Sum of n terms in AP: Worksheet 2 - Beginner Practice Sum of n terms in AP BEGINNER

Ready to master Sum of n terms in AP? This entry level practice worksheet (2/10) presents 20 beginner-level challenges. Focus area: pattern recognition. Learn to solve sum of n terms in ap reasoning questions, handle sum of n terms in ap practice, and perfect sum of n terms in ap for competitive exams with our step-by-step solutions.

📝 Worksheet 2 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Beginner level

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Worksheet 2 of 10 (11% complete)

Question 1

Find the sum of first 7 terms of the AP: First term=12, common difference=4.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*12+(6)*4] = 168.0

Question 2

Find the sum of first 16 terms of the AP: First term=7, common difference=2.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*7+(15)*2] = 352.0

Question 3

Find the sum of first 18 terms of the AP: First term=2, common difference=7.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*2+(17)*7] = 1107.0

Question 4

Find the sum of first 18 terms of the AP: First term=3, common difference=8.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*3+(17)*8] = 1278.0

Question 5

Find the sum of first 12 terms of the AP: First term=5, common difference=3.
S_n = n/2 [2a + (n-1)d] = 12/2*[2*5+(11)*3] = 258.0

Question 6

Find the sum of first 11 terms of the AP: First term=5, common difference=5.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*5+(10)*5] = 330.0

Question 7

Find the sum of first 19 terms of the AP: First term=12, common difference=7.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*12+(18)*7] = 1425.0

Question 8

Find the sum of first 10 terms of the AP: First term=8, common difference=8.
S_n = n/2 [2a + (n-1)d] = 10/2*[2*8+(9)*8] = 440.0

Question 9

Find the sum of first 9 terms of the AP: First term=5, common difference=8.
S_n = n/2 [2a + (n-1)d] = 9/2*[2*5+(8)*8] = 333.0

Question 10

Find the sum of first 18 terms of the AP: First term=6, common difference=7.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*6+(17)*7] = 1179.0

Question 11

Find the sum of first 7 terms of the AP: First term=7, common difference=5.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*7+(6)*5] = 154.0

Question 12

Find the sum of first 13 terms of the AP: First term=10, common difference=6.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*10+(12)*6] = 598.0

Question 13

Find the sum of first 13 terms of the AP: First term=10, common difference=4.
S_n = n/2 [2a + (n-1)d] = 13/2*[2*10+(12)*4] = 442.0

Question 14

Find the sum of first 7 terms of the AP: First term=12, common difference=3.
S_n = n/2 [2a + (n-1)d] = 7/2*[2*12+(6)*3] = 147.0

Question 15

Find the sum of first 18 terms of the AP: First term=11, common difference=7.
S_n = n/2 [2a + (n-1)d] = 18/2*[2*11+(17)*7] = 1269.0

Question 16

Find the sum of first 19 terms of the AP: First term=7, common difference=7.
S_n = n/2 [2a + (n-1)d] = 19/2*[2*7+(18)*7] = 1330.0

Question 17

Find the sum of first 16 terms of the AP: First term=9, common difference=7.
S_n = n/2 [2a + (n-1)d] = 16/2*[2*9+(15)*7] = 984.0

Question 18

Find the sum of first 11 terms of the AP: First term=3, common difference=6.
S_n = n/2 [2a + (n-1)d] = 11/2*[2*3+(10)*6] = 363.0

Question 19

Find the sum of first 20 terms of the AP: First term=4, common difference=4.
S_n = n/2 [2a + (n-1)d] = 20/2*[2*4+(19)*4] = 840.0

Question 20

Find the sum of first 8 terms of the AP: First term=7, common difference=8.
S_n = n/2 [2a + (n-1)d] = 8/2*[2*7+(7)*8] = 280.0
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