Olympiad Chain Arithmetic: Worksheet 6 - Intermediate-Advanced Practice Olympiad Chain Arithmetic INTERMEDIATE ADVANCED

Ready to master Olympiad Chain Arithmetic? This timed practice ⚡ worksheet (6/10) presents 20 intermediate-advanced-level challenges. Focus area: speed building. Learn to solve olympiad chain arithmetic tricks, handle olympiad chain arithmetic shortcut methods, and perfect olympiad chain arithmetic bank exam questions with our step-by-step solutions.

📝 Worksheet 6 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Intermediate Advanced level

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Worksheet 6 of 10 (55% complete)

Question 1

Town population 46133, grows 5% annually for 4 years. Population increase invested at 6% SI for 2 years. Find interest.
Population 46133, growth 5% for 4y → increase 9942. SI at 6% for 2y = 1193.04

Question 2

Investment returns in ratio 3:4, total ₹14586. If first investor gets 6251.14 at 20% ROI, find their investment.
Returns ratio 3:4, total ₹14586. Return1=6251.14 at 100% ROI, Investment=41674.29

Question 3

A and B share ₹3401 in ratio 5:3. If A's share increases by 10%, what is A's new share?
Ratio 5:3, total 3401, A's share = 2125.62. After 10% increase = 2338.19

Question 4

MP ₹1100, discount 15%, profit 15%. Find cost price.
MP=1100, Discount=15%, SP=935.00. Profit 15%, CP=813.04

Question 5

A car travels at 48 km/h for 3 hours. The distance covered equals the elder's age. The younger is 3 times younger. Find younger's age.
Distance = 48×3 = 144 km. Elder age = distance = 144. Younger = 144/3 = 48

Question 6

Sum of first 4 terms of AP (a=322, d=137) is invested at 9% compound interest for 3 years. Find compound interest.
AP sum: 2110. CI on ₹2110 at 9% for 3 years = 622.51

Question 7

In a GP, the 5th term is 1280 (a=5, r=4). This amount is invested at 8% simple interest for 3 years. Find the interest earned.
GP: a=5, r=4, term 5 = 1280. SI on ₹1280 at 8% for 3 years = 307.2

Question 8

Distance 127km. At 48km/h vs 85km/h, time saved = ?
Distance 127km. Time1=2.65h, Time2=1.49h, Saved=1.15h

Question 9

A and B share ₹4105 in ratio 5:2. If A's share increases by 10%, what is A's new share?
Ratio 5:2, total 4105, A's share = 2932.14. After 10% increase = 3225.36

Question 10

Find difference between CI and SI on ₹2885 at 5% for 2 years.
P=2885, R=5%, T=2. SI=288.50, CI=295.71, Difference=7.21

Question 11

MP ₹835, discount 20%, profit 15%. Find cost price.
MP=835, Discount=20%, SP=668.00. Profit 15%, CP=580.87

Question 12

Find difference between CI and SI on ₹3111 at 5% for 2 years.
P=3111, R=5%, T=2. SI=311.10, CI=318.88, Difference=7.78

Question 13

Work efficiency: A = 3 units/day, B = 1 units/day. Total work 84 units. Difference in days to complete = ?
A efficiency=3, B=1, Work=84. A time=28.0, B time=84.0, Difference=56.0

Question 14

MP ₹1205, discount 20%, profit 15%. Find cost price.
MP=1205, Discount=20%, SP=964.00. Profit 15%, CP=838.26

Question 15

Find difference between CI and SI on ₹2824 at 12% for 3 years.
P=2824, R=12%, T=3. SI=1016.64, CI=1143.52, Difference=126.88

Question 16

A completes work in 16 days, B in 17 days. They work together and earn ₹6979. Find A's share.
A: 16 days, B: 17 days. Work ratio = 0.062:0.059. Profit 6979, A's share = 3595.24

Question 17

Investment returns in ratio 2:3, total ₹27829. If first investor gets 11131.60 at 20% ROI, find their investment.
Returns ratio 2:3, total ₹27829. Return1=11131.60 at 100% ROI, Investment=55658.0

Question 18

Work efficiency: A = 4 units/day, B = 2 units/day. Total work 101 units. Difference in days to complete = ?
A efficiency=4, B=2, Work=101. A time=25.25, B time=50.5, Difference=25.2

Question 19

Find difference in CI for ₹2956 at 9% vs 13% for 2 years.
P=2956, R1=9%, R2=13%, T=2. CI difference = 262.49

Question 20

In AP (a=33, d=15, n=8), what % of total sum is the 4th term?
AP sum = 684, term4=78, percentage=11.4%
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