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Olympiad Chain Arithmetic - Expert Level: conceptual clarity Olympiad Chain Arithmetic EXPERT

This skill evaluation ⚡ worksheet focuses on Olympiad Chain Arithmetic - a key topic in Arithmetic Problems. You'll solve 20 expert-level problems (Worksheet 9 of 10). The primary focus is on conceptual clarity. Master olympiad chain arithmetic ssc cgl, olympiad chain arithmetic reasoning tricks, and fast olympiad chain arithmetic solving through systematic practice.

📝 Worksheet 9 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Expert level

What you'll learn in this worksheet:
Your progress through Olympiad Chain Arithmetic
Worksheet 9 of 10 (88% complete)

Question 1

₹2659 and ₹2274 at 6% for 2 years. Ratio of simple interests = ?
SI1=319.08, SI2=272.88, Ratio = 1.17:1

Question 2

Find difference in CI for ₹2232 at 8% vs 11% for 2 years.
P=2232, R1=8%, R2=11%, T=2. CI difference = 146.64

Question 3

A car travels at 44 km/h for 5 hours. The distance covered equals the elder's age. The younger is 4 times younger. Find younger's age.
Distance = 44×5 = 220 km. Elder age = distance = 220. Younger = 220/4 = 55

Question 4

A takes 12 days, B takes 18 days. Total wages ₹11951. Find A's share.
A: 12 days, B: 18 days. Wage ratio 0.083:0.056. Total ₹11951, A's wage=7170.6

Question 5

Find (CI - SI) on ₹1650 at 9% for 2 years.
P=1650, R=9%, T=2y. CI=310.37, SI=297.00, Difference=13.37

Question 6

In a group, 29 members are aged 21, 36 members aged 52. Find average age.
29 people age 21, 36 people age 52. Average = 38.2

Question 7

In a GP, the 3th term is 45 (a=5, r=3). This amount is invested at 5% simple interest for 3 years. Find the interest earned.
GP: a=5, r=3, term 3 = 45. SI on ₹45 at 5% for 3 years = 6.75

Question 8

Work efficiency: A = 3 units/day, B = 2 units/day. Total work 70 units. Difference in days to complete = ?
A efficiency=3, B=2, Work=70. A time=23.333333333333332, B time=35.0, Difference=11.7

Question 9

Town population 12434, grows 5% annually for 3 years. Population increase invested at 6% SI for 2 years. Find interest.
Population 12434, growth 5% for 3y → increase 1960. SI at 6% for 2y = 235.2

Question 10

In a GP, the 5th term is 32 (a=2, r=2). This amount is invested at 4% simple interest for 2 years. Find the interest earned.
GP: a=2, r=2, term 5 = 32. SI on ₹32 at 4% for 2 years = 2.56

Question 11

MP ₹1436, discount 10%, profit 15%. Find cost price.
MP=1436, Discount=10%, SP=1292.40. Profit 15%, CP=1123.83

Question 12

Average age of 7 people is 40. If a 26-year-old leaves, find new average.
Total 7 people avg 40 → total=280. Remove age 26, new avg=42.333333333333336

Question 13

₹2287 and ₹4423 at 9% for 3 years. Ratio of simple interests = ?
SI1=617.49, SI2=1194.21, Ratio = 0.52:1

Question 14

₹1580 and ₹2546 at 9% for 3 years. Ratio of simple interests = ?
SI1=426.60, SI2=687.42, Ratio = 0.62:1

Question 15

Distance 205km. At 40km/h vs 73km/h, time saved = ?
Distance 205km. Time1=5.12h, Time2=2.81h, Saved=2.32h

Question 16

A and B share ₹1214 in ratio 5:4. If A's share increases by 20%, what is A's new share?
Ratio 5:4, total 1214, A's share = 674.44. After 20% increase = 809.33

Question 17

A and B share ₹1116 in ratio 2:6. If A's share increases by 20%, what is A's new share?
Ratio 2:6, total 1116, A's share = 279.00. After 20% increase = 334.8

Question 18

Town population 39010, grows 8% annually for 3 years. Population increase invested at 6% SI for 2 years. Find interest.
Population 39010, growth 8% for 3y → increase 10131. SI at 6% for 2y = 1215.72

Question 19

A car travels at 60 km/h for 2 hours. The distance covered equals the elder's age. The younger is 4 times younger. Find younger's age.
Distance = 60×2 = 120 km. Elder age = distance = 120. Younger = 120/4 = 30

Question 20

Sum of AP (a=6, d=8, n=4) + 4th term of GP (a=2, r=3) = ?
AP sum = 72, GP term = 54. Combined = 126.0
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