Question 1
Original matrix:
A B C
D E F
G H I
After rotated-270 transformation, the matrix becomes:
Applying rotated-270 transformation yields:
C F I
B E H
A D G
C F I
B E H
A D G
Matrix Coding - Expert Level: center focus EXPERT
Comprehensive self assessment worksheet covering 20 expert-level matrix coding problems. Worksheet 28 of 30 emphasizes center focus. Master grid logic, matrix decoding, table patterns through detailed explanations. Difficulty: challenging problems and time-bound practice. Tailored for expert-level preparation.
What you'll learn in this worksheet:
- Complete coverage of grid logic topics
- In-depth practice of matrix decoding variations
- Master all self assessment question types
- Thorough understanding of table patterns
- Comprehensive center focus preparation
Your progress through Matrix Coding
Worksheet 28 of 30 (93% complete)
Question 2
In matrix:
1 4 7
2 5 8
3 6 9
Which row has the maximum sum?
Row sums: Row1=12, Row2=15, Row3=18. Maximum is Row 3 with sum 18
Question 3
In matrix:
1 2 3
4 5 6
7 8 9
What is the sum of middle column?
The sum of middle column: 2 + 5 + 8 = 15
Question 4
In the 4×4 matrix:
A B C D
E F G H
I J K L
M N O P
If we follow the last column path (Start at (1,4) and move down), what word do we get?
Following the last column path: (1,4)=D (2,4)=H (3,4)=L (4,4)=P → DHLP
Question 5
Find the missing element (?) in this matrix pattern:
2 4 6
4 8 12
6 12 ?
What should replace the '?'?
Pattern: multiplication table pattern
Step 1: First row: multiples of 2 (2×1, 2×2, 2×3)
Step 2: Second row: multiples of 4 (4×1, 4×2, 4×3)
Step 3: Third row: multiples of 6 (6×1, 6×2, 6×3)
Step 4: Missing cell is 6×3 = 18
Pattern: Matrix[i][j] = (row_value) × (j+1)
Answer: 18
Step 1: First row: multiples of 2 (2×1, 2×2, 2×3)
Step 2: Second row: multiples of 4 (4×1, 4×2, 4×3)
Step 3: Third row: multiples of 6 (6×1, 6×2, 6×3)
Step 4: Missing cell is 6×3 = 18
Pattern: Matrix[i][j] = (row_value) × (j+1)
Answer: 18
Question 6
If A=0001, B=0010, C=0011, D=0100, E=0101, F=0110, G=0111, H=1000, I=1001, J=1010, K=1011, L=1100 (binary sequence 1-12), then 'HEAD' in binary?
Binary coding: H=1000 + E=0101 + A=0001 + D=0100 = 1000010100010100
Question 7
In a 6×6 matrix (row0-5, col0-5) containing letters A-Z and digits 0-9 in row-major order, encode 'ENCODE' by giving row and column numbers concatenated.
Position mapping: E→(0,4) N→(2,1) C→(0,2) O→(2,2) D→(0,3) E→(0,4) → 042102220304
Question 8
In a 5×5 matrix:
Row1: A B C D E
Row2: F G H I J
Row3: K L M N O
Row4: P Q R S T
Row5: U V W X Y
'CODE' is coded as (row,col) combination. What is the code?
Matrix positions: C=(1,3) O=(3,5) D=(1,4) E=(1,5) → Combined code: 13351415
Question 9
In matrix:
2 9 4
7 5 3
6 1 8
Which column has the maximum sum?
Column sums: Col1=15, Col2=15, Col3=15. Maximum is Column 1 with sum 15
Question 10
Find the missing element (?) in this matrix pattern:
2 4 6
4 8 12
6 12 ?
What should replace the '?'?
