ReasoningAbility.com

Min/Max Age Constraints - Absolute-Beginner Level: core concept mastery Min/Max Age Constraints ABSOLUTE BEGINNER

This skill primer 🌟 worksheet focuses on Min/Max Age Constraints - a key topic in Age Problems. You'll solve 20 absolute-beginner-level problems (Worksheet 1 of 10). The primary focus is on core concept mastery. Master min/max age constraints problems, min/max age constraints reasoning questions, and min/max age constraints practice through systematic practice.

📝 Worksheet 1 of 10 • 20 questions • ⏱️ Estimated time: 20 minutes • 🎯 Absolute Beginner level

What you'll learn in this worksheet:
Your progress through Min/Max Age Constraints
Worksheet 1 of 10 (0% complete)

Question 1

A is older than B. C is younger than B. A + B + C = 79. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 79, max C = 20

Question 2

A and B's ages sum to 58. A is between 5 and 4 times as old as B. What is the minimum possible age of A?
A + B = 58, A/B between 5 and 4. For min A, take A/B = 5 → B = 9.7, A = 48.3 → min A = 49

Question 3

A is older than B. C is younger than B. A + B + C = 61. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 61, max C = 16

Question 4

Sum of A and B's ages is 69. After 7 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 69, (A+7) = 3*(B+7) → A = 55.2 → max A = 55

Question 5

A and B's ages sum to 53. A is between 2 and 5 times as old as B. What is the minimum possible age of A?
A + B = 53, A/B between 2 and 5. For min A, take A/B = 2 → B = 17.7, A = 35.3 → min A = 36

Question 6

A is older than B. C is younger than B. A + B + C = 60. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 60, max C = 15

Question 7

Sum of A and B's ages is 58. After 8 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 58, (A+8) = 3*(B+8) → A = 47.5 → max A = 47

Question 8

Sum of A and B's ages is 61. After 10 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 61, (A+10) = 2*(B+10) → A = 44.0 → max A = 44

Question 9

Sum of A and B's ages is 59. After 9 years, A will be 3 times as old as B. What is the maximum possible age of A now?
A + B = 59, (A+9) = 3*(B+9) → A = 48.8 → max A = 48

Question 10

A is older than B. C is younger than B. A + B + C = 69. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 69, max C = 20

Question 11

A and B's ages sum to 57. A is between 2 and 5 times as old as B. What is the minimum possible age of A?
A + B = 57, A/B between 2 and 5. For min A, take A/B = 2 → B = 19.0, A = 38.0 → min A = 38

Question 12

A is older than B. C is younger than B. A + B + C = 75. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 75, max C = 20

Question 13

A is older than B. C is younger than B. A + B + C = 75. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 75, max C = 20

Question 14

A and B's ages sum to 58. A is between 4 and 5 times as old as B. What is the minimum possible age of A?
A + B = 58, A/B between 4 and 5. For min A, take A/B = 4 → B = 11.6, A = 46.4 → min A = 47

Question 15

A and B's ages sum to 59. A is between 4 and 3 times as old as B. What is the minimum possible age of A?
A + B = 59, A/B between 4 and 3. For min A, take A/B = 4 → B = 11.8, A = 47.2 → min A = 48

Question 16

Sum of A and B's ages is 63. After 5 years, A will be 2 times as old as B. What is the maximum possible age of A now?
A + B = 63, (A+5) = 2*(B+5) → A = 43.7 → max A = 43

Question 17

A and B's ages sum to 42. A is between 4 and 5 times as old as B. What is the minimum possible age of A?
A + B = 42, A/B between 4 and 5. For min A, take A/B = 4 → B = 8.4, A = 33.6 → min A = 34

Question 18

A and B's ages sum to 43. A is between 5 and 4 times as old as B. What is the minimum possible age of A?
A + B = 43, A/B between 5 and 4. For min A, take A/B = 5 → B = 7.2, A = 35.8 → min A = 36

Question 19

A is older than B. C is younger than B. A + B + C = 73. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 73, max C = 22

Question 20

A is older than B. C is younger than B. A + B + C = 75. A is at least 5 years older than B. Maximum possible age of C?
For max C, minimize A and B. A ≥ B+5, B > C. With sum 75, max C = 22
Next Worksheet