, B=1, C=2, D=3, E=5, F=8... (Fibonacci sequence), what is 'DOG' coded as?
Fibonacci coding: D=3, O=610, G=13 → concatenated = 361013
fibonacci, sequence, advanced

Question 8

For 'MNO', odd positions (1st,3rd,5th...) are coded as their position numbers, even positions are shifted by 1 letter forward. What is the code?
Odd/Even coding: Pos1:M→13, Pos2:N→N, Pos3:O→15 → 13N15
position, pattern, mixed

Question 9

For 'MNO', odd positions (1st,3rd,5th...) are coded as their position numbers, even positions are shifted by 1 letter forward. What is the code?
Odd/Even coding: Pos1:M→13, Pos2:N→N, Pos3:O→15 → 13N15
position, pattern, mixed

Question 10

If each letter is shifted forward by 2 positions (A→C), what is 'BED' coded as?
Shift coding: B→D(+2), E→G(+2), D→F(+2) → DGF
shift, caesar, cipher

Question 11

For 'ABC', find the differences between consecutive letter positions (A=1,B=2...). Format as comma-separated values.
Positions: [1, 2, 3] → Differences: [1, 1]
difference, sequence, pattern

Question 12

If each letter is coded as the square of its position (A=1→1, B=2→4, C=3→9...), what is 'EGG' coded as?
Square coding: E=5²=25, G=7²=49, G=7²=49 → concatenated = 254949
square, exponential, advanced

Question 13

If each letter is coded as the sum of digits of its position (A=1→1, B=2→2, ..., J=10→1+0=1...), what is 'EGG' coded as?
Digit sum coding: E=5→digit_sum=5, G=7→digit_sum=7, G=7→digit_sum=7 → concatenated = 577
digits, sum, pattern

Question 14

For 'VWX', odd positions (1st,3rd,5th...) are coded as their position numbers, even positions are shifted by 1 letter forward. What is the code?
Odd/Even coding: Pos1:V→22, Pos2:W→W, Pos3:X→24 → 22W24
position, pattern, mixed

Question 15

If A=26, B=25, C=24... Z=1 (reverse order), then 'ACE' is coded as?
Reverse coding: A=26 + C=24 + E=22 → concatenated = 262422
reverse, sequence

Question 16

For 'ACE', find the differences between consecutive letter positions (A=1,B=2...). Format as comma-separated values.
Positions: [1, 3, 5] → Differences: [2, 2]
difference, sequence, pattern

Question 17

If letters are coded as (position mod 7), 'PYTHON' becomes?
Modular coding: P=16%7=2, Y=25%7=4, T=20%7=6, H=8%7=1, O=15%7=1, N=14%7=0 → concatenated = 246110
modular, advanced

Question 18

If letters are coded as 5-bit binary (A=1=00001, B=2=00010...), 'BED' is coded as?
Binary coding: B=2=00010, E=5=00101, D=4=00100 → concatenated = 000100010100100
binary, advanced

Question 19

If a word's code is the product of its letter positions, what is 'CAT's code?
Product calculation: C=3 × A=1 × T=20 = 60
product, arithmetic

Question 20

If A=1, B=2, C=3... Z=26, then 'DOG' is coded as?
Letter to number: D=4 + O=15 + G=7 → concatenated = 4157
basic, sequence
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