Parallelograms

Parallelogram Counting problems involve counting the number of parallelograms formed by a set of intersecting lines (usually horizontal and vertical lines). The number of parallelograms = C(h,2) × C(v,2), where h is the number of horizontal lines and v is the number of vertical lines.

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Introduction to Parallelograms

Parallelogram Counting problems involve counting the number of parallelograms formed by a set of intersecting lines (usually horizontal and vertical lines). The number of parallelograms = C(h,2) × C(v,2), where h is the number of horizontal lines and v is the number of vertical lines.

Prerequisites

Combination formula: C(n,2) = n(n-1)/2 Understanding of parallelogram geometry Grid line concepts Multiplication principle
Why This Matters: Parallelogram problems appear in 1-2 questions in SSC CGL and Banking PO exams. They test combinatorial reasoning and understanding of parallelogram formation.

How to Solve Parallelograms Problems

1

Step 1: Count the number of horizontal lines (h) in the grid

2

Step 2: Count the number of vertical lines (v) in the grid

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Step 3: Choose 2 horizontal lines: C(h,2) = h(h-1)/2

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Step 4: Choose 2 vertical lines: C(v,2) = v(v-1)/2

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Step 5: Total parallelograms = C(h,2) × C(v,2)

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Step 6: This formula works because any two horizontal and two vertical lines form a parallelogram (actually a rectangle, which is a special parallelogram)

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Step 7: Answer with the total count

Pro Strategy: Use the formula: Parallelograms = C(h,2) × C(v,2). This counts all rectangles (special parallelograms) as well. For grids with non-perpendicular lines, the formula still works as long as lines are parallel to each other in two sets.

Example Problem

Example: Count parallelograms in a grid with 3 horizontal lines and 4 vertical lines. Solution: Step 1: h = 3 horizontal lines, v = 4 vertical lines Step 2: C(3,2) = 3×2/2 = 3 Step 3: C(4,2) = 4×3/2 = 6 Step 4: Total parallelograms = 3 × 6 = 18 Answer: 18 parallelograms

Pro Tips & Tricks

  • Formula: Parallelograms = h(h-1)/2 × v(v-1)/2
  • For a grid of horizontal and vertical lines, every choice of 2 horizontal and 2 vertical lines forms a parallelogram (actually a rectangle)
  • If lines are not perpendicular but still parallel in two sets, the same formula applies
  • For a square grid of points (m×n points), parallelograms = C(m,2) × C(n,2)
  • This formula counts ALL parallelograms whose sides are along the grid lines
  • Parallelograms that are not aligned with grid lines are not counted by this formula

Shortcut Methods to Solve Faster

Parallelograms = C(h,2) × C(v,2) = [h(h-1)/2] × [v(v-1)/2]
For 3×3 grid lines: C(3,2)×C(3,2) = 3×3 = 9
For 3×4 grid lines: C(3,2)×C(4,2) = 3×6 = 18
For 4×4 grid lines: C(4,2)×C(4,2) = 6×6 = 36

Common Mistakes to Avoid

Counting only rectangles instead of all parallelograms (in perpendicular grids, rectangles are parallelograms, so it's fine)
Using number of points instead of number of lines
Forgetting to divide by 2 in the combination formula
Using m×n instead of the combination formula

Exam Importance

Parallelograms is an important topic for various competitive exams. Here's how frequently it appears:

SSC CGL
1-2 questions
BANKING PO
1-2 questions
RAILWAYS RRB
1-2 questions
CAT
1-2 questions
INSURANCE
1-2 questions

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20 practice questions
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