Seating Arrangement - Expert Level: parallel rows EXPERT

Solution Approach:

Step 1: Mark directions
↑ = North facing, ↓ = South facing

Step 2: Apply position-based conditions
- P sits third from the left end facing North (↑) → Position 3
- U sits at the left extreme end facing South (↓) → Position 1

Position: U(↓) _ P(↑) _ _ _

Step 3: Apply relative positioning
- Q sits second to the right of P (pos 3) → Position 5
- Q faces opposite direction to P (North) → Q faces South (↓)
- T sits immediately to the left of Q (pos 5) facing North (↑) → Position 4

Position: U(↓) _ P(↑) T(↑) Q(↓) _

Step 4: Fill remaining positions
Remaining persons: R, S
Position 2 gets R, Position 6 gets S

Final Arrangement:
Pos: U(↓) R(↑) P(↑) T(↑) Q(↓) S(↑)

Verification:
✓ P at pos 3, facing North
✓ Q at pos 5 (second right of P), facing South (opposite of P)
✓ U at pos 1 (left extreme), facing South
✓ T at pos 4 (immediately left of Q), facing North

Person between U (pos 1) and P (pos 3): pos 2 = R

Answer: R sits between U and P.

Solution Approach:

Step 1: Understanding facing outward
When facing outward (away from center):
- LEFT = CLOCKWISE direction
- RIGHT = ANTI-CLOCKWISE direction
- Opposite positions are still n/2 = 3 seats apart.

Step 2: Draw diagram (positions 1–6 clockwise)

Step 3: Apply conditions
- Fix P at position 1.
- O sits second to the LEFT of P: left(outward)=CW, so O is 2 CW from P.
pos[O] = 3
- M sits opposite O (pos 3): pos 6
- K sits immediately to the RIGHT of M (pos 6):
right(outward)=anti-CW → pos 5
- N sits opposite P (pos 1): pos 4
- Remaining L fills pos 2.

Final Arrangement (clockwise):
pos1:P → pos2:L → pos3:O → pos4:N → pos5:K → pos6:M
(All facing outward ↗)

Find immediate left of O (pos 3):
Left (outward) = clockwise → pos 4 = N

Verification:
✓ O second to left of P (CW direction)
✓ M opposite O
✓ K immediately right (anti-CW) of M
✓ N opposite P

Answer: N sits immediately to the left of O.

Solution Approach:

Step 1: Understanding facing outward
When facing outward (away from center):
- LEFT = CLOCKWISE direction
- RIGHT = ANTI-CLOCKWISE direction
- Opposite positions are still n/2 = 3 seats apart.

Step 2: Draw diagram (positions 1–6 clockwise)

Step 3: Apply conditions
- Fix P at position 1.
- N sits second to the LEFT of P: left(outward)=CW, so N is 2 CW from P.
pos[N] = 3
- O sits opposite N (pos 3): pos 6
- M sits immediately to the RIGHT of O (pos 6):
right(outward)=anti-CW → pos 5
- K sits opposite P (pos 1): pos 4
- Remaining L fills pos 2.

Final Arrangement (clockwise):
pos1:P → pos2:L → pos3:N → pos4:K → pos5:M → pos6:O
(All facing outward ↗)

Find immediate left of N (pos 3):
Left (outward) = clockwise → pos 4 = K

Verification:
✓ N second to left of P (CW direction)
✓ O opposite N
✓ M immediately right (anti-CW) of O
✓ K opposite P

Answer: K sits immediately to the left of N.

Solution Approach:

Step 1: Draw circular diagram
6 persons facing center. Opposite positions are 3 seats apart.
Number positions 1–6 clockwise.

Step 2: Place definite positions
- Fix C at position 1 (reference point)
- C is second to the LEFT of F → F is 2 clockwise from C
pos[F] = 3
- D sits OPPOSITE C (pos 1) → pos 4
- B sits immediately to the right of D (pos 4) → pos 5

Step 3: Resolve remaining positions
Remaining persons: E, A → remaining seats: [2, 6]
E is NOT adjacent to B (pos 5).
Adjacent to pos 5: pos 4 and pos 6.
Therefore E → pos 2, and A → pos 6.

Final Arrangement (clockwise):
pos1:C → pos2:E → pos3:F → pos4:D → pos5:B → pos6:A
(All facing center)

Opposite pairs: pos1↔pos4, pos2↔pos5, pos3↔pos6

F is at pos 3 → opposite = pos 6 = A

Answer: A sits opposite to F.