Pattern: multiplication table pattern
Step 1: First row: multiples of 2 (2×1, 2×2, 2×3)
Step 2: Second row: multiples of 4 (4×1, 4×2, 4×3)
Step 3: Third row: multiples of 6 (6×1, 6×2, 6×3)
Step 4: Missing cell is 6×3 = 18
Pattern: Matrix[i][j] = (row_value) × (j+1)
Answer: 18
Step 1: First row: multiples of 2 (2×1, 2×2, 2×3)
Step 2: Second row: multiples of 4 (4×1, 4×2, 4×3)
Step 3: Third row: multiples of 6 (6×1, 6×2, 6×3)
Step 4: Missing cell is 6×3 = 18
Pattern: Matrix[i][j] = (row_value) × (j+1)
Answer: 18
Question 11
In matrix:
1 4 7
2 5 8
3 6 9
Which row has the minimum sum?
Row sums: Row1=12, Row2=15, Row3=18. Minimum is Row 1 with sum 12
Question 12
If A=0001, B=0010, C=0011, D=0100, E=0101, F=0110, G=0111, H=1000, I=1001, J=1010, K=1011, L=1100 (binary sequence 1-12), then 'BAD' in binary?
Binary coding: B=0010 + A=0001 + D=0100 = 001000010100
Question 13
In the 4×4 matrix:
A B C D
E F G H
I J K L
M N O P
If we follow the first column path (Start at (1,1) and move down), what word do we get?
Following the first column path: (1,1)=A (2,1)=E (3,1)=I (4,1)=M → AEIM
Question 14
In matrix:
1 2 3
4 5 6
7 8 9
What is the sum of anti-diagonal?
The sum of anti-diagonal: 3 + 5 + 7 = 15
Question 15
In pattern matrix:
* @ # $
@ # $ *
# $ * @
$ * @ #
Code 'ABCD' using A=col1, B=col2, C=col3, D=col4, row advances sequentially (row0, row1, row2, row3, then repeats)?
Coding process: A→* B→# C→* D→# = *#*#
Question 16
Find the missing element (?) in this matrix pattern:
2 4 6
4 8 12
6 12 ?
What should replace the '?'?
Pattern: multiplication table pattern
Step 1: First row: multiples of 2 (2×1, 2×2, 2×3)
Step 2: Second row: multiples of 4 (4×1, 4×2, 4×3)
Step 3: Third row: multiples of 6 (6×1, 6×2, 6×3)
Step 4: Missing cell is 6×3 = 18
Pattern: Matrix[i][j] = (row_value) × (j+1)
Answer: 18
Step 1: First row: multiples of 2 (2×1, 2×2, 2×3)
Step 2: Second row: multiples of 4 (4×1, 4×2, 4×3)
Step 3: Third row: multiples of 6 (6×1, 6×2, 6×3)
Step 4: Missing cell is 6×3 = 18
Pattern: Matrix[i][j] = (row_value) × (j+1)
Answer: 18
Question 17
Using this 5×5 cipher matrix:
★ ♠ ♣ ♥ ♦
♣ ♥ ♦ ★ ♠
♦ ★ ♠ ♣ ♥
♠ ♣ ♥ ♦ ★
♥ ♦ ★ ♠ ♣
Letters A-T map to cells in row-major order (A→★, B→♠, C→♣, D→♥, E→♦, etc.)
What is the encoded form of 'CODE'?
Encoding 'CODE': C→♣ O→♥ D→♥ E→♦ = ♣♥♥♦
Question 18
In matrix:
1 2 3
4 5 6
7 8 9
What is the sum of main diagonal?
The sum of main diagonal: 1 + 5 + 9 = 15
Question 19
Original matrix:
1 2 3
4 5 6
7 8 9
After rotated-180 transformation, the matrix becomes:
Applying rotated-180 transformation yields:
9 8 7
6 5 4
3 2 1
9 8 7
6 5 4
3 2 1
Question 20
In a 5×5 matrix:
Row1: A B C D E
Row2: F G H I J
Row3: K L M N O
Row4: P Q R S T
Row5: U V W X Y
'SMART' is coded as (row,col) combination. What is the code?
Matrix positions: S=(4,4) M=(3,3) A=(1,1) R=(4,3) T=(4,5) → Combined code: 4433114345
📈 Building expertise: Worksheet 28 of 30 in Matrix Coding.