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Distance Logic - Intermediate-Advanced Level: path length INTERMEDIATE-ADVANCED

Ready to master distance logic? This time-bound test features 20 intermediate-advanced-level challenges. Worksheet 22 of 30 sharpens your path length skills. Master distance calculation, shortest path, displacement problems through guided practice. Perfect for advanced developing test preparation.

📝 Worksheet 22 of 30 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate-advanced level

What you'll learn in this worksheet:
Your progress through Distance Logic
Worksheet 22 of 30 (73% complete)

Question 1

Two runners start from the same point on a circular track of length 735 m. Their speeds are 11 m/s and 8 m/s. If they run in the same direction, when will they meet again?
Step-by-step:
1. Relative speed (same direction) = |8 - 11| = 3 m/s
2. Time to meet = Track length / Relative speed = 735 / 3 = 245.0 seconds
circular, track, meeting, laps

Question 2

Two persons A and B start from the same point. A walks 18 m North, then 15 m West. B walks 6 m North, then 18 m East, then 6 m West. What is the distance between them?
Step-by-step:
1. A's final position: (-15, 18)
2. B's final position: (12, 6)
3. Distance = √[(-15-12)² + (18-6)²] = √[-27² + 12²] = 30 m
two-persons, relative, distance

Question 3

From point P, a person walks 9 m West, then 12 m South. What is the shortest distance from point P?
Step-by-step:
1. These movements form a right angle
2. Shortest distance = √(9² + 12²)
3. = √(81 + 144) = √225 = 15 m
pythagoras, right-angle, shortest-distance

Question 4

A train 174 m long is running at 83 km/h. How long will it take to cross a 233 m long platform?
Step-by-step:
1. Speed = 83 km/h = 23.1 m/s
2. Total distance = Train length + Platform length = 174 + 233 = 407 m
3. Time = Distance / Speed = 407 / 23.1 = 17.7 seconds
train, platform, pole, ssc

Question 5

A person walks 20 m East, then 15 m South, then 22 m North, then 8 m East. Find his displacement from the starting point.
Step-by-step:
1. Track net displacement:
- North-South: 7 m North
- East-West: 28 m East
2. Displacement = √(28² + 7²) = √833 = 29 m
3. Total distance walked = 65 m
multi-stage, displacement, complex

Question 6

A boat travels at 22 km/h in still water. The stream flows at 6 km/h. How long will it take to go 78 km upstream?
Step-by-step:
1. Upstream speed = Boat speed - Stream speed = 22 - 6 = 16 km/h
2. Time = Distance / Speed = 78 / 16 = 4.9 hours
boat, stream, upstream, downstream

Question 7

A person travels at 55 km/h for 2 hours and then at 59 km/h for 2 hours. What is the average speed?
Step-by-step:
1. For equal time intervals, Average Speed = (v1 + v2) / 2
2. = (55 + 59) / 2 = 57.0 km/h
average, speed, distance

Question 8

A person travels 5 m West, then 12 m South. Find the shortest distance from the starting point.
Step-by-step:
1. West and South are perpendicular directions
2. Shortest distance = √(5² + 12²) = √169 = 13 m
shortest-path, pythagoras

Question 9

A boat travels at 25 km/h in still water. Stream speed is 3 km/h. What is the difference between upstream and downstream time for 74 km?
Step-by-step:
1. Downstream speed = 28 km/h, Time = 2.6 hours
2. Upstream speed = 22 km/h, Time = 3.4 hours
3. Difference = 3.4 - 2.6 = 0.8 hours
boat, stream, upstream, downstream

Question 10

A person walks 24 m North, then 10 m East. What is the straight-line distance from the starting point?
Step-by-step:
1. These are perpendicular movements
2. Straight-line distance = √(24² + 10²) = √676 = 26 m
shortest-path, pythagoras

Question 11

A person walks 25 m South, then 13 m West, then 24 m North, then 14 m South. Find his displacement from the starting point.
Step-by-step:
1. Track net displacement:
- North-South: -15 m South
- East-West: -13 m West
2. Displacement = √(-13² + -15²) = √394 = 20 m
3. Total distance walked = 76 m
multi-stage, displacement, complex

Question 12

A person starts from point O and walks 20m South, then 20m South, then 25m South. What is his straight line distance from point O?
Step-by-step:
1. Track movements: 20m South, then 20m South, then 25m South
2. Net position: (0, -65)
3. Distance = √(0² + -65²) = √4225 = 65 m
basic, movement, straight-line

Question 13

A train moves at 78 km/h for 15 minutes. What distance does it cover?
Time = 15 minutes = 0.25 hours
Distance = 78 × 0.25 = 19.5 km
speed, time, basic

Question 14

A person travels 8 m West, then 6 m South. Find the shortest distance from the starting point.
Step-by-step:
1. West and South are perpendicular directions
2. Shortest distance = √(8² + 6²) = √100 = 10 m
shortest-path, pythagoras

Question 15

Two persons A and B start from the same point. A walks 5 m West, then 13 m West. B walks 18 m South, then 12 m North. What is the distance between them?
Step-by-step:
1. A's final position: (-18, 0)
2. B's final position: (0, -6)
3. Distance = √[(-18-0)² + (0--6)²] = √[-18² + 6²] = 19 m
two-persons, relative, distance

Question 16

A car travels at 73 km/h for 5 hours. What distance does it cover?
Distance = Speed × Time = 73 × 5 = 365 km
speed, time, basic

Question 17

A person travels at 56 km/h for 2 hours and then at 53 km/h for 2 hours. What is the average speed?
Step-by-step:
1. For equal time intervals, Average Speed = (v1 + v2) / 2
2. = (56 + 53) / 2 = 54.5 km/h
average, speed, distance

Question 18

A person walks 25 m North, then 20 m North, then 18 m West. Find his displacement from the starting point.
Step-by-step:
1. Track net displacement:
- North-South: 45 m North
- East-West: -18 m West
2. Displacement = √(-18² + 45²) = √2349 = 48 m
3. Total distance walked = 63 m
multi-stage, displacement, complex

Question 19

Car A at 49 km/h and Car B at 72 km/h start from the same point in the same direction. How long will it take for them to be 439 km apart?
Step-by-step:
1. Relative speed when moving in same direction = |72 - 49| = 23 km/h
2. Time = Distance / Relative Speed = 439 / 23 = 19.1 hours
3. The second car will be 439 km ahead after 19.1 hours
relative, meeting, catch-up

Question 20

A car travels at 39 km/h for 6 hours. What distance does it cover?
Distance = Speed × Time = 39 × 6 = 234 km
speed, time, basic
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