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- F at seat 3
- E at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(F) 4(_) 5(_) 6(_) 7(_) 8(E) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- B sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = B ✓

Seat: 1(_) 2(B) 3(F) 4(_) 5(_) 6(_) 7(_) 8(E) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- C sits fourth to the LEFT of E (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- C at seat 4 ✓

Seat: 1(_) 2(B) 3(F) 4(C) 5(_) 6(_) 7(_) 8(E) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: D, G, A, H → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing D(5), G(6), A(7), H(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(B) 3(F) 4(C) 5(D) 6(G) 7(A) 8(E) 9(_) 10(H)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: B, F, C, D, G, A, E = 7 persons

Verification:
✓ F at seat 3
✓ E at seat 8
✓ Empty at seat 1 (extreme end)
✓ B immediately right of empty seat 1
✓ C fourth to left of E (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Understanding facing South
When persons face South:
- Their right hand points West (viewer's LEFT) — "right" in the question = lower position number
- Viewer's "right" (higher position) = person's left side

Step 2: Set up diagram (viewer's perspective)
Position: 1(left) 2 3 4 5(right)

Step 3: Apply conditions
- S at the right extreme end → Position 5
- T sits second to the right of R:
South-facing right = viewer's left = lower position: pos[T] = pos[R] - 2
Possible: R=3→T=1, or R=4→T=2
- Q sits immediately to the right of R (viewer's right = higher pos): pos[Q] = pos[R] + 1
If R=3 → Q=4 ✓ (pos 4 free)
If R=4 → Q=5 = S ✗ (conflict)
∴ R=3, T=1, Q=4

Position: T _ R Q S

Step 4: Apply constraint
- P not adjacent to S (pos 5): P ≠ pos 4 (taken by Q) → P at pos 2 ✓

Final Arrangement (all facing South ↓):
Position: T P R Q S

Verification:
✓ S at right extreme end (pos 5)
✓ T second to right of R: pos[T](=1)-2 = 3 = pos[R] (south-facing right=lower)
✓ Q immediately right of R (viewer right): pos 3+1 = 4
✓ P not adjacent to S (pos 2, not pos 4)

Answer: T sits at the left extreme end (position 1).

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- A sits at one extreme end → Place A at position 1
- E sits second to the right of A → E at position 3
- B sits immediately to the left of E → B at position 2

Position: A B E _ _

Step 3: Apply constraint conditions
- C is not at any extreme end → remaining positions are 4 and 5; C cannot be at 5, so C at position 4
- Only D remains → D at position 5

Final Arrangement (all facing North ↑):
Position: A B E C D

Verification:
✓ A at extreme end (pos 1)
✓ E second to the right of A (pos 3)
✓ B immediately to the left of E (pos 2)
✓ C not at extreme end (pos 4)

Answer: D sits at the other extreme end (position 5).

Solution Approach:

Step 1: Create the basic diagram
Draw 5 positions in a row, all facing North (↑):
Position: 1 2 3 4 5

Step 2: Apply direct conditions
- B sits at one extreme end → Place B at position 1
- D sits second to the right of B → D at position 3
- A sits immediately to the left of D → A at position 2

Position: B A D _ _

Step 3: Apply constraint conditions
- E is not at any extreme end → remaining positions are 4 and 5; E cannot be at 5, so E at position 4
- Only C remains → C at position 5

Final Arrangement (all facing North ↑):
Position: B A D E C

Verification:
✓ B at extreme end (pos 1)
✓ D second to the right of B (pos 3)
✓ A immediately to the left of D (pos 2)
✓ E not at extreme end (pos 4)

Answer: C sits at the other extreme end (position 5).

Solution Approach:

Step 1: Draw the double row setup
Row 1 faces South (↓), Row 2 faces North (↑)
Person at position i in Row 1 faces person at position i in Row 2.

Position: 1 2 3 4 5
Row 1 (↓): _ _ _ _ _
Row 2 (↑): _ _ _ _ _

Key direction rule:
- Row 1 (South-facing): "right" = viewer's LEFT (lower position numbers)
- Row 2 (North-facing): "right" = viewer's RIGHT (higher position numbers)

Step 2: Place Row 1 persons
- C sits 4th from the left end of Row 1 → Row 1, pos 4
- E sits at an extreme end: pos 1 or pos 5
- D sits second to the RIGHT of E (south-facing → lower position):
pos[D] = pos[E] - 2
If E at pos 1 → pos[D] = -1 (invalid ✗)
If E at pos 5 → pos[D] = 3 ✓ (pos 3 is free)
∴ E at pos 5, D at pos 3 ✓

Row 1: _ _ D C E
Remaining B,A at pos 1 and 2 (either order — pinned next).

Step 3: Place Row 2 persons
- P faces C (pos 4) → P at Row 2, pos 4
- T sits second to the LEFT of P (north-facing → lower position):
pos[T] = pos[P] - 2 = 2 → T at Row 2 pos 2 ✓
- R sits at extreme end of Row 2: pos 1 or pos 5
- Q is NOT adjacent to P (pos 4): adjacent = pos 3 and pos 5
So Q ≠ pos 3 and Q ≠ pos 5
Remaining positions for R,S,Q: pos 1, pos 3, pos 5
Q not at pos 3 or pos 5 → Q at pos 1
R at extreme → pos 5 (since pos 1 is Q) ✓
S fills pos 3 ✓

Row 2: Q T S P R

Final Arrangement:
Position: 1 2 3 4 5
Row 1 (↓): B/A B/A D C E
Row 2 (↑): Q T S P R

Find who faces D:
D is at Row 1, position 3.
Person at Row 2, position 3 = S

Answer: S faces D.

Solution Approach:

Step 1: Apply the fixed condition
- W sits second from the left → W at position 2 (fixed)

Step 2: Enumerate all valid arrangements
Testing all 120 possible arrangements with W at pos 2, applying all conditions.
7 valid arrangement(s) found.

Valid arrangement(s):
• Z W X V Y
• Z W X Y V
• X W Y V Z
• V W Z X Y
• Y W Z X V
• Y W X Z V
(shown up to 6)

Step 3: Test each MCQ option

- "Y sits at position 4": ✓ Possible in at least one valid arrangement
- "Z sits at position 2": ✗ NEVER possible → must be FALSE
- "Z sits at position 4": ✓ Possible in at least one valid arrangement
- "V sits at position 5": ✓ Possible in at least one valid arrangement

Step 4: Conclusion
"Z sits at position 2" is impossible in ALL 7 valid arrangement(s) — it must be FALSE.
All other options occur in at least one valid arrangement.

Answer: "Z sits at position 2" must be FALSE.

Solution Approach:

Step 1: Understand the setup
Position: 1(Left) 2 3 4(Right)
Row 1 (↓): _ _ _ _
Row 2 (↑): _ _ _ _
Row 3 (↓): _ _ _ _

Facing: Row 1 pos i faces Row 2 pos i; Row 2 pos i faces Row 3 pos i.
(Using viewer's perspective: left=position 1, right=position 4)

Step 2: Apply facing relationships
- D faces R who faces W: all three in the SAME vertical column.
Place at position 2:
Row1: _ D _ _
Row2: _ R _ _
Row3: _ W _ _

Step 3: Apply left-right conditions
- B sits to the left of D(pos 2) in Row 1 → B at position 1
Row1: B D _ _

Step 4: Second facing relationship
- P faces B(Row1 pos1) → P at Row2 position 1
- P faces X → X at Row3 position 1
Row1: B D _ _
Row2: P R _ _
Row3: X W _ _

Step 5: Apply relative positioning in Row 2
- S sits second to the right of P(pos1): 1+2=3 → S at Row2 position 3
Row2: P R S _
S faces Row1 pos3 → A at Row1 pos3 ✓
S faces Row3 pos3 → Z at Row3 pos3 ✓

Step 6: Fill remaining positions
Remaining: Row1 pos4=C, Row2 pos4=Q, Row3 pos4=Y

Final Arrangement:
Position: 1 2 3 4
Row 1 (↓): B D A C
Row 2 (↑): P R S Q
Row 3 (↓): X W Z Y

Right extreme of Row 3 = position 4 = Y

Answer: Y

Solution Approach:

Step 1: Understanding facing South
When persons face South:
- Their right hand points West (viewer's LEFT) — "right" in the question = lower position number
- Viewer's "right" (higher position) = person's left side

Step 2: Set up diagram (viewer's perspective)
Position: 1(left) 2 3 4 5(right)

Step 3: Apply conditions
- T at the right extreme end → Position 5
- R sits second to the right of Q:
South-facing right = viewer's left = lower position: pos[R] = pos[Q] - 2
Possible: Q=3→R=1, or Q=4→R=2
- P sits immediately to the right of Q (viewer's right = higher pos): pos[P] = pos[Q] + 1
If Q=3 → P=4 ✓ (pos 4 free)
If Q=4 → P=5 = T ✗ (conflict)
∴ Q=3, R=1, P=4

Position: R _ Q P T

Step 4: Apply constraint
- S not adjacent to T (pos 5): S ≠ pos 4 (taken by P) → S at pos 2 ✓

Final Arrangement (all facing South ↓):
Position: R S Q P T

Verification:
✓ T at right extreme end (pos 5)
✓ R second to right of Q: pos[R](=1)-2 = 3 = pos[Q] (south-facing right=lower)
✓ P immediately right of Q (viewer right): pos 3+1 = 4
✓ S not adjacent to T (pos 2, not pos 4)

Answer: R sits at the left extreme end (position 1).

Solution Approach:

Step 1: Apply the fixed condition
- V sits second from the left → V at position 2 (fixed)

Step 2: Enumerate all valid arrangements
Testing all 120 possible arrangements with V at pos 2, applying all conditions.
7 valid arrangement(s) found.

Valid arrangement(s):
• Z V W X Y
• Z V W Y X
• W V Y X Z
• X V Z W Y
• Y V Z W X
• Y V W Z X
(shown up to 6)

Step 3: Test each MCQ option

- "X sits at position 4": ✓ Possible in at least one valid arrangement
- "Y sits at position 4": ✓ Possible in at least one valid arrangement
- "X sits at position 5": ✓ Possible in at least one valid arrangement
- "Z sits at position 2": ✗ NEVER possible → must be FALSE

Step 4: Conclusion
"Z sits at position 2" is impossible in ALL 7 valid arrangement(s) — it must be FALSE.
All other options occur in at least one valid arrangement.

Answer: "Z sits at position 2" must be FALSE.

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- A sits immediately to the right of B (inner circle, facing center: right=CW)
→ B and A are adjacent. Possible: B=I1, A=I2 or B=I2, A=I3, etc.
- C sits opposite to A:
If A=I2, then C=I4. Then B=I1 (left of I2), D=I3 (remaining).
All constraints consistent ✓.

Inner: I1=B, I2=A, I3=D, I4=C

Step 4: Place outer circle persons
- Q faces B(I1) → Q at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- R second to right of P (outer, facing center: right=CW, step 2):
Remaining outer persons: R,P,S at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ P=O2, R=O4, S=O5 ✓
- S(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(R) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
A is at I2. Opposite of I2 = I4 = C.

Final Arrangements:
Inner (CW): I1=B, I2=A, I3=D, I4=C
Outer (CW): O1=Q, O2=P, O3=empty, O4=R, O5=S, O6=empty

Verification:
✓ Q faces B (I1↔O1)
✓ A immediately right of B (I2 is CW from I1)
✓ C opposite A (I4 opposite I2)
✓ R second right of P (O4 = O2 + 2 CW)
✓ S(O5) immediately left of empty O6

Answer: C sits opposite to A.

Solution Approach:

Step 1: Draw concentric circles
Inner circle: 4 positions I1(12 o'clock), I2(3), I3(6), I4(9) — all occupied.
Outer circle: 6 positions O1–O6 clockwise — 4 occupied, 2 empty.
Facing alignment: I1↔O1, I2↔O2, I3↔O4, I4↔O5 (O3 and O6 are empty).

Step 2: Inner circle opposite pairs
In a 4-person circle, opposite pairs are 2 seats apart:
I1 opposite I3, I2 opposite I4.

Step 3: Place inner circle persons
- D sits immediately to the right of A (inner circle, facing center: right=CW)
→ A and D are adjacent. Possible: A=I1, D=I2 or A=I2, D=I3, etc.
- C sits opposite to D:
If D=I2, then C=I4. Then A=I1 (left of I2), B=I3 (remaining).
All constraints consistent ✓.

Inner: I1=A, I2=D, I3=B, I4=C

Step 4: Place outer circle persons
- R faces A(I1) → R at O1 ✓
- Outer occupied seats: O1, O2, O4, O5. Empty: O3, O6.
- S second to right of Q (outer, facing center: right=CW, step 2):
Remaining outer persons: S,Q,P at O2, O4, O5.
R=O2 → Q=O4, S=O5 ✓
R=O4 → Q=O6(empty) ✗
R=O5 → Q=O1=P ✗
∴ Q=O2, S=O4, P=O5 ✓
- P(O5) immediately to the LEFT of an empty:
Left(CW) of O5 = O4(S) — NOT empty.
RIGHT(CW) of O5 = O6(empty). So O5 is immediately to the LEFT of O6(empty) ✓.

Step 5: Answer the question
D is at I2. Opposite of I2 = I4 = C.

Final Arrangements:
Inner (CW): I1=A, I2=D, I3=B, I4=C
Outer (CW): O1=R, O2=Q, O3=empty, O4=S, O5=P, O6=empty

Verification:
✓ R faces A (I1↔O1)
✓ D immediately right of A (I2 is CW from I1)
✓ C opposite D (I4 opposite I2)
✓ S second right of Q (O4 = O2 + 2 CW)
✓ P(O5) immediately left of empty O6

Answer: C sits opposite to D.

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Bhanu at H1 (pos 1).
- Bhanu opposite Charu: opp(pos1) = pos4 → Charu at H4

Step 3: Apply relative positioning
- Deepak second to the right of Bhanu(pos1):
CW 2: pos1→pos2→pos3
→ Deepak at H3

- Esha second to the right of Aman:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Bhanu=1, Charu=4, Deepak=3,
remaining seats: [2, 5, 6].
Esha = 2 CW from Aman: pos5 is 2 clockwise [solver-verified].
→ Aman at pos6, Esha at pos2

Step 4: Apply constraint
- Farhan not adjacent to Bhanu(pos1):
Adjacent to pos1: pos6 and pos2
→ Farhan at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Bhanu → H2:Esha → H3:Deepak → H4:Charu → H5:Farhan → H6:Aman

Step 5: Find Farhan's position relative to Deepak
Deepak at pos3, Farhan at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Bhanu opposite Charu
✓ Deepak second to right of Bhanu
✓ Esha second to right of Aman
✓ Farhan not adjacent to Bhanu

Answer: Farhan sits to the second to the right of Deepak.

Solution Approach:

Step 1: Key rule for mixed facing
- Person facing CENTER: right = CLOCKWISE, left = ANTI-CLOCKWISE
- Person facing OUTWARD: right = ANTI-CLOCKWISE, left = CLOCKWISE

Step 2: Draw 8-seat circle (positions 1–8 clockwise)

Step 3: Start with definite information
- Fix P (faces center) at position 1 (reference point)
- N faces outward, sits third to the RIGHT of P:
P faces center → right = clockwise
3 CW from pos 1 → pos 4
N = pos 4 ✓

Step 4: Apply relative positions
- R sits second to the LEFT of P (pos 1):
P faces center → left = anti-clockwise
2 anti-CW from pos 1 → pos 7
R faces same as N → OUTWARD
- T faces center, sits immediately to the RIGHT of R (pos 7):
R faces outward → right = anti-clockwise
1 anti-CW from pos 7 → pos 6

Step 5: Fill remaining persons
- S immediately to the RIGHT of P(pos 1, center→CW): pos 2
- M opposite P(pos 1): pos 5
- O not adjacent to N(pos 4): adj = pos 3 & 5
→ O at pos 8, Q at pos 3

Final Arrangement (clockwise):
pos1:P(ctr) | pos2:S(out) | pos3:Q(ctr) | pos4:N(out) | pos5:M(out) | pos6:T(ctr) | pos7:R(out) | pos8:O(ctr)

Find second to the right of T (pos 6, center-facing → CW):
2 CW from pos 6: → pos 8 = O

Verification:
✓ N(outward) 3 left of P(center): 3 ACW from pos1 = pos4
✓ R 2nd left of P, same direction as N (outward)
✓ T(center) immediately right of R(outward, right=ACW)
✓ S immediately right (CW) of P
✓ M opposite P
✓ O not adjacent to N

Answer: O sits second to the right of T.

Solution Approach:

Step 1: Mark total positions
Seats: 1 2 3 4 5 6 7 8 9 10
Total: 10 seats, 8 persons, 2 empty.

Step 2: Place definite positions
- G at seat 3
- C at seat 8 (seat 8)
- One empty seat at extreme end → seat 1 is empty

Seat: 1(_) 2(_) 3(G) 4(_) 5(_) 6(_) 7(_) 8(C) 9(_) 10(_)

Step 3: Apply empty seat adjacency
- A sits immediately to the RIGHT of an empty seat
- Empty at seat 1 → seat 2 = A ✓

Seat: 1(_) 2(A) 3(G) 4(_) 5(_) 6(_) 7(_) 8(C) 9(_) 10(_)

Step 4: Apply "fourth to the left" condition
- D sits fourth to the LEFT of C (seat 8)
- Fourth to left: 8 → 7 → 6 → 5 → 4
- D at seat 4 ✓

Seat: 1(_) 2(A) 3(G) 4(D) 5(_) 6(_) 7(_) 8(C) 9(_) 10(_)

Step 5: Locate second empty seat
Remaining persons: B, H, F, E → fill seats 5, 6, 7, 9, 10 minus one empty.
After placing B(5), H(6), F(7), E(10): seat 9 is empty.

Step 6: Final arrangement
Seat: 1(_) 2(A) 3(G) 4(D) 5(B) 6(H) 7(F) 8(C) 9(_) 10(E)

Count persons between empty seats (seat 1 and seat 9):
Seats 2 through 8: A, G, D, B, H, F, C = 7 persons

Verification:
✓ G at seat 3
✓ C at seat 8
✓ Empty at seat 1 (extreme end)
✓ A immediately right of empty seat 1
✓ D fourth to left of C (seat 4 = seat 8 - 4)

Answer: 7 persons sit between the two empty seats.

Solution Approach:

Step 1: Draw square table diagram
Positions clockwise (C=Corner, M=Midpoint):
C1(1) → M1(2) → C2(3) → M2(4) → C3(5) → M3(6) → C4(7) → M4(8) → back to C1
Corner positions: 1, 3, 5, 7
Midpoint positions: 2, 4, 6, 8
Opposite corners: pos1↔pos5, pos3↔pos7

Step 2: Place persons systematically
- D sits at a corner → pos 1
- C sits second to the RIGHT of D: right(center-facing)=CW
2 CW from pos 1 → pos 3 ✓ (corner)
- A sits OPPOSITE D (pos 1) → pos 5 ✓
- G at midpoint, NOT adjacent to D(pos 1):
Adjacent to pos 1: pos 8 and pos 2
G → pos 6 (midpoint, not adjacent) ✓
- B sits at corner immediately to the RIGHT of G(pos 6):
1 CW from pos 6 → pos 7 (corner) ✓

Step 3: Remaining persons
Remaining: H, F, E
Fill remaining seats: pos2=H, pos8=F, pos4=E

Final Arrangement (clockwise):
pos1:D → pos2:H → pos3:C → pos4:E → pos5:A → pos6:G → pos7:B → pos8:F

Step 4: Count from LEFT of D to A
Left = anti-clockwise direction from D(pos 1):
pos1(D) → pos8(F) → pos7(B) → pos6(G) → pos5(A)
Persons between (excluding D and A): pos8(F), pos7(B), pos6(G)
Count = 3 person(s)

Answer: Three person(s) sit between D and A.

Solution Approach:

Step 1: Draw hexagonal arrangement
6 corners H1–H6 clockwise.
Opposite pairs: H1↔H4, H2↔H5, H3↔H6.

Step 2: Place definite positions
- Fix Bhanu at H1 (pos 1).
- Bhanu opposite Farhan: opp(pos1) = pos4 → Farhan at H4

Step 3: Apply relative positioning
- Aman second to the right of Bhanu(pos1):
CW 2: pos1→pos2→pos3
→ Aman at H3

- Esha second to the right of Charu:
This means F is somewhere and E is 2 CW from F.
We need to find where F and E land.
After placing Bhanu=1, Farhan=4, Aman=3,
remaining seats: [2, 5, 6].
Esha = 2 CW from Charu: pos5 is 2 clockwise [solver-verified].
→ Charu at pos6, Esha at pos2

Step 4: Apply constraint
- Deepak not adjacent to Bhanu(pos1):
Adjacent to pos1: pos6 and pos2
→ Deepak at pos5 (not adjacent) ✓

Final Arrangement (clockwise):
H1:Bhanu → H2:Esha → H3:Aman → H4:Farhan → H5:Deepak → H6:Charu

Step 5: Find Deepak's position relative to Aman
Aman at pos3, Deepak at pos5.
pos5 is 2 clockwise from pos3.

Verification:
✓ Bhanu opposite Farhan
✓ Aman second to right of Bhanu
✓ Esha second to right of Charu
✓ Deepak not adjacent to Bhanu

Answer: Deepak sits to the second to the right of Aman